Hello,
I need a view to return plain/text and I came up with the following code:
from django import http
from django.views.generic.base import TemplateResponseMixin
from django.views.generic.list import ListView
from django.views.generic.detail import DetailView
from django.conf import settings
class PlainTextResponseMixin(TemplateResponseMixin):
def render_to_response(self, context):
return super(PlainTextResponseMixin, self).render_to_response(
context,
content_type='plain/text; charset=%s' % settings.DEFAULT_CHARSET)
class PlainTextListView(PlainTextResponseMixin, ListView):
pass
class PlainTextDetailView(PlainTextResponseMixin, DetailView):
pass
meant to be used as follows (for example):
url(r'^v/(?P<slug>[-\w]+)\.bib$',
cache_page(PlainTextDetailView.as_view(
model=Publication,
template_name='academic/publication_detail.bib')),
name='academic_publishing_publication_detail_bibtex'),
Questions:
1) If I don't add `charset=%s' % settings.DEFAULT_CHARSET` the default
charset is not honored. Why?
2) could I do better or with less code? For instance, with
function-based views, all I had to do is pass a `{'mimetype':
'text/plain'}` kwarg to `object_list`
Thanks.
-F
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