Re: override render_to_response
I think the closest you could get to a painless implementation of what you need, for existing apps, could be to create a method named something like "render_to_json_response", that behave the way you want and have the appropriate "views" modules in each app import it as "render_to_response" (indeed commenting out the original import statements). --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: override render_to_response
On Mon, 2009-03-16 at 18:34 -0700, Preston Timmons wrote: > I am wondering if render_to_response is really the proper function you > are looking for. > > For instance, here is a simple view that returns json using > HttpResponse without need of a template: He was wanting to hijack the output from existing views in other applications for some reason, from what I gathered. Regards, Malcolm --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: override render_to_response
I am wondering if render_to_response is really the proper function you are looking for. For instance, here is a simple view that returns json using HttpResponse without need of a template: import simplejson from django.http import HttpResponse def output_json(request): data = [ dict(name='joe', weight=165), dict(name='roger', weight=130), ] return HttpResponse(simplejson.dumps(data), mimetype="application/ json") More docs on the HttpResponse is available here: http://docs.djangoproject.com/en/dev/ref/request-response/#django.http.HttpResponse.__init__ Preston --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: override render_to_response
On Mon, 2009-03-16 at 20:05 -0400, Malinka Rellikwodahs wrote: [...] > Unless I'm mistaken it should be fairly simple in this case to create > your own set of templates for each of the django apps you're using and > then have them output the data you need as json text instead of as > html Ooh ... that's a clever idea. Could even be done with a simple template tag, rendering everything in the context to json results. For the original poster: If youdo this, don't forget to use middleware to change the content type on the response. Regards, Malcolm --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: override render_to_response
On Mon, Mar 16, 2009 at 12:42, a b <dolittle...@gmail.com> wrote: > Hi, > > I'm building a one page app with no page refresh. > All the content is loaded as JSON dynamically and the UI is built using > javascript. > > I'm using external django apps and I need them to send back the context dict > as JSON instead > of rendering the html template. > > Is it possible to override render_to_response so all the apps using it will > respond with JSON without > actually touching the apps code? I don't want to create a middleware that > will modify the response because > then I have the overhead of rendering the html template. Unless I'm mistaken it should be fairly simple in this case to create your own set of templates for each of the django apps you're using and then have them output the data you need as json text instead of as html > Thanks > > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: override render_to_response
On Mon, 2009-03-16 at 18:42 +0200, a b wrote: > Hi, > > I'm building a one page app with no page refresh. > All the content is loaded as JSON dynamically and the UI is built > using javascript. > > I'm using external django apps and I need them to send back the > context dict as JSON instead > of rendering the html template. > > Is it possible to override render_to_response so all the apps using it > will respond with JSON without > actually touching the apps code? Not really, no. Monkey-patching like that is generally discouraged, in any case. Regards, Malcolm --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
override render_to_response
Hi, I'm building a one page app with no page refresh. All the content is loaded as JSON dynamically and the UI is built using javascript. I'm using external django apps and I need them to send back the context dict as JSON instead of rendering the html template. Is it possible to override render_to_response so all the apps using it will respond with JSON without actually touching the apps code? I don't want to create a middleware that will modify the response because then I have the overhead of rendering the html template. Thanks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
