[C++-sig] Boost Python Tuple - Find length of tuple?
Hello,
I have a simple question. How do I find out in c++ how many elements are
contained within a boost::python::tuple?
I tried this:
using namespace boost::python;
tuple a = make_tuple("hello", 42);
object b = a.attr("length"); // exception
unsigned int c = extract(b);
assert( c==2 );
AttributeError: 'tuple' object has no attribute 'length'
Am I missing something?
Thanks
Si
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Re: [C++-sig] Boost Python Tuple - Find length of tuple?
You could try this instead: (untested!)
using namespace boost::python;
tuple a = make_tuple("hello", 42);
std::cout << "Length = " << boost::python::len(a) << std::endl; //
explicit namespace not needed
hth,
Brian
2010/1/4 Simon Pickles
> Hello,
>
> I have a simple question. How do I find out in c++ how many elements are
> contained within a boost::python::tuple?
>
> I tried this:
>
> using namespace boost::python;
> tuple a = make_tuple("hello", 42);
> object b = a.attr("length"); // exception
> unsigned int c = extract(b);
> assert( c==2 );
>
> AttributeError: 'tuple' object has no attribute 'length'
>
> Am I missing something?
>
> Thanks
>
> Si
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>
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Re: [C++-sig] Boost Python Tuple - Find length of tuple?
On 01/04/2010 08:53 AM, Simon Pickles wrote:
Hello,
I have a simple question. How do I find out in c++ how many elements
are contained within a boost::python::tuple?
I tried this:
using namespace boost::python;
tuple a = make_tuple("hello", 42);
object b = a.attr("length"); // exception
unsigned int c = extract(b);
assert( c==2 );
AttributeError: 'tuple' object has no attribute 'length'
Am I missing something?
The attribute is spelled "__len__", not "length", and the pythonic way
to call it is "len(a)". Thus:
tuple a = ...;
unsigned int c = len(a);
should work fine.
Stefan
--
...ich hab' noch einen Koffer in Berlin...
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Re: [C++-sig] Boost Python Tuple - Find length of tuple?
On 04/01/2010 14:02, Brian O'Kennedy wrote:
You could try this instead: (untested!)
using namespace boost::python;
tuple a = make_tuple("hello", 42);
std::cout << "Length = " << boost::python::len(a) << std::endl;
// explicit namespace not needed
Thanks, thats perfect.
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[C++-sig] [boost.python] How can I link against certain python version?
Hi, I try to upgrade my boost from 1.36 to 1.41, but it will link against python26.lib. My own python version is 2.5, How can I tell boost to link with python25.lib? Thanks. -- View this message in context: http://old.nabble.com/-boost.python--How-can-I-link-against-certain-python-version--tp26984580p26984580.html Sent from the Python - c++-sig mailing list archive at Nabble.com. ___ Cplusplus-sig mailing list [email protected] http://mail.python.org/mailman/listinfo/cplusplus-sig
