Re: OUStringBuffer
sorry was working with openmeetings and that is in java On Wed, May 8, 2013 at 4:42 AM, Regina Henschel rb.hensc...@t-online.dewrote: Hi Jorge, jorge ivan poot diaz schrieb: Hello, I have a doubt, help I made this snippet String abuf = buf.charAt(nLen - 1); double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL ); printf ( Is : %i , ng); I do not meant, that you should call stringToDouble. I meant, that you should look into the implementation of that method to see how the conversion from character to digit is done there. Are you sure that the line String abuf = buf.charAt(nLen - 1); really does, what you think that it does? Kind regards Regina --**--**- To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.orgdev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org -- Rahul Bhola B.E. computers Core Member Department of backstage Bits Pilani KK Birla Goa Campus
Re: OUStringBuffer
Hello, I have a doubt, help I made this snippet String abuf = buf.charAt(nLen - 1); double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL ); printf ( Is : %i , ng); But the return value is 0, in theory I want to return the last digit of the string String : world1695 Is : 0 String : world3184 Is : 0 ivan@ivan-Presario-CQ43-Notebook-PC:~$ The idea is that String : world3184 Is : 4 Any ideas why not return a numeric value? Regards 2013/5/6 Regina Henschel rb.hensc...@t-online.de Hi Jorge, jorge ivan poot diaz schrieb: thanks, buf.charAt (nLen - 1): this variable has a string as '1' or '2', '3'...'9' as it could change to int, any ideas, please help! I've done this: int ty = buf.charAt(nLen - 1); built well, but the result is not as expected. You should post what you get and what you expect. But perhaps the following hints might already solve your problem. Have a look at stringToDouble in main/sal/rtl/source/math.cxx to learn about converting to number. Or charAt returns a sal_Unicode. Searching the definition for sal_unicode you come to main/sal/inc/sal/types.h with leads you to wchar_t. So search in internet for wchar_t to int to get an idea what to do. Kind regards Regina --**--**- To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.orgdev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org
Re: OUStringBuffer
take a substring that contains only the last letter and then use Integer.parseInt() to convert it into integer On Tue, May 7, 2013 at 9:56 PM, jorge ivan poot diaz ivan.pootd...@gmail.com wrote: Hello, I have a doubt, help I made this snippet String abuf = buf.charAt(nLen - 1); double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL ); printf ( Is : %i , ng); But the return value is 0, in theory I want to return the last digit of the string String : world1695 Is : 0 String : world3184 Is : 0 ivan@ivan-Presario-CQ43-Notebook-PC:~$ The idea is that String : world3184 Is : 4 Any ideas why not return a numeric value? Regards 2013/5/6 Regina Henschel rb.hensc...@t-online.de Hi Jorge, jorge ivan poot diaz schrieb: thanks, buf.charAt (nLen - 1): this variable has a string as '1' or '2', '3'...'9' as it could change to int, any ideas, please help! I've done this: int ty = buf.charAt(nLen - 1); built well, but the result is not as expected. You should post what you get and what you expect. But perhaps the following hints might already solve your problem. Have a look at stringToDouble in main/sal/rtl/source/math.cxx to learn about converting to number. Or charAt returns a sal_Unicode. Searching the definition for sal_unicode you come to main/sal/inc/sal/types.h with leads you to wchar_t. So search in internet for wchar_t to int to get an idea what to do. Kind regards Regina --**--**- To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.org dev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org -- Rahul Bhola B.E. computers Core Member Department of backstage Bits Pilani KK Birla Goa Campus
Re: OUStringBuffer
Hi, rahul bhola schrieb: take a substring that contains only the last letter and then use Integer.parseInt() to convert it into integer ??? We are in C++ not in Java. Kind regards Regina On Tue, May 7, 2013 at 9:56 PM, jorge ivan poot diaz ivan.pootd...@gmail.com wrote: Hello, I have a doubt, help I made this snippet String abuf = buf.charAt(nLen - 1); double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL ); printf ( Is : %i , ng); But the return value is 0, in theory I want to return the last digit of the string String : world1695 Is : 0 String : world3184 Is : 0 ivan@ivan-Presario-CQ43-Notebook-PC:~$ The idea is that String : world3184 Is : 4 Any ideas why not return a numeric value? Regards 2013/5/6 Regina Henschel rb.hensc...@t-online.de Hi Jorge, jorge ivan poot diaz schrieb: thanks, buf.charAt (nLen - 1): this variable has a string as '1' or '2', '3'...'9' as it could change to int, any ideas, please help! I've done this: int ty = buf.charAt(nLen - 1); built well, but the result is not as expected. You should post what you get and what you expect. But perhaps the following hints might already solve your problem. Have a look at stringToDouble in main/sal/rtl/source/math.cxx to learn about converting to number. Or charAt returns a sal_Unicode. Searching the definition for sal_unicode you come to main/sal/inc/sal/types.h with leads you to wchar_t. So search in internet for wchar_t to int to get an idea what to do. Kind regards Regina --**--**- To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.org dev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org - To unsubscribe, e-mail: dev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org
Re: OUStringBuffer
Hi Jorge, jorge ivan poot diaz schrieb: Hello, I have a doubt, help I made this snippet String abuf = buf.charAt(nLen - 1); double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL ); printf ( Is : %i , ng); I do not meant, that you should call stringToDouble. I meant, that you should look into the implementation of that method to see how the conversion from character to digit is done there. Are you sure that the line String abuf = buf.charAt(nLen - 1); really does, what you think that it does? Kind regards Regina - To unsubscribe, e-mail: dev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org
Re: OUStringBuffer
thanks, buf.charAt (nLen - 1): this variable has a string as '1' or '2', '3'...'9' as it could change to int, any ideas, please help! I've done this: int ty = buf.charAt(nLen - 1); built well, but the result is not as expected. regards! 2013/4/29 Herbert Dürr h...@apache.org Hi Jorge, like Regina I have a hard time to understand the question. My best guess is that you have an OUStringBuffer object and need an UniString (aka tool's String [1]). If that is so you can get it using the UniString constructor that takes an OUString argument: UniString( buf.makeStringAndClear() ) [1] http://opengrok.adfinis-**sygroup.org/source/xref/aoo-** trunk/main/tools/inc/tools/**solar.h#269http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/tools/inc/tools/solar.h#269 Hope that helps, Herbert On 2013/04/25 8:00 PM, jorge ivan poot diaz wrote: I've already made a concatenation, in this file: http://opengrok.adfinis-**sygroup.org/source/xref/aoo-** trunk/main/cui/source/**tabpages/tpcolor.cxx#546http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#546 Something like this: OUStringBuffer buf( 128 ); buf.append( aName ); buf.append( 4 ); OUString string = buf.makeStringAndClear(); OString oString = rtl::OUStringToOString( string , RTL_TEXTENCODING_ASCII_US ); Substituting aName by oString in this fragment of code http://opengrok.adfinis-**sygroup.org/source/xref/aoo-** trunk/main/cui/source/**tabpages/tpcolor.cxx#549http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#549 , I have the following error, http://ooo.pastebin.ca/2366521 So, I want to convert this code to a STRING: OString oString = rtl::OUStringToOString( string , RTL_TEXTENCODING_ASCII_US ); Because the definition of aName is STRING, as you can see here: http://ooo.pastebin.ca/2366523 The file is located at: http://opengrok.adfinis-**sygroup.org/source/xref/aoo-** trunk/main/svx/inc/svx/xtable.**hxx#57http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/svx/inc/svx/xtable.hxx#57 --**--**- To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.orgdev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org
Re: OUStringBuffer
Hi Jorge, jorge ivan poot diaz schrieb: thanks, buf.charAt (nLen - 1): this variable has a string as '1' or '2', '3'...'9' as it could change to int, any ideas, please help! I've done this: int ty = buf.charAt(nLen - 1); built well, but the result is not as expected. You should post what you get and what you expect. But perhaps the following hints might already solve your problem. Have a look at stringToDouble in main/sal/rtl/source/math.cxx to learn about converting to number. Or charAt returns a sal_Unicode. Searching the definition for sal_unicode you come to main/sal/inc/sal/types.h with leads you to wchar_t. So search in internet for wchar_t to int to get an idea what to do. Kind regards Regina - To unsubscribe, e-mail: dev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org
Re: OUStringBuffer
Hi Jorge, like Regina I have a hard time to understand the question. My best guess is that you have an OUStringBuffer object and need an UniString (aka tool's String [1]). If that is so you can get it using the UniString constructor that takes an OUString argument: UniString( buf.makeStringAndClear() ) [1] http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/tools/inc/tools/solar.h#269 Hope that helps, Herbert On 2013/04/25 8:00 PM, jorge ivan poot diaz wrote: I've already made a concatenation, in this file: http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#546 Something like this: OUStringBuffer buf( 128 ); buf.append( aName ); buf.append( 4 ); OUString string = buf.makeStringAndClear(); OString oString = rtl::OUStringToOString( string , RTL_TEXTENCODING_ASCII_US ); Substituting aName by oString in this fragment of code http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#549, I have the following error, http://ooo.pastebin.ca/2366521 So, I want to convert this code to a STRING: OString oString = rtl::OUStringToOString( string , RTL_TEXTENCODING_ASCII_US ); Because the definition of aName is STRING, as you can see here: http://ooo.pastebin.ca/2366523 The file is located at: http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/svx/inc/svx/xtable.hxx#57 - To unsubscribe, e-mail: dev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org
Re: OUStringBuffer
Hi Jorge, I fear, I cannot help you really. Perhaps, you ask again with a clear statement, what the goal of your tries are. Your emails are very hard to understand for me. jorge ivan poot diaz schrieb: I've already made a concatenation, in this file: http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#546 Something like this: OUStringBuffer buf( 128 ); buf.append( aName ); buf.append( 4 ); OUString string = buf.makeStringAndClear(); OString oString = rtl::OUStringToOString( string , RTL_TEXTENCODING_ASCII_US ); Substituting aName by oString why? Reading code where a variable has the same or nearly the same identifier as a data type is hard. Please avoid it. There might be other side effects of using string as identifier. in this fragment of code http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#549, I have the following error, http://ooo.pastebin.ca/2366521 Yes, the second parameter has a wrong type. So, I want to convert this code to a STRING: STRING ?? Please be very exact in using lower or upper characters. The class String is in main/cosv/inc/cosv/string.hxx Kind regards Regina - To unsubscribe, e-mail: dev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org
Re: OUStringBuffer
Hi, jorge ivan poot diaz schrieb: I have doubts about using class OUStringBuffer You should be more specific about your problem. Do you need help in understanding the descriptions in ustrbuf.hxx? Or do you get an compiler error, which do you not understand? Or do you need help about the difference to other string types? Or ...? I want to implement this code: x = new OUStringBuffer().append(a).append(4).append(c).toString(); (one example) This snippet, missing something? (A declaration of variables?) Please post a little bit more. Where do you want to use that code? What is x ? Do you want to do something specific, or is it an exercise, some kind of hello world? Kind regards Regina - To unsubscribe, e-mail: dev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org
Re: OUStringBuffer
I've already made a concatenation, in this file: http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#546 Something like this: OUStringBuffer buf( 128 ); buf.append( aName ); buf.append( 4 ); OUString string = buf.makeStringAndClear(); OString oString = rtl::OUStringToOString( string , RTL_TEXTENCODING_ASCII_US ); Substituting aName by oString in this fragment of code http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#549, I have the following error, http://ooo.pastebin.ca/2366521 So, I want to convert this code to a STRING: OString oString = rtl::OUStringToOString( string , RTL_TEXTENCODING_ASCII_US ); Because the definition of aName is STRING, as you can see here: http://ooo.pastebin.ca/2366523 The file is located at: http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/svx/inc/svx/xtable.hxx#57 Regards. 2013/4/25 Regina Henschel rb.hensc...@t-online.de Hi, jorge ivan poot diaz schrieb: I have doubts about using class OUStringBuffer You should be more specific about your problem. Do you need help in understanding the descriptions in ustrbuf.hxx? Or do you get an compiler error, which do you not understand? Or do you need help about the difference to other string types? Or ...? I want to implement this code: x = new OUStringBuffer().append(a).**append(4).append(c).** toString(); (one example) This snippet, missing something? (A declaration of variables?) Please post a little bit more. Where do you want to use that code? What is x ? Do you want to do something specific, or is it an exercise, some kind of hello world? Kind regards Regina --**--**- To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.orgdev-unsubscr...@openoffice.apache.org For additional commands, e-mail: dev-h...@openoffice.apache.org
