On Tue, 8 Aug 2006, Rafael Santos wrote:
> i just want to increase a value...
>
> by jQuery:
> var cont = $("#img_counter").val(); //its an input value
> cont = parseInt(cont + 5);
> $("#img_counter").val(cont);
> ...
> =( where am i wrong?
You want:
cont = parseInt(cont) + 5
The input value is a string. To ensure that it is treated like a number,
you have to convert it before you use the + operator, since + is
overloaded for numbers and strings.
--
.. Dave Benjamin - Software Developer - ramenlabs.com
.. AIM: ramenlabs / MSN: [EMAIL PROTECTED]
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