Hi and Happy Easter to all of you.
I want to thank thokster for his very good advice (in a personal
conversation) that helped to clear my brains. Now that I reorganize my
photo filing system I can easily use $(FILE_FOLDER) to get what I want.
It's my lot to think in a too complicated way.
Volker
Am 09.04.20 um 20:30 schrieb Volker Lenhardt:
I use to export my images to jpg with a standardized file name:
$(FILE_NAME:4)-???_$(EXIF_YEAR)-$(DESCRIPTION)
The "???" is a placeholder for a part of the path, which I type in for
the time being, but which I want to find an automized way to replace,
too. One after the other.
How can I set the preference from the default "$(FILE_NAME)" to my user
defined string?
I couldn‘t find a way, so I thought about some lua script. Lua seems to
be somewhat simple, but I find the lua API not so easy to look through.
Anyhow I find "events.intermediate-export-image.callback" promising to
intercept and change the filename, but how do I proceed? My skills are
on the scale of pre-beginners for now. I haven’t got further than
scanning through existing lua scripts to catch a glimpse of what to do,
but I‘m confident in raising my learning curve soon.
Please set me on the track.
Volker
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