Re: Upload new file to the uploaded file path

[Robin Lery]

It works perfectly! I am using it to upload in s3, and even for s3 it works
as it is supposed to. I am really grateful to you.

Thank you.

On Wed, Aug 5, 2015 at 4:37 PM, 'Tom Evans' via Django users <
django-users@googlegroups.com> wrote:

> On Tue, Aug 4, 2015 at 9:45 PM, Robin Lery  wrote:
> > I have a model for Video:
> >
> > class Video(models.Model):
> > title = models.CharField(max_length=75)
> > pubdate = models.DateTimeField(default=timezone.now)
> > original_video = models.FileField(upload_to=get_upload_file_name)
> > mp4_720 = models.FileField(upload_to=get_upload_file_name,blank=True,
> > null=True)
> > converted = models.BooleanField(default=False)
> >
> > And this is the view:
> >
> > def upload_video(request):
> > if request.POST:
> > form = VideoForm(request.POST, request.FILES)
> > if form.is_valid():
> > video = form.save(commit=False)
> > video.save()
> > convert_video.delay(video.id)
> > return HttpResponseRedirect('/')
> >
> > Lastly the tasks.py:
> >
> > def get_upload_file_name(video):
> > name = video.title
> > name = name+'.mp4'
> > return name
> >
> > from pyvid.settings import MEDIA_ROOT
> >
> > @app.task
> > def convert_video(video_id):
> > video = Video.objects.get(id=video_id)
> > video_path = str(MEDIA_ROOT)+'/'+str(video.original_video)
> > convert_video_name = get_upload_file_name(video)
> > cmd = 'ffmpeg -i %s -codec:v libx264 -profile:v baseline -preset slow
> > -b:v 250k -maxrate 250k -bufsize 500k -vf scale=-1:360 -threads 0
> -codec:a
> > libfdk_aac -movflags +faststart %s.mp4' % (video_path,
> convert_video_name)
> > subprocess.call(
> > cmd,
> > shell=True
> > )
> >
> > video.mp4_720 = convert_video_name
> > video.converted = True
> > video.save()
> >
> > The problem is, even though video.mp4_720 is directed to
> > upload_to=get_upload_file_name, its just taking the value of
> > convert_video_name file path (which is in the base directory of the
> project)
> > but not to the path applied.
> >
> > How do I upload the new converted file it to the uploaded path?
> >
>
> You asked this about 3 weeks ago as well (and replied to that email
> today), did this approach not work?:
>
> This is explained in the docs for FileField, you need to create a
> django.core.files.File subclass, and save() it on the FieldFile object
> that is returned when you access the FileField field on your model
> instance.
>
> Eg:
>
> from django.core.files import File
> fp = open('/path/to/file')
> myfile = File(fp)
> my_obj.mp4_720.save(name="", content=myfile)
>
>
> https://docs.djangoproject.com/en/1.8/ref/models/fields/#django.db.models.fields.files.FieldFile.save
>
> Cheers
>
> Tom
>
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> .
> For more options, visit https://groups.google.com/d/optout.
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Re: Upload new file to the uploaded file path

['Tom Evans' via Django users]

On Tue, Aug 4, 2015 at 9:45 PM, Robin Lery  wrote:
> I have a model for Video:
>
> class Video(models.Model):
> title = models.CharField(max_length=75)
> pubdate = models.DateTimeField(default=timezone.now)
> original_video = models.FileField(upload_to=get_upload_file_name)
> mp4_720 = models.FileField(upload_to=get_upload_file_name,blank=True,
> null=True)
> converted = models.BooleanField(default=False)
>
> And this is the view:
>
> def upload_video(request):
> if request.POST:
> form = VideoForm(request.POST, request.FILES)
> if form.is_valid():
> video = form.save(commit=False)
> video.save()
> convert_video.delay(video.id)
> return HttpResponseRedirect('/')
>
> Lastly the tasks.py:
>
> def get_upload_file_name(video):
> name = video.title
> name = name+'.mp4'
> return name
>
> from pyvid.settings import MEDIA_ROOT
>
> @app.task
> def convert_video(video_id):
> video = Video.objects.get(id=video_id)
> video_path = str(MEDIA_ROOT)+'/'+str(video.original_video)
> convert_video_name = get_upload_file_name(video)
> cmd = 'ffmpeg -i %s -codec:v libx264 -profile:v baseline -preset slow
> -b:v 250k -maxrate 250k -bufsize 500k -vf scale=-1:360 -threads 0 -codec:a
> libfdk_aac -movflags +faststart %s.mp4' % (video_path, convert_video_name)
> subprocess.call(
> cmd,
> shell=True
> )
>
> video.mp4_720 = convert_video_name
> video.converted = True
> video.save()
>
> The problem is, even though video.mp4_720 is directed to
> upload_to=get_upload_file_name, its just taking the value of
> convert_video_name file path (which is in the base directory of the project)
> but not to the path applied.
>
> How do I upload the new converted file it to the uploaded path?
>

You asked this about 3 weeks ago as well (and replied to that email
today), did this approach not work?:

This is explained in the docs for FileField, you need to create a
django.core.files.File subclass, and save() it on the FieldFile object
that is returned when you access the FileField field on your model
instance.

Eg:

from django.core.files import File
fp = open('/path/to/file')
myfile = File(fp)
my_obj.mp4_720.save(name="", content=myfile)

https://docs.djangoproject.com/en/1.8/ref/models/fields/#django.db.models.fields.files.FieldFile.save

Cheers

Tom

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Upload new file to the uploaded file path

[Robin Lery]

I have a model for Video:

class Video(models.Model):
title = models.CharField(max_length=75)
pubdate = models.DateTimeField(default=timezone.now)
original_video = models.FileField(upload_to=get_upload_file_name)
mp4_720 = models.FileField(upload_to=get_upload_file_name,blank=True,
null=True)
converted = models.BooleanField(default=False)

And this is the view:

def upload_video(request):
if request.POST:
form = VideoForm(request.POST, request.FILES)
if form.is_valid():
video = form.save(commit=False)
video.save()
convert_video.delay(video.id)
return HttpResponseRedirect('/')

Lastly the tasks.py:

def get_upload_file_name(video):
name = video.title
name = name+'.mp4'
return name

from pyvid.settings import MEDIA_ROOT

@app.task
def convert_video(video_id):
video = Video.objects.get(id=video_id)
video_path = str(MEDIA_ROOT)+'/'+str(video.original_video)
convert_video_name = get_upload_file_name(video)
cmd = 'ffmpeg -i %s -codec:v libx264 -profile:v baseline -preset slow
-b:v 250k -maxrate 250k -bufsize 500k -vf scale=-1:360 -threads 0 -codec:a
libfdk_aac -movflags +faststart %s.mp4' % (video_path, convert_video_name)
subprocess.call(
cmd,
shell=True
)

video.mp4_720 = convert_video_name
video.converted = True
video.save()

The problem is, even though video.mp4_720 is directed to
upload_to=get_upload_file_name,
its just taking the value of convert_video_name file path (which is in the
base directory of the project) but not to the path applied.

How do I upload the new converted file it to the uploaded path?

Thank you

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