apply func
I cannot understand why this does'nt work (apply inc [1 2 3 4]) ; apply inc to each vector element while this works (apply println [1 2 3 4]) ;; takes each element and prints it why inc can't take each element and incr it giving the result ... 2 3 4 5 thanks in advance vincent -- You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: apply func
why inc can't take each element and incr it giving the result ... 2 3 4 5 thanks in advance apply works as if you were calling the function with the elements of the vector. In other words: (apply inc [1 2 3 4 5) ==is like saying=== (inc 1 2 3 4 5) Which is not what you want. However, the following will with each individual element in the vector, call a function and return a new sequence with the results in each subsequent slot: (map inc [1 2 3 4 5] ;= (2 3 4 5 6) -- You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: apply func
On Sun Sep 25 06:38 2011, Vincent wrote: I cannot understand why this does'nt work (apply inc [1 2 3 4]) ; apply inc to each vector element From the documentation: clojure.core/apply ([f args* argseq]) Applies fn f to the argument list formed by prepending args to argseq. This means that apply invokes the function once with the collection expanded to become the arguments to the function. So, (apply inc [1 2 3 4]) essentially expands to (inc 1 2 3 4). However, inc only takes one argument at a time. What you want to do instead is invoke the function for each item in the vector. For this, there is map: clojure.core/map ([f coll] [f c1 c2] [f c1 c2 c3] [f c1 c2 c3 colls]) Returns a lazy sequence consisting of the result of applying f to the set of first items of each coll, followed by applying f to the set of second items in each coll, until any one of the colls is exhausted. Any remaining items in other colls are ignored. Function f should accept number-of-colls arguments. Using map, (map inc [1 2 3 4]) essentially becomes: '((inc 1) (inc 2) (inc 3) (inc 4)), except that it is lazy, meaning that none of the increments are actually invoked until you actually try to use them. If you really want a vector, you can use apply for that: user= (apply vector (map inc [1 2 3 4])) [2 3 4 5] This apply/map combination is common in Clojure and other functional languagues. while this works (apply println [1 2 3 4]) ;; takes each element and prints it This works because takes a variable number of arguments. You can compare how map and apply differ when using them with println: user= (apply println [1 2 3 4]) ; one invocation with all arguments 1 2 3 4 nil user= (map println [1 2 3 4]) ; an invocation for each argument (1 2 3 4 nil nil nil nil) why inc can't take each element and incr it giving the result ... 2 3 4 5 I hope my explanation helps. Sincerely, Daniel Solano Gómez signature.asc Description: Digital signature
Re: apply func
inc takes number as an argument, not a seq. The function that you are probably looking for is map: (map inc [1 2 3 4]) -- You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
