Re: [EM] A Comparison of the Two Known Monotone, Clone Free Methods for Electing Uncovered Alternatives
fsimm...@pcc.edu wrote: To my knowledge, so far only two monotone, clone free, uncovered methods have been discovered. Both of them are ways of processing given monotone, clone free lists, such as a complete ordinal ballot or a list of alternatives in order of approval. I think Short Ranked Pairs also passes all these. To my knowledge, Short Ranked Pairs is like Ranked Pairs, except that you can only admit XY if that will retain the property that every pair of affirmed candidates have a beatpath of at most two steps between them. See http://lists.electorama.com/pipermail/election-methods-electorama.com/2004-November/014255.html . The definition of a short acyclic set of defeats was later changed, and the new definition is at http://lists.electorama.com/pipermail/election-methods-electorama.com/2004-November/014258.html I also guess you could make methods with properties like the above by constraining monotone cloneproof methods to the Landau set (whether by making something like Landau,Schulze or Landau/Schulze). I'm not sure of that, however, particularly not in the X/Y case since the elimination could lead to unwanted effects. Is one of the two methods you mention UncAAO generalized? Election-Methods mailing list - see http://electorama.com/em for list info
Re: [EM] A Comparison of the Two Known Monotone, Clone Free Methods for Electing Uncovered Alternatives
Where's a good place to find out more about the Landau set? Is it really possible to have a monotone, clone free method that is independent of non-Landau alternatives? It turns out that there are several versions of covering, depending on how ties are treated. All of them including the Landau set are the same when there are no pairwise ties (except with self). In July of this year I gave an example that shows that no decent deterministic monotone method can be independent from covered alternatives. The example applies to the Landau version of uncovered. So neither Ranked Pairs nor Beatpath nor Range restricted to Landau can monotone. Here's the example Suppose that we have a method that satisfies independence from non-Landau alternatives, and that gives greater winning probability to alternative B in this scenario 40 BCA 30 CAB 30 ABC than in this scenario 40 DBC 30 BCD 30 CDB as any decent method would. Then consider the scenario 40 DBCA 30 ABCD 30 CADB The Landau set is {A,B,C} and so by independence from non-Landau alternatives the winner is chosen according to the first scenario above. Now switch A and B in the second faction to get 40 DBCA 30 BACD 30 CADB . The Landau set becomes {D,B,C}.and so by independence from non-Landau alternatives the winner is chosen according to the second scenario above. In summary, solely by raising B relative to A , the winning probability of B decreased. For a deterministic method the probability of B would go from one to zero. Election-Methods mailing list - see http://electorama.com/em for list info
Re: [EM] A Comparison of the Two Known Monotone, Clone Free Methods for Electing Uncovered Alternatives
Hi Kristofer, you wrote: I think Short Ranked Pairs also passes all these. To my knowledge, Short Ranked Pairs is like Ranked Pairs, except that you can only admit XY if that will retain the property that every pair of affirmed candidates have a beatpath of at most two steps between them. See http://lists.electorama.com/pipermail/election-methods-electorama.com/2004-November/014255.html . The definition of a short acyclic set of defeats was later changed, and the new definition is at http://lists.electorama.com/pipermail/election-methods-electorama.com/2004-November/014258.html Thanks for unearthing this old idea of mine -- I had forgotten them completely already. Unfortunately, I fear Short Ranked Pairs might not be monotonic. One would habe to check. And I'm not sure your description of an algorithm for Short Ranked Pairs is valid -- after all, I only defined it abstractly by saying that one has to find the lexicographically maximal short acyclic set without giving an algorithm to find it. I propose to proceed as follows: Check how that lexicographically maximal short acyclic set can be found in the simpler case in which we define defeat strength as approval of defeating option. This will also allow us to compare the method to DMC since DMC is the result of applying ordinary Ranked Pairs with this definition of defeat strength, so applying Short Ranked Pairs to them should not be too much different. The resulting short acyclic set will contain all defeats from the approval winner to other options, but I don't see immediately whether one can somehow continue to lock in defeats similar to ordinary Ranked Pairs, skipping certain defeats that would destroy the defining properties of a short acyclic set. I somehow doubt that since that defining property is not that some configurations must not exist but than some configurations must exist. Anyway, in the case where defeat strength is approval of defeating option, all might be somewhat simpler. Jobst I also guess you could make methods with properties like the above by constraining monotone cloneproof methods to the Landau set (whether by making something like Landau,Schulze or Landau/Schulze). I'm not sure of that, however, particularly not in the X/Y case since the elimination could lead to unwanted effects. Is one of the two methods you mention UncAAO generalized? Election-Methods mailing list - see http://electorama.com/em for list info Election-Methods mailing list - see http://electorama.com/em for list info