scope exit in mixin template

[Byron via Digitalmars-d-learn]

Can we not use scope(..) in a mixin template?

struct bar {}
bar* c_make() { return new bar(); }
void c_free(bar* b) { b = null; }

mixin template Foo() {
  auto b = c_make;
  scope(exit) if(b) c_free(b);
}

void main() {
  mixin Foo;
}

I get Error: Declaration expected, not '('

-Byron

Re: scope exit in mixin template

[monarch_dodra via Digitalmars-d-learn]

On Sunday, 8 June 2014 at 18:28:25 UTC, Byron wrote:


Can we not use scope(..) in a mixin template?

struct bar {}
bar* c_make() { return new bar(); }
void c_free(bar* b) { b = null; }

mixin template Foo() {
  auto b = c_make;
  scope(exit) if(b) c_free(b);
}

void main() {
  mixin Foo;
}

I get Error: Declaration expected, not '('

-Byron


Mixin templates can only insert declarations, not arbitrary code. 
When it sees scope, it's expecting it to be the attribute, not 
the declaration.

Re: scope exit in mixin template

[monarch_dodra via Digitalmars-d-learn]

On Sunday, 8 June 2014 at 18:48:03 UTC, monarch_dodra wrote:
Mixin templates can only insert declarations, not arbitrary 
code. When it sees scope, it's expecting it to be the 
attribute, not the declaration.


To add to that, if you want to mixin arbitrary code, then you can 
use a string mixin:


template declare_bar(string var_name) {
  enum declare_bar =
auto  ~ var_name ~  = c_make(); ~
scope(exit) if( ~ var_name ~ ) c_free( ~ var_name ~ );
}

void main() {
mixin(declar_var!b)
}

For example.

That said, given your example, simply using an RAII wrapper 
*could* be superior (depends on your actual usecase).

Re: scope exit in mixin template

[monarch_dodra via Digitalmars-d-learn]

On Sunday, 8 June 2014 at 18:28:25 UTC, Byron wrote:

void c_free(bar* b) { b = null; }


Heads up: This code does nothing. You are passing the pointer by 
value, so b = null; will have no effect at the end of the call. 
Use pass by ref:


void c_free(ref bar* b) { b = null; }