Re: Proabably a simple python question but ...

[Richard Shebora]

This post from Graham Dumpleton (wrote mod_wsgi) goes into detail of
why that happens.

Extremely useful reading...
http://blog.dscpl.com.au/2010/03/improved-wsgi-script-for-use-with.html

Thanks,
Richard Shebora

On Tue, Jun 1, 2010 at 10:15 AM, Thomas Lionel Smets  wrote:
>
> If I put at the end of my settings.py file, the following code :
>
> 
> if (DEBUG):
>   print "Project name : " + PRJ_NAME
>   print "Root directory : " + ROOT_DIR
> 
>
> The lines are printed twice :
> 
> Project name : XXX
> Root directory : /Users/tsmets/Documents/python/XXX/site/
> Project name : XXX
> Root directory : /Users/tsmets/Documents/python/XXX/site/
> 
>
>
>
> --
> Thomas SMETS
> 1050 Brussels
> W : http://genealogy.tsmets.lautre.net
> skype : tsmets
>
> --
> You received this message because you are subscribed to the Google Groups
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Proabably a simple python question but ...

[Thomas Lionel Smets]

If I put at the end of my settings.py file, the following code :


if (DEBUG):
  print "Project name : " + PRJ_NAME
  print "Root directory : " + ROOT_DIR


The lines are printed twice :

Project name : XXX
Root directory : /Users/tsmets/Documents/python/XXX/site/
Project name : XXX
Root directory : /Users/tsmets/Documents/python/XXX/site/




--
Thomas SMETS
1050 Brussels
W : http://genealogy.tsmets.lautre.net
skype : tsmets

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Re: simple python question

[Thomas Kerpe]

results.append({'URL': '/feed/%s/show/%s' % (item.rss, item.rssfeed),})

On Thu, Aug 21, 2008 at 23:29, Bobby Roberts <[EMAIL PROTECTED]> wrote:

>
> hi.
>
> I'm trying to figure out how to dynamically replace things in a string
> as follows:
>
>
>results.append({'URL': '/feed/%s/show/%s' (%item.rss,
> %item.rssfeed),})
>
>
> I think i'm close but it's not the right syntax.  can anyone out there
> help?
>
>
> >
>

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simple python question

[Bobby Roberts]

hi.

I'm trying to figure out how to dynamically replace things in a string
as follows:


results.append({'URL': '/feed/%s/show/%s' (%item.rss,
%item.rssfeed),})


I think i'm close but it's not the right syntax.  can anyone out there
help?


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Re: Simple python question

[mrstone]

> What I'm doing is to load a model from a template.
> I have in a template something like this:
> {% block menu %}
> {% block rss %}
>
> I want to load "menu" and "rss", but I think that is too much work for
> now, I have no idea how to implement it and I probably won't do it.
> Thank you very much for your help.


Have you looked at template tags?
Check this tutorial: 
http://www.djangoproject.com/documentation/templates_python/
-Sten


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Re: Simple python question

[Grupo Django]

Thank you!
What I'm doing is to load a model from a template.
I have in a template something like this:
{% block menu %}
{% block rss %}

I want to load "menu" and "rss", but I think that is too much work for
now, I have no idea how to implement it and I probably won't do it.
Thank you very much for your help.




On 11 abr, 00:07, "Todd O'Bryan" <[EMAIL PROTECTED]> wrote:
> On Tue, 2007-04-10 at 18:03 -0500, Jeremy Dunck wrote:
> > On 4/10/07, Todd O'Bryan <[EMAIL PROTECTED]> wrote:
> > ...
> > > The key is that he wanted to use the string name of the class, not the
> > > class itself. Assuming that Foo is available (i.e., is local to the code
> > > you're running or has been imported), this should work:
>
> > > o = locals()['Foo']()
>
> > Oh.  In that case, you also want to make sure the string is trust-worthy.
>
> > I hope you're not creating a class instance from a request parameter. :)
>
> What he said! (I'm inclined to be so trusting...)


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Re: Simple python question

[Todd O'Bryan]

On Tue, 2007-04-10 at 18:03 -0500, Jeremy Dunck wrote:
> On 4/10/07, Todd O'Bryan <[EMAIL PROTECTED]> wrote:
> ...
> > The key is that he wanted to use the string name of the class, not the
> > class itself. Assuming that Foo is available (i.e., is local to the code
> > you're running or has been imported), this should work:
> >
> > o = locals()['Foo']()
> 
> Oh.  In that case, you also want to make sure the string is trust-worthy.
> 
> I hope you're not creating a class instance from a request parameter. :)

What he said! (I'm inclined to be so trusting...)



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Re: Simple python question

[Masida]

This should work:

class Foo:
def hello(self):
return "Hello World"

object = Foo()
print object.hello()


More information:
http://www.diveintopython.org/object_oriented_framework/index.html

Ciao,
- Matt


On Apr 11, 12:22 am, "Grupo Django" <[EMAIL PROTECTED]> wrote:
> I know this is not the right place for asking about python, but it's a
> simple question.
> I need to load an object given in a string. Example:
>
> #I have a class called foo
> class foo:
> def Hello():
> return "Hello World"
>
> object = 'foo'
>
> print object.Hello()
>
> Something like this.
> Is it possible in python? I think it is but I don't know how to do it.
>
> Thank you very much.


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Re: Simple python question

[Jeremy Dunck]

On 4/10/07, Todd O'Bryan <[EMAIL PROTECTED]> wrote:
...
> The key is that he wanted to use the string name of the class, not the
> class itself. Assuming that Foo is available (i.e., is local to the code
> you're running or has been imported), this should work:
>
> o = locals()['Foo']()

Oh.  In that case, you also want to make sure the string is trust-worthy.

I hope you're not creating a class instance from a request parameter. :)

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Re: Simple python question

[Todd O'Bryan]

On Tue, 2007-04-10 at 17:50 -0500, Jeremy Dunck wrote:
> On 4/10/07, Grupo Django <[EMAIL PROTECTED]> wrote:
> >
> > I know this is not the right place for asking about python, but it's a
> > simple question.
> > I need to load an object given in a string. Example:
> >
> > #I have a class called foo
> > class foo:
> > def Hello():
> > return "Hello World"
> >
> > object = 'foo'
> >
> > print object.Hello()
> 
> You probably don't really want to use the variable name "object",
> since that's also the name of Python's base class.
> 
> But just to follow your example, these lines (almost) do what you want:
> 
> object = foo()
> print object.Hello()
> 
> Now I'll rewrite it using better Python conventions and correct a small bug:
> 
> class Foo(object):
> def hello(self):
> return "Hello World"
> 
> o = Foo()
> print o.hello()
> 
The key is that he wanted to use the string name of the class, not the
class itself. Assuming that Foo is available (i.e., is local to the code
you're running or has been imported), this should work:

o = locals()['Foo']()

The locals() function returns a dictionary with all currently defined
names as keys mapped to their current values. Since 'Foo' is mapped to a
class, the code above gets the class and then makes an instance by
calling it like a function.

Todd


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Re: Simple python question

[Jeremy Dunck]

On 4/10/07, Grupo Django <[EMAIL PROTECTED]> wrote:
>
> I know this is not the right place for asking about python, but it's a
> simple question.
> I need to load an object given in a string. Example:
>
> #I have a class called foo
> class foo:
> def Hello():
> return "Hello World"
>
> object = 'foo'
>
> print object.Hello()

You probably don't really want to use the variable name "object",
since that's also the name of Python's base class.

But just to follow your example, these lines (almost) do what you want:

object = foo()
print object.Hello()

Now I'll rewrite it using better Python conventions and correct a small bug:

class Foo(object):
def hello(self):
return "Hello World"

o = Foo()
print o.hello()

Note:
  * upper-case class name
  * consistent indention (4 spaces)
  * lower-case method name.
  * method name takes explicit "self" argument, similar to implicit
"this" in other languages
  * avoid using built-in names in variables

To see a list of built-ins you should avoid stomping on, try this at
the python prompt:

dir(__builtins__)

To see more about python coding conventions, see PEP 8:
http://www.python.org/dev/peps/pep-0008/

To get a nice overview of Python, see this:
http://docs.python.org/tut/

If you're new to programming, this may be more helpful:
http://www.greenteapress.com/thinkpython/

If you're experienced with programming but new to Python, try this:
http://diveintopython.org

To get more help with Python (not Django) see python-help:
http://mail.python.org/mailman/listinfo/python-help

Welcome to Python.

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Simple python question

[Grupo Django]

I know this is not the right place for asking about python, but it's a
simple question.
I need to load an object given in a string. Example:

#I have a class called foo
class foo:
def Hello():
return "Hello World"

object = 'foo'

print object.Hello()

Something like this.
Is it possible in python? I think it is but I don't know how to do it.

Thank you very much.


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