Re: {{ form.as_table }} not displaying in template
Oh and I am not familiar with Ajax I am sorry because I've been
told that's a way to handle it...
Regards
2009/12/13 Mark Schuuring :
> Hey guys thanks for your respond. First of all i read the tutorial
> and the form works in /search with the template and the view. For now
> I am trying to achieve a searchfield in another folder, /blog. Are you
> guys saying i have to copy/ repeat the form in the /blog view and
> template? To be as DRY as possible I'd like to have 1 template/view
> search function and I'd like to pass data from elsewhere to that
> place. So I understand my question was a bit vague but what I'd like
> to do in the /blog template is:
>
> * send from
> /blog to template/view of search
>
> {{ form.as_table }} * load form from
> /search template/view into /blog
>
>
>
>
>
>
>
>
> This is the (standard) views.py from haystack which i have in the app
> folder: http://dpaste.com/132922/
> And this is the (standard) forms.py http://dpaste.com/132923/
>
> Thanks
>
> 2009/12/13 oliver :
>> Sounds like you are not creating the form in your view .. read the
>> tutorial the part about creating a form ..
>> you need the form class, and the view that process your form (a)
>> creates an empty form b) process the submitted one)
>>
>> see this relative simple example of a login form ..
>>
>> class userLoginForm(forms.Form):
>> email = forms.CharField(max_length=45, label="Email address",
>> error_messages={'required': 'Please enter an email address.'})
>> password = forms.CharField(widget=forms.PasswordInput(),
>> label="Password", error_messages={'required': 'Please enter a
>> password.'})
>>
>>
>> def userLogin(request):
>> context_instance = RequestContext(request)
>> try:
>> nextUrl = request.GET['next']
>> except:
>> nextUrl = "/myopal/"
>> if request.POST:
>> form = userLoginForm(request.POST)
>> username = request.POST['email']
>> password = request.POST['password']
>> if form.is_valid():
>> user = authenticate(username=username, password=password)
>> if user is not None:
>> if user.is_active:
>> login(request, user)
>> return HttpResponseRedirect(nextUrl)
>> else:
>> error = "This account as been disabled, please contact
>> support."
>> return render_to_response('registration/login.html',
>> {'form': form, 'login_error': error, 'nextUrl': nextUrl},
>> context_instance)
>> else:
>> error = "Wrong details entered, please try again."
>> return render_to_response('registration/login.html', {'form':
>> form, 'login_error': error, 'nextUrl': nextUrl}, context_instance)
>> else:
>> return render_to_response('registration/login.html', {'form':
>> form, 'nextUrl': nextUrl}, context_instance)
>> else:
>> form = userLoginForm()
>> return render_to_response('registration/login.html', {'form': form,
>> 'nextUrl': nextUrl}, context_instance)
>>
>>
>>
>> On Dec 12, 11:04 pm, GoSantoni wrote:
>>> Hey i've got a very basic question about django form processing. Got
>>> haystack installed and searching works fine in the standard search
>>> template (http://haystacksearch.org/docs/tutorial.html#search-
>>> template) in the /search . Though i want to use the search box defined
>>> by {{ form.as_table }} in another template in /blog . Just copying
>>> {{ form.as_table }} fails to display the input field so what part of
>>> the views.py or the forms.py needs to be copied from the haystack app?
>>> Or what is another solution? So far in /blogs/blogs.html
>>>
>>>
>>>
>>> {{ form.as_table }}
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>> My goal is just to display the input box and send the query to /search
>>> so the results are displayed on that page
>>>
>>> Thanks in advance!
>>
>> --
>>
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>> "Django users" group.
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>>
>>
>>
>
>
>
> --
> Mark Schuuring
> M: mj.schuur...@gmail.com
>
--
Mark Schuuring
M: mj.schuur...@gmail.com
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Re: {{ form.as_table }} not displaying in template
Hey guys thanks for your respond. First of all i read the tutorial
and the form works in /search with the template and the view. For now
I am trying to achieve a searchfield in another folder, /blog. Are you
guys saying i have to copy/ repeat the form in the /blog view and
template? To be as DRY as possible I'd like to have 1 template/view
search function and I'd like to pass data from elsewhere to that
place. So I understand my question was a bit vague but what I'd like
to do in the /blog template is:
* send from
/blog to template/view of search
{{ form.as_table }} * load form from
/search template/view into /blog
This is the (standard) views.py from haystack which i have in the app
folder: http://dpaste.com/132922/
And this is the (standard) forms.py http://dpaste.com/132923/
Thanks
2009/12/13 oliver :
> Sounds like you are not creating the form in your view .. read the
> tutorial the part about creating a form ..
> you need the form class, and the view that process your form (a)
> creates an empty form b) process the submitted one)
>
> see this relative simple example of a login form ..
>
> class userLoginForm(forms.Form):
> email = forms.CharField(max_length=45, label="Email address",
> error_messages={'required': 'Please enter an email address.'})
> password = forms.CharField(widget=forms.PasswordInput(),
> label="Password", error_messages={'required': 'Please enter a
> password.'})
>
>
> def userLogin(request):
> context_instance = RequestContext(request)
> try:
> nextUrl = request.GET['next']
> except:
> nextUrl = "/myopal/"
> if request.POST:
> form = userLoginForm(request.POST)
> username = request.POST['email']
> password = request.POST['password']
> if form.is_valid():
> user = authenticate(username=username, password=password)
> if user is not None:
> if user.is_active:
> login(request, user)
> return HttpResponseRedirect(nextUrl)
> else:
> error = "This account as been disabled, please contact
> support."
> return render_to_response('registration/login.html',
> {'form': form, 'login_error': error, 'nextUrl': nextUrl},
> context_instance)
> else:
> error = "Wrong details entered, please try again."
> return render_to_response('registration/login.html', {'form':
> form, 'login_error': error, 'nextUrl': nextUrl}, context_instance)
> else:
> return render_to_response('registration/login.html', {'form':
> form, 'nextUrl': nextUrl}, context_instance)
> else:
> form = userLoginForm()
> return render_to_response('registration/login.html', {'form': form,
> 'nextUrl': nextUrl}, context_instance)
>
>
>
> On Dec 12, 11:04 pm, GoSantoni wrote:
>> Hey i've got a very basic question about django form processing. Got
>> haystack installed and searching works fine in the standard search
>> template (http://haystacksearch.org/docs/tutorial.html#search-
>> template) in the /search . Though i want to use the search box defined
>> by {{ form.as_table }} in another template in /blog . Just copying
>> {{ form.as_table }} fails to display the input field so what part of
>> the views.py or the forms.py needs to be copied from the haystack app?
>> Or what is another solution? So far in /blogs/blogs.html
>>
>>
>>
>> {{ form.as_table }}
>>
>>
>>
>>
>>
>>
>>
>>
>>
>> My goal is just to display the input box and send the query to /search
>> so the results are displayed on that page
>>
>> Thanks in advance!
>
> --
>
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To post to this group, send email to django-us...@googlegroups.com.
> To unsubscribe from this group, send email to
> django-users+unsubscr...@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/django-users?hl=en.
>
>
>
--
Mark Schuuring
M: mj.schuur...@gmail.com
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Re: {{ form.as_table }} not displaying in template
Sounds like you are not creating the form in your view .. read the
tutorial the part about creating a form ..
you need the form class, and the view that process your form (a)
creates an empty form b) process the submitted one)
see this relative simple example of a login form ..
class userLoginForm(forms.Form):
email = forms.CharField(max_length=45, label="Email address",
error_messages={'required': 'Please enter an email address.'})
password = forms.CharField(widget=forms.PasswordInput(),
label="Password", error_messages={'required': 'Please enter a
password.'})
def userLogin(request):
context_instance = RequestContext(request)
try:
nextUrl = request.GET['next']
except:
nextUrl = "/myopal/"
if request.POST:
form = userLoginForm(request.POST)
username = request.POST['email']
password = request.POST['password']
if form.is_valid():
user = authenticate(username=username, password=password)
if user is not None:
if user.is_active:
login(request, user)
return HttpResponseRedirect(nextUrl)
else:
error = "This account as been disabled, please contact
support."
return render_to_response('registration/login.html',
{'form': form, 'login_error': error, 'nextUrl': nextUrl},
context_instance)
else:
error = "Wrong details entered, please try again."
return render_to_response('registration/login.html', {'form':
form, 'login_error': error, 'nextUrl': nextUrl}, context_instance)
else:
return render_to_response('registration/login.html', {'form':
form, 'nextUrl': nextUrl}, context_instance)
else:
form = userLoginForm()
return render_to_response('registration/login.html', {'form': form,
'nextUrl': nextUrl}, context_instance)
On Dec 12, 11:04 pm, GoSantoni wrote:
> Hey i've got a very basic question about django form processing. Got
> haystack installed and searching works fine in the standard search
> template (http://haystacksearch.org/docs/tutorial.html#search-
> template) in the /search . Though i want to use the search box defined
> by {{ form.as_table }} in another template in /blog . Just copying
> {{ form.as_table }} fails to display the input field so what part of
> the views.py or the forms.py needs to be copied from the haystack app?
> Or what is another solution? So far in /blogs/blogs.html
>
>
>
> {{ form.as_table }}
>
>
>
>
>
>
>
>
>
> My goal is just to display the input box and send the query to /search
> so the results are displayed on that page
>
> Thanks in advance!
--
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Re: {{ form.as_table }} not displaying in template
On Dec 12, 5:04 pm, GoSantoni wrote:
> Hey i've got a very basic question about django form processing. Got
> haystack installed and searching works fine in the standard search
> template (http://haystacksearch.org/docs/tutorial.html#search-
> template) in the /search . Though i want to use the search box defined
> by {{ form.as_table }} in another template in /blog . Just copying
> {{ form.as_table }} fails to display the input field so what part of
> the views.py or the forms.py needs to be copied from the haystack app?
> Or what is another solution? So far in /blogs/blogs.html
>
>
>
> {{ form.as_table }}
>
>
>
>
>
>
>
>
>
> My goal is just to display the input box and send the query to /search
> so the results are displayed on that page
>
> Thanks in advance!
I'm not really sure what you are asking. If the {{ form }} isn't
displaying, then look to your view that renders the template. Are you
building the form right and passing it to the template correctly?
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{{ form.as_table }} not displaying in template
Hey i've got a very basic question about django form processing. Got
haystack installed and searching works fine in the standard search
template (http://haystacksearch.org/docs/tutorial.html#search-
template) in the /search . Though i want to use the search box defined
by {{ form.as_table }} in another template in /blog . Just copying
{{ form.as_table }} fails to display the input field so what part of
the views.py or the forms.py needs to be copied from the haystack app?
Or what is another solution? So far in /blogs/blogs.html
{{ form.as_table }}
My goal is just to display the input box and send the query to /search
so the results are displayed on that page
Thanks in advance!
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-us...@googlegroups.com.
To unsubscribe from this group, send email to
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Re: form.as_table not displaying in template
Thank you all for your quick responses. I was passing the class
instead of the instance. Everything is working great now!
On Apr 22, 12:20 pm, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Tue, 2008-04-22 at 09:02 -0700, Explore wrote:
> > Hi. I am new to django and I am trying to get a handle around the form
> > processing. I am using the svn trunk Revision: 7419 on Windows with
> > the development server. I have a views.py setup in my app that looks
> > like this:
>
> > form = TestingForm()
> > print form.as_table()
> > print form.as_table
> > return render_to_response('testing.html', { 'form':TestingForm })
>
> You're passing in a class to the template, rather than an instance of
> the form. Your need to pass the "form" variable via the dictionary, not
> the TestingForm class.
>
> Regards,
> Malcolm
>
> --
> I just got lost in thought. It was unfamiliar
> territory.http://www.pointy-stick.com/blog/
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Re: form.as_table not displaying in template
Karan and Malcolm,
Thank you both - that was the problem. It is working great now!
On Apr 22, 12:20 pm, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Tue, 2008-04-22 at 09:02 -0700, Explore wrote:
> > Hi. I am new to django and I am trying to get a handle around the form
> > processing. I am using the svn trunk Revision: 7419 on Windows with
> > the development server. I have a views.py setup in my app that looks
> > like this:
>
> > form = TestingForm()
> > print form.as_table()
> > print form.as_table
> > return render_to_response('testing.html', { 'form':TestingForm })
>
> You're passing in a class to the template, rather than an instance of
> the form. Your need to pass the "form" variable via the dictionary, not
> the TestingForm class.
>
> Regards,
> Malcolm
>
> --
> I just got lost in thought. It was unfamiliar
> territory.http://www.pointy-stick.com/blog/
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Re: form.as_table not displaying in template
On Tue, 2008-04-22 at 09:02 -0700, Explore wrote:
> Hi. I am new to django and I am trying to get a handle around the form
> processing. I am using the svn trunk Revision: 7419 on Windows with
> the development server. I have a views.py setup in my app that looks
> like this:
>
> form = TestingForm()
> print form.as_table()
> print form.as_table
> return render_to_response('testing.html', { 'form':TestingForm })
You're passing in a class to the template, rather than an instance of
the form. Your need to pass the "form" variable via the dictionary, not
the TestingForm class.
Regards,
Malcolm
--
I just got lost in thought. It was unfamiliar territory.
http://www.pointy-stick.com/blog/
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Re: form.as_table not displaying in template
On Tue, Apr 22, 2008 at 12:02 PM, Explore <[EMAIL PROTECTED]>
wrote:
>
> Hi. I am new to django and I am trying to get a handle around the form
> processing. I am using the svn trunk Revision: 7419 on Windows with
> the development server. I have a views.py setup in my app that looks
> like this:
>
> form = TestingForm()
> print form.as_table()
> print form.as_table
> return render_to_response('testing.html', { 'form':TestingForm })
>
>
You are passing the TestingForm class into the template context instead of
the form instance you created. This should be:
return render_to_response('testing.html', { 'form': form })
Karen
>
> When I look at the output of this on my development server I see that
> form.as_table prints out the object info and form.as_table() prints
> out the tr tags for the form. So this looks like form.as_table() is
> working as it should when printing to the command line.
>
> However, when I try to use this in my template testing.html like this:
>
> test 1
>
>{{ form.as_table }}
>
>
> nothing prints out (maybe because it is trying to print the object
> instead of calling the method?) However, when I try:
>
> form.as_table() I get the following syntaxerror:
> Could not parse the remainder: '()' from 'form.as_table()'
>
> How can I use form.as_table in my template?
>
> I am new to both python and django so any help would be appreciated.
> Thanks very much.
> >
>
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Re: form.as_table not displaying in template
On 22-Apr-08, at 9:32 PM, Explore wrote:
> test 1
>
> {{ form.as_table }}
>
>
> nothing prints out (maybe because it is trying to print the object
> instead of calling the method?)
this is correct. It should work, but to diagnose you should post the
full template and the full view
--
regards
kg
http://lawgon.livejournal.com
http://nrcfosshelpline.in/code/
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form.as_table not displaying in template
Hi. I am new to django and I am trying to get a handle around the form
processing. I am using the svn trunk Revision: 7419 on Windows with
the development server. I have a views.py setup in my app that looks
like this:
form = TestingForm()
print form.as_table()
print form.as_table
return render_to_response('testing.html', { 'form':TestingForm })
When I look at the output of this on my development server I see that
form.as_table prints out the object info and form.as_table() prints
out the tr tags for the form. So this looks like form.as_table() is
working as it should when printing to the command line.
However, when I try to use this in my template testing.html like this:
test 1
{{ form.as_table }}
nothing prints out (maybe because it is trying to print the object
instead of calling the method?) However, when I try:
form.as_table() I get the following syntaxerror:
Could not parse the remainder: '()' from 'form.as_table()'
How can I use form.as_table in my template?
I am new to both python and django so any help would be appreciated.
Thanks very much.
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