Re: Member function forwarding
On Thursday, 17 February 2022 at 21:17:02 UTC, Andrey Zherikov
wrote:
On Thursday, 17 February 2022 at 20:59:43 UTC, Andrey Zherikov
wrote:
Another question: does `auto foo(ARGS...)(ARGS args) { return
a.foo(args); }` correctly forward `ref`, `const` etc.
arguments?
Actually the answer is `NO`. I have to do `auto
foo(ARGS...)(auto ref ARGS args) { return
a.foo(args); }`.
This also doesn't forward correctly. It'll always try to copy all
arguments. What would fowrard is
```
import core.lifetime : forward;
auto foo(Args...)(auto ref Args args) { return
a.foo(forward!args); }
```
Re: Member function forwarding
On Thursday, 17 February 2022 at 20:59:43 UTC, Andrey Zherikov
wrote:
Another question: does `auto foo(ARGS...)(ARGS args) { return
a.foo(args); }` correctly forward `ref`, `const` etc. arguments?
Actually the answer is `NO`. I have to do `auto foo(ARGS...)(auto
ref ARGS args) { return
a.foo(args); }`. Also if `a.foo` is a `const` function then I
have to add `const` to this definition as well.
Member function forwarding
I have a struct that has struct data member and I'd like to
forward some (not all) functions from internal data member. Some
thing like this:
```d
struct A {
void foo() const { writeln("A.foo"); }
}
struct B {
A a;
auto foo(ARGS...)(ARGS args) { return a.foo(args); }
// alias foo = a.foo;
}
void main()
{
B b;
b.foo(); // In "alias" case: Error: `this` for `foo` needs
to be type `A` not type `B`
}
```
Is there simpler way to achieve this?
I tried `alias foo = a.foo` but it doesn't work: "Error: `this`
for `foo` needs to be type `A` not type `B`" - when function is
called (`b.foo()`).
Another question: does `auto foo(ARGS...)(ARGS args) { return
a.foo(args); }` correctly forward `ref`, `const` etc. arguments?
