Re: converting a string into a set
(set abc) will do it...
On Tue, Jul 19, 2011 at 9:20 AM, Tuba Lambanog tuba.lamba...@gmail.comwrote:
Hello,
My apologies for this newbie question. I couldn't find a way to
convert a string to a set, thus:
abc = #{a b c}
Thanks.
tuba
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Re: converting a string into a set
Hi,
(set abc)
gives me #{\a \b \c}.
I'm expecting instead: #{a b c}
But thanks,
Tuba
On Mon, Jul 18, 2011 at 9:50 PM, Tuba Lambanog tuba.lamba...@gmail.comwrote:
Hello,
My apologies for this newbie question. I couldn't find a way to
convert a string to a set, thus:
abc = #{a b c}
Thanks.
tuba
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Re: converting a string into a set
On Mon, Jul 18, 2011 at 9:17 PM, Tuba Lambanog tuba.lamba...@gmail.com wrote:
(set abc)
gives me #{\a \b \c}.
I'm expecting instead: #{a b c}
(set (map abc))
(set (map str Tuba Lambanog))
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Re: converting a string into a set
Tuba Lambanog wrote:
Tuba Lambanog wrote:
Hello, My apologies for this newbie question. I couldn't find a way to
convert a string to a set, thus:
abc = #{a b c}
(set abc) gives me #{\a \b \c}. I'm expecting instead: #{a b c}
Hi Tuba,
Are you quite sure that #{\a \b \c} is not what you want? In Clojure's
notation, a backslashed character [more or less] refers to a
single-character string--something akin to the char type from C. Hence \a is
the character a. On the other hand #{a b c} is a set containing three
Clojure symbols, which is probably not what you want.
(If you want to be using a, b, and c as some kind of identifiers, take a
look at keywords.)
--
Benjamin D. Esham | bdes...@gmail.com | www.bdesham.info
How to Ask Questions the Smart Way, by Eric S. Raymond:
http://catb.org/~esr/faqs/smart-questions.html
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Re: converting a string into a set
On 19/07/2011, at 2:29 PM, Sean Corfield wrote:
On Mon, Jul 18, 2011 at 9:17 PM, Tuba Lambanog tuba.lamba...@gmail.com
wrote:
(set abc)
gives me #{\a \b \c}.
I'm expecting instead: #{a b c}
(set (map abc))
(set (map str Tuba Lambanog))
This will produce #{a b c}
I think
(set (map #(symbol (str %)) abc))
should do the trick
--
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An Architect's View -- http://corfield.org/
World Singles, LLC. -- http://worldsingles.com/
Railo Technologies, Inc. -- http://www.getrailo.com/
Perfection is the enemy of the good.
-- Gustave Flaubert, French realist novelist (1821-1880)
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]
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Re: converting a string into a set
I'm with Benjamin despite my last post...
On 19/07/2011, at 2:31 PM, Benjamin Esham wrote:
Tuba Lambanog wrote:
Tuba Lambanog wrote:
Hello, My apologies for this newbie question. I couldn't find a way to
convert a string to a set, thus:
abc = #{a b c}
(set abc) gives me #{\a \b \c}. I'm expecting instead: #{a b c}
Hi Tuba,
Are you quite sure that #{\a \b \c} is not what you want? In Clojure's
notation, a backslashed character [more or less] refers to a
single-character string--something akin to the char type from C. Hence \a is
the character a. On the other hand #{a b c} is a set containing three
Clojure symbols, which is probably not what you want.
(If you want to be using a, b, and c as some kind of identifiers, take a
look at keywords.)
--
Benjamin D. Esham | bdes...@gmail.com | www.bdesham.info
How to Ask Questions the Smart Way, by Eric S. Raymond:
http://catb.org/~esr/faqs/smart-questions.html
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Re: converting a string into a set
(thank-you Sean A Corfield)
On Mon, Jul 18, 2011 at 10:29 PM, Sean Corfield seancorfi...@gmail.comwrote:
On Mon, Jul 18, 2011 at 9:17 PM, Tuba Lambanog tuba.lamba...@gmail.com
wrote:
(set abc)
gives me #{\a \b \c}.
I'm expecting instead: #{a b c}
(set (map abc))
(set (map str Tuba Lambanog))
--
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An Architect's View -- http://corfield.org/
World Singles, LLC. -- http://worldsingles.com/
Railo Technologies, Inc. -- http://www.getrailo.com/
Perfection is the enemy of the good.
-- Gustave Flaubert, French realist novelist (1821-1880)
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Re: converting a string into a set
Hi,
I'm clear on what I want ;) (something new to me), but I'm not clear on how
to get there. I'd like to compare str1 and str2, if at least one of the
letters in str1 is in str2. I'm thinking that if I can convert str1 and str2
to sets, then I can use the set intersection operation. It probably doesn't
matter here if the sets contain characters or symbols?
Tuba
On Mon, Jul 18, 2011 at 10:31 PM, Benjamin Esham bdes...@gmail.com wrote:
Tuba Lambanog wrote:
Tuba Lambanog wrote:
Hello, My apologies for this newbie question. I couldn't find a way to
convert a string to a set, thus:
abc = #{a b c}
(set abc) gives me #{\a \b \c}. I'm expecting instead: #{a b c}
Hi Tuba,
Are you quite sure that #{\a \b \c} is not what you want? In Clojure's
notation, a backslashed character [more or less] refers to a
single-character string--something akin to the char type from C. Hence \a
is
the character a. On the other hand #{a b c} is a set containing three
Clojure symbols, which is probably not what you want.
(If you want to be using a, b, and c as some kind of identifiers, take a
look at keywords.)
--
Benjamin D. Esham | bdes...@gmail.com | www.bdesham.info
How to Ask Questions the Smart Way, by Eric S. Raymond:
http://catb.org/~esr/faqs/smart-questions.html
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Re: converting a string into a set
In that case you don't need to convert to a symbol...
(set abc) should be fine...
Using set intersection, something like this is probably what you're looking
for...
(use 'clojure.set)
(if (empty? (intersection (set abc) (set cde))) false true))
I'm sure there's other (better) ways though
On 19/07/2011, at 2:48 PM, Tuba Lambanog wrote:
Hi,
I'm clear on what I want ;) (something new to me), but I'm not clear on how
to get there. I'd like to compare str1 and str2, if at least one of the
letters in str1 is in str2. I'm thinking that if I can convert str1 and str2
to sets, then I can use the set intersection operation. It probably doesn't
matter here if the sets contain characters or symbols?
Tuba
On Mon, Jul 18, 2011 at 10:31 PM, Benjamin Esham bdes...@gmail.com wrote:
Tuba Lambanog wrote:
Tuba Lambanog wrote:
Hello, My apologies for this newbie question. I couldn't find a way to
convert a string to a set, thus:
abc = #{a b c}
(set abc) gives me #{\a \b \c}. I'm expecting instead: #{a b c}
Hi Tuba,
Are you quite sure that #{\a \b \c} is not what you want? In Clojure's
notation, a backslashed character [more or less] refers to a
single-character string--something akin to the char type from C. Hence \a is
the character a. On the other hand #{a b c} is a set containing three
Clojure symbols, which is probably not what you want.
(If you want to be using a, b, and c as some kind of identifiers, take a
look at keywords.)
--
Benjamin D. Esham | bdes...@gmail.com | www.bdesham.info
How to Ask Questions the Smart Way, by Eric S. Raymond:
http://catb.org/~esr/faqs/smart-questions.html
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Re: converting a string into a set
(some (set str1) str2)
will give you what you want..
Sunil
On Tue, Jul 19, 2011 at 10:06 AM, Tuba Lambanog tuba.lamba...@gmail.comwrote:
(thank-you Sean A Corfield)
On Mon, Jul 18, 2011 at 10:29 PM, Sean Corfield seancorfi...@gmail.comwrote:
On Mon, Jul 18, 2011 at 9:17 PM, Tuba Lambanog tuba.lamba...@gmail.com
wrote:
(set abc)
gives me #{\a \b \c}.
I'm expecting instead: #{a b c}
(set (map abc))
(set (map str Tuba Lambanog))
--
Sean A Corfield -- (904) 302-SEAN
An Architect's View -- http://corfield.org/
World Singles, LLC. -- http://worldsingles.com/
Railo Technologies, Inc. -- http://www.getrailo.com/
Perfection is the enemy of the good.
-- Gustave Flaubert, French realist novelist (1821-1880)
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Re: converting a string into a set
On Tue, Jul 19, 2011 at 12:48 AM, Tuba Lambanog tuba.lamba...@gmail.comwrote: Hi, I'm clear on what I want ;) (something new to me), but I'm not clear on how to get there. I'd like to compare str1 and str2, if at least one of the letters in str1 is in str2. I'm thinking that if I can convert str1 and str2 to sets, then I can use the set intersection operation. It probably doesn't matter here if the sets contain characters or symbols? Tuba Or you could do this: (some (set str1) (set str2)) David -- You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: converting a string into a set
Wow, that some function is just what I'd expect from Clojure, simple, straightforward, elegant. How did I miss it? Thanks all. Tuba On Jul 18, 11:00 pm, David Nolen dnolen.li...@gmail.com wrote: On Tue, Jul 19, 2011 at 12:48 AM, Tuba Lambanog tuba.lamba...@gmail.comwrote: Hi, I'm clear on what I want ;) (something new to me), but I'm not clear on how to get there. I'd like to compare str1 and str2, if at least one of the letters in str1 is in str2. I'm thinking that if I can convert str1 and str2 to sets, then I can use the set intersection operation. It probably doesn't matter here if the sets contain characters or symbols? Tuba Or you could do this: (some (set str1) (set str2)) David -- You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
