Re: [EM] A Comparison of the Two Known Monotone, Clone Free Methods for Electing Uncovered Alternatives

2010-12-03 Thread Kristofer Munsterhjelm

fsimm...@pcc.edu wrote:

To my knowledge, so far only two monotone, clone free, uncovered methods have
been discovered.  Both of them are ways of processing given monotone, clone free
lists, such as a complete ordinal ballot or a list of alternatives in order of
approval.


I think Short Ranked Pairs also passes all these. To my knowledge, Short 
Ranked Pairs is like Ranked Pairs, except that you can only admit XY if 
that will retain the property that every pair of affirmed candidates 
have a beatpath of at most two steps between them.


See 
http://lists.electorama.com/pipermail/election-methods-electorama.com/2004-November/014255.html 
. The definition of a short acyclic set of defeats was later changed, 
and the new definition is at 
http://lists.electorama.com/pipermail/election-methods-electorama.com/2004-November/014258.html


I also guess you could make methods with properties like the above by 
constraining monotone cloneproof methods to the Landau set (whether by 
making something like Landau,Schulze or Landau/Schulze). I'm not sure of 
that, however, particularly not in the X/Y case since the elimination 
could lead to unwanted effects.


Is one of the two methods you mention UncAAO generalized?

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Re: [EM] A Comparison of the Two Known Monotone, Clone Free Methods for Electing Uncovered Alternatives

2010-12-03 Thread fsimmons
 Where's a good place to find out more about the Landau set? Is
 it really
 possible to have a monotone, clone free method that is
 independent of non-Landau
 alternatives?

It turns out that there are several versions of covering, depending on how ties
are treated.  All of them including the Landau set are the same when there are
no pairwise ties (except with self).

In July of this year I gave an example that shows that no decent deterministic
monotone method can be independent from covered alternatives.  The example
applies to the Landau version of uncovered.  So neither Ranked Pairs nor
Beatpath nor Range restricted to Landau can monotone.

Here's the example

Suppose that we have a method that satisfies independence from non-Landau
alternatives, and that gives 
greater winning probability to alternative B in this scenario

40 BCA
30 CAB
30 ABC

than in this scenario

40 DBC
30 BCD
30 CDB

as any decent method would.

Then consider the scenario

40 DBCA
30 ABCD
30 CADB

The Landau set is {A,B,C} and so by independence from non-Landau alternatives
the winner is chosen 
according to the first scenario above.

Now switch A and B in the second faction to get

40 DBCA
30 BACD
30 CADB .

The Landau set becomes  {D,B,C}.and so by independence from non-Landau
alternatives the winner is 
chosen according to the second scenario above.

In summary, solely by raising B relative to A , the winning probability of B
decreased.

For a deterministic method the probability of B would go from one to zero.


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Re: [EM] A Comparison of the Two Known Monotone, Clone Free Methods for Electing Uncovered Alternatives

2010-12-03 Thread Jobst Heitzig
Hi Kristofer,

you wrote:
 I think Short Ranked Pairs also passes all these. To my knowledge, Short
 Ranked Pairs is like Ranked Pairs, except that you can only admit XY if
 that will retain the property that every pair of affirmed candidates
 have a beatpath of at most two steps between them.
 
 See
 http://lists.electorama.com/pipermail/election-methods-electorama.com/2004-November/014255.html
 . The definition of a short acyclic set of defeats was later changed,
 and the new definition is at
 http://lists.electorama.com/pipermail/election-methods-electorama.com/2004-November/014258.html

Thanks for unearthing this old idea of mine -- I had forgotten them
completely already.

Unfortunately, I fear Short Ranked Pairs might not be monotonic. One
would habe to check. And I'm not sure your description of an algorithm
for Short Ranked Pairs is valid -- after all, I only defined it
abstractly by saying that one has to find the lexicographically maximal
short acyclic set without giving an algorithm to find it.

I propose to proceed as follows: Check how that lexicographically
maximal short acyclic set can be found in the simpler case in which we
define defeat strength as approval of defeating option. This will also
allow us to compare the method to DMC since DMC is the result of
applying ordinary Ranked Pairs with this definition of defeat strength,
so applying Short Ranked Pairs to them should not be too much different.

The resulting short acyclic set will contain all defeats from the
approval winner to other options, but I don't see immediately whether
one can somehow continue to lock in defeats similar to ordinary Ranked
Pairs, skipping certain defeats that would destroy the defining
properties of a short acyclic set. I somehow doubt that since that
defining property is not that some configurations must not exist but
than some configurations must exist. Anyway, in the case where defeat
strength is approval of defeating option, all might be somewhat simpler.

Jobst



 
 
 I also guess you could make methods with properties like the above by
 constraining monotone cloneproof methods to the Landau set (whether by
 making something like Landau,Schulze or Landau/Schulze). I'm not sure of
 that, however, particularly not in the X/Y case since the elimination
 could lead to unwanted effects.
 
 Is one of the two methods you mention UncAAO generalized?
 
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