Re: can't access an alias created inside an if statement
On Wednesday, 5 August 2020 at 09:39:47 UTC, Simen Kjærås wrote:
On Wednesday, 5 August 2020 at 09:32:58 UTC, Flade wrote:
Thanks! You see it should work but the thing is. I'm using it
inside a function. I'm checking for one of the function's
parameter (if parameter == false) and it says that "the
variable `parameter` cannot be read at compile time. Do you
know if there is a way to fix this?
As the error message says, the value must be known at compile
time. Most likely, you can simply pass it as a template
parameter:
void fun(bool parameter)(int arg1, string arg2) {
static if (parameter) {
}
}
void main() {
fun!true(1, "foo");
fun!false(19, "bar");
}
--
Simen
Thanks man! Works as expected! Have a great day!
Re: can't access an alias created inside an if statement
On Wednesday, 5 August 2020 at 09:32:58 UTC, Flade wrote:
Thanks! You see it should work but the thing is. I'm using it
inside a function. I'm checking for one of the function's
parameter (if parameter == false) and it says that "the
variable `parameter` cannot be read at compile time. Do you
know if there is a way to fix this?
As the error message says, the value must be known at compile
time. Most likely, you can simply pass it as a template parameter:
void fun(bool parameter)(int arg1, string arg2) {
static if (parameter) {
}
}
void main() {
fun!true(1, "foo");
fun!false(19, "bar");
}
--
Simen
Re: can't access an alias created inside an if statement
On Wednesday, 5 August 2020 at 09:25:23 UTC, Simen Kjærås wrote:
On Wednesday, 5 August 2020 at 09:05:36 UTC, Flade wrote:
I have used an if-else statement to create an alias to avoid
code duplication but it doesn't let me access it outside the
if statement. Is there a way to solve this?
You're probably looking for static if:
static if (useAlias) {
alias myAlias = getAlias!();
}
myAlias foo = getFoo();
What happens is a regular if statement introduces a scope, so
anything declared inside it is unavailable outside. static if
does not introduce a new scope, and so its contents can be
accessed.
static if only works with compile-time constant conditions, but
aliases are also compile-time constructs, so this should not
pose a problem.
--
Simen
Thanks! You see it should work but the thing is. I'm using it
inside a function. I'm checking for one of the function's
parameter (if parameter == false) and it says that "the variable
`parameter` cannot be read at compile time. Do you know if there
is a way to fix this?
Re: can't access an alias created inside an if statement
On Wednesday, 5 August 2020 at 09:05:36 UTC, Flade wrote:
I have used an if-else statement to create an alias to avoid
code duplication but it doesn't let me access it outside the if
statement. Is there a way to solve this?
You're probably looking for static if:
static if (useAlias) {
alias myAlias = getAlias!();
}
myAlias foo = getFoo();
What happens is a regular if statement introduces a scope, so
anything declared inside it is unavailable outside. static if
does not introduce a new scope, and so its contents can be
accessed.
static if only works with compile-time constant conditions, but
aliases are also compile-time constructs, so this should not pose
a problem.
--
Simen
can't access an alias created inside an if statement
I have used an if-else statement to create an alias to avoid code duplication but it doesn't let me access it outside the if statement. Is there a way to solve this?
