Re: Using std.math: FloatingPointControl.enableExceptions

[Shriramana Sharma via Digitalmars-d-learn]

rumbu wrote:

> Constant folding: a is evaluated at compile time to + infinity.

Hmm... I guess the compiler figures that if someone is hardcoding that 
expression then they don't want to see an exception. Thanks for the 
explanation.

-- 
Shriramana Sharma, Penguin #395953

Re: Using std.math: FloatingPointControl.enableExceptions

[rumbu via Digitalmars-d-learn]

On Friday, 11 December 2015 at 06:28:09 UTC, Shriramana Sharma 
wrote:
Hello. I'm trying to figure out how to use 
FloatingPointControl.enableExceptions. Upon enabling 
severeExceptions I would expect the division by zero to be 
signaled, but neither do I get a SIGFPE nor does ieeeFlags show 
the exception having been signaled. What am I doing wrong?


import std.stdio;
import std.math;
void main()
{
FloatingPointControl fc;
fc.enableExceptions(fc.severeExceptions);
real a = 1.0 / 0.0;
writeln(ieeeFlags.divByZero);



Constant folding: a is evaluated at compile time to + infinity.

Using std.math: FloatingPointControl.enableExceptions

[Shriramana Sharma via Digitalmars-d-learn]

Hello. I'm trying to figure out how to use 
FloatingPointControl.enableExceptions. Upon enabling severeExceptions I 
would expect the division by zero to be signaled, but neither do I get a 
SIGFPE nor does ieeeFlags show the exception having been signaled. What am I 
doing wrong?

import std.stdio;
import std.math;
void main()
{
FloatingPointControl fc;
fc.enableExceptions(fc.severeExceptions);
real a = 1.0 / 0.0;
writeln(ieeeFlags.divByZero);
}

-- 
Shriramana Sharma, Penguin #395953