On Wednesday, 17 October 2018 at 02:54:26 UTC, test wrote:
I need get the Route UDA only for method without (static
methods, property, constructor, destructor), dont know how to
do it.
1) Note that __traits(allMembers, T) gets you a tuple of names,
not actual member aliases.
2) Remember there may be overloads
3) Filter the unwanted out:
import std.traits;
import std.meta : Alias, AliasSeq;
import std.stdio;
import std.string : startsWith;
import std.algorithm : among;
alias operatorNames = AliasSeq!("opUnary", "opIndexUnary",
"opCast", "opBinary", "opBinaryRight",
"opIn", "opIn_r", "opEquals",
"opCmp", "opCall", "opAssign",
"opIndexAssign", "opOpAssign",
"opIndexOpAssign", "opSliceOpAssign",
"opIndex", "opSlice", "opDollar",
"opDispatch");
void main() {
writeln(getRoutes!App);
}
struct Route { string r; }
Route[] getRoutes(T)(){
Route[] routes;
foreach (name; __traits(allMembers, T)) {
alias member = Alias!(__traits(getMember, T, name));
static if (__traits(isStaticFunction, member) ||
name.startsWith("__") ||
name.among(operatorNames))
{}
else static if (is(typeof(member) == function)) {
foreach (overload; __traits(getOverloads, T, name)) {
pragma(msg, name);
static foreach(route; getUDAs!(overload, Route)) {
routes ~= route;
}
}
}
}
return routes;
}
struct App {
@Route("xxx")
int field;
@Route("/blah")
this(this) {}
@Route("ggg")
~this() {}
@Route("/index")
void home() {}
@Route("/index2")
void home(bool overloaded) {}
@Route("/blog")
void blog(){}
}