Re: list* does not make a list?
Hi, On 17 Jan., 11:28, LordGeoffrey wrote: > The docs don't say that it is lazy. How (as a newbie) can i tell that it > is lazy? By the words "the last of which will be treated as a sequence". A sequence is (in general) lazy. Hence, what list* returns is actually a sequence and not a list. As mentioned elsewhere the docs could be improved and the name "list*" was likely a suboptimal choice. Sincerely Meikel -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: list* does not make a list?
The docs don't say that it is lazy. How (as a newbie) can i tell that it is lazy? Docs: "Creates a new list containing the items prepended to the rest, the last of which will be treated as a sequence." On 17/01/11 06:27, Sean Allen wrote: the documentation on that could be improved. the doc string for that is basically the same as for list. but they return different types. rather surprising when you first see it. -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: list* does not make a list?
the documentation on that could be improved. the doc string for that is basically the same as for list. but they return different types. rather surprising when you first see it. On Sun, Jan 16, 2011 at 1:55 PM, Alan wrote: > list* consumes its last argument lazily, which means it can't count it > (a requirement to be a real list). Both functions return objects that > are seqs, though, so you can (seq?) them if you want. > > user=> (def x (list* (range))) > #'user/x > user=> (def x (apply list (range))) > java.lang.OutOfMemoryError: Java heap space (NO_SOURCE_FILE:4) > > > On Jan 16, 10:21 am, Brian Marick wrote: > > movies.core> (list? (apply list (map identity [1 2 3]))) > > true > > > > Makes sense to me! > > > > movies.core> (list? (list* (map identity [1 2 3]))) > > false > > > > Huh? > > > > - > > Brian Marick, Artisanal Labrador > > Contract programming in Ruby and Clojure > > Author of /Ring/ (forthcoming; sample: > http://bit.ly/hfdf9T)www.exampler.com,www.exampler.com/blog,www.twitter.com/marick > > -- > You received this message because you are subscribed to the Google > Groups "Clojure" group. > To post to this group, send email to clojure@googlegroups.com > Note that posts from new members are moderated - please be patient with > your first post. > To unsubscribe from this group, send email to > clojure+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/clojure?hl=en > -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: list* does not make a list?
On Jan 16, 2011, at 12:55 PM, Alan wrote: > list* consumes its last argument lazily, which means it can't count it That is indeed what it does. seq* would have been a better name. Too late now, I guess. - Brian Marick, Artisanal Labrador Contract programming in Ruby and Clojure Author of /Ring/ (forthcoming; sample: http://bit.ly/hfdf9T) www.exampler.com, www.exampler.com/blog, www.twitter.com/marick -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: list* does not make a list?
list* consumes its last argument lazily, which means it can't count it (a requirement to be a real list). Both functions return objects that are seqs, though, so you can (seq?) them if you want. user=> (def x (list* (range))) #'user/x user=> (def x (apply list (range))) java.lang.OutOfMemoryError: Java heap space (NO_SOURCE_FILE:4) On Jan 16, 10:21 am, Brian Marick wrote: > movies.core> (list? (apply list (map identity [1 2 3]))) > true > > Makes sense to me! > > movies.core> (list? (list* (map identity [1 2 3]))) > false > > Huh? > > - > Brian Marick, Artisanal Labrador > Contract programming in Ruby and Clojure > Author of /Ring/ (forthcoming; > sample:http://bit.ly/hfdf9T)www.exampler.com,www.exampler.com/blog,www.twitter.com/marick -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
