I wrote this earlier:
```
import std.stdio;
import std.algorithm.searching;
string[] numeric_traits_1 = [];
string[] numeric_traits_2 = ["Two"];
string[] numeric_traits_3 = ["One"];
string[] numeric_traits_4 = ["One", "Two"];
void main() {
void numeric_traits_contains(string[] numeric) {
if(numeric.canFind("One") & numeric.canFind("Two")) {
writeln("Array contains 'One' and 'Two'.");
} else if(numeric.canFind("One", "Two")) {
writeln("Array contains 'One' or 'Two'.");
} else {
writeln("Array contains neither 'One' nor 'Two'");
}
}
numeric_traits_contains(numeric_traits_1);
numeric_traits_contains(numeric_traits_2);
numeric_traits_contains(numeric_traits_3);
numeric_traits_contains(numeric_traits_4);
}
```
`if` runs when both "One" and "Two" are in the given array as
intended, but its conditional statement looks verbose. Is there a
more concise way of getting the same result?
