Re: [EM] An interesting real election

2011-01-30 Thread Paul Kislanko
How is #1 not a Condorcet Winner, since #1 pairwise-beats every other
alternative?

  _  

From: election-methods-boun...@lists.electorama.com
[mailto:election-methods-boun...@lists.electorama.com] On Behalf Of Andrew
Myers
Sent: Saturday, January 29, 2011 4:41 PM
To: Election Methods Mailing List
Subject: [EM] An interesting real election


Here is an unusual case from a real poll run recently by a group using CIVS.
Usually there is a Condorcet winner, but not this time. Who should win?

Ranked pairs says #1, and ranks the six choices as shown. It only has to
reverse one preference. Schulze says #2, because it beats #6 by 15-11, and
#6 beats #1 by 14-13. So #2 has a 14-13 beatpath vs. #1. Hill's method
(Condorcet-IRV) picks #6 as the winner.

-- Andrew


 1.  2.  3.  4.  5.  6. 
1. 
 -   13  15  17  16  13 
2. 
 9   -   13  14  17  15 
3.   11  11  -   13  15  14 
4. 
 9   10  10  -   14  13 
5. 
 11  10  9   10  -   13 
6. 
 14  11  11  13  10  -  

Election-Methods mailing list - see http://electorama.com/em for list info


Re: [EM] An interesting real election

2011-01-30 Thread Paul Kislanko
Strike my previous reply... Didn't notice that #6 pairwise beat #1, but
pairwise lost to #2-#5.
 
Here's a case where I'd actually like to see instead of the pairwise matrix
the matrix that shows counts of votes for #1, #2, ... #5. In particular,
which is the Bucklin winner?
 
#6 loses or ties with every alternative except #1. 

  _  

From: election-methods-boun...@lists.electorama.com
[mailto:election-methods-boun...@lists.electorama.com] On Behalf Of Andrew
Myers
Sent: Saturday, January 29, 2011 4:41 PM
To: Election Methods Mailing List
Subject: [EM] An interesting real election


Here is an unusual case from a real poll run recently by a group using CIVS.
Usually there is a Condorcet winner, but not this time. Who should win?

Ranked pairs says #1, and ranks the six choices as shown. It only has to
reverse one preference. Schulze says #2, because it beats #6 by 15-11, and
#6 beats #1 by 14-13. So #2 has a 14-13 beatpath vs. #1. Hill's method
(Condorcet-IRV) picks #6 as the winner.

-- Andrew


 1.  2.  3.  4.  5.  6. 
1. 
 -   13  15  17  16  13 
2. 
 9   -   13  14  17  15 
3.   11  11  -   13  15  14 
4. 
 9   10  10  -   14  13 
5. 
 11  10  9   10  -   13 
6. 
 14  11  11  13  10  -  

Election-Methods mailing list - see http://electorama.com/em for list info


Re: [EM] An interesting real election

2011-01-30 Thread Andrew Myers

On 1/30/11 2:39 PM, Paul Kislanko wrote:
Strike my previous reply... Didn't notice that #6 pairwise beat #1, 
but pairwise lost to #2-#5.
Here's a case where I'd actually like to see instead of the pairwise 
matrix the matrix that shows counts of votes for #1, #2, ... #5. In 
particular, which is the Bucklin winner?

#6 loses or ties with every alternative except #1.
I've attached the ballots. Note that there were actually 15 candidates 
in this election; I just showed the action for the top 6 in my earlier 
mail.  Each ballot is one row, and position x shows the ranking that the 
voter assigned to candidate x. The listing uses the unranked numbers for 
the candidates, so the top 6 candidates are not candidates 1-6. There is 
also one more ballot in the listing below than for the matrix I sent 
earlier, but the same relatively interesting situation still pertains.


-- Andrew
8,6,5,3,15,7,13,12,1,2,12,12,12,4,14
15,10,7,4,9,3,14,13,1,8,5,12,2,11,6
15,6,4,3,12,2,6,11,11,11,1,13,7,11,14
3,4,13,9,2,1,15,10,9,9,14,12,9,11,11
15,12,2,7,14,8,13,6,3,1,12,12,6,4,5
4,14,5,15,6,7,14,14,14,14,14,2,1,14,3
4,6,8,2,14,9,15,13,12,12,7,3,5,12,1
4,15,3,8,15,7,15,15,2,1,5,15,15,15,6
15,15,15,15,15,15,15,15,1,1,15,15,2,15,2
15,5,6,2,15,14,14,14,14,3,1,14,4,14,14
15,15,15,2,15,15,15,5,4,15,15,15,1,15,3
15,12,4,11,11,2,14,13,11,11,11,1,11,11,3
7,11,4,3,10,6,12,15,5,2,13,9,1,14,8
2,5,6,7,15,8,14,12,3,1,10,11,4,13,9
15,14,14,14,2,14,1,14,14,14,14,14,14,14,14
7,12,12,4,14,2,15,1,6,3,12,13,12,5,12
9,11,2,1,8,4,10,5,3,6,12,13,14,7,15
15,5,12,4,12,12,13,12,2,12,3,12,1,12,14
1,15,15,15,15,15,15,15,15,1,15,15,15,15,15
1,8,3,7,4,7,15,15,2,15,15,15,5,15,15
4,15,15,1,15,15,15,15,3,2,15,15,15,15,15
15,8,10,10,6,1,14,14,4,2,5,11,3,14,7
13,4,2,6,14,5,15,10,9,1,11,8,7,12,3
3,4,14,2,14,6,14,14,7,15,1,14,5,14,8
15,10,10,2,14,10,14,10,2,1,10,10,2,10,10
15,15,15,15,3,15,15,15,15,15,15,15,1,2,15
6,6,8,6,3,7,15,1,3,11,9,15,12,15,7
15,15,14,3,2,10,15,4,13,1,15,15,11,15,12
10,3,4,15,14,5,8,13,1,9,6,11,2,12,7
14,15,15,15,10,8,15,15,3,2,1,15,15,15,15
9,11,2,3,12,4,15,1,5,6,13,14,8,7,10

Election-Methods mailing list - see http://electorama.com/em for list info


[EM] HB240 could lead to Approval voting in New Hampshire

2011-01-30 Thread Michael Rouse
HB240 is a New Hampshire bill to allow Approval voting for all state 
offices and Presidential primaries. Here is the link to the Slashdot story:


http://politics.slashdot.org/story/11/01/30/1911232/New-Hampshire-Bill-Could-Lead-To-Adoption-of-Approval-Voting#comments

I would be very happy to see this signed into law. :)

Mike Rouse



Election-Methods mailing list - see http://electorama.com/em for list info


Re: [EM] HB240 could lead to Approval voting in New Hampshire

2011-01-30 Thread Jan Kok
This is a HUGE deal!

I believe there will be a hearing on this bill at the NH State
Legislature this TUESDAY. Can anyone go and testify in its favor,
either this Tuesday, or possibly at some later hearings?

Thanks,
- Jan


On Sun, Jan 30, 2011 at 2:22 PM, Michael Rouse mrou...@mrouse.com wrote:
 HB240 is a New Hampshire bill to allow Approval voting for all state offices
 and Presidential primaries. Here is the link to the Slashdot story:

 http://politics.slashdot.org/story/11/01/30/1911232/New-Hampshire-Bill-Could-Lead-To-Adoption-of-Approval-Voting#comments

 I would be very happy to see this signed into law. :)

 Mike Rouse


 
 Election-Methods mailing list - see http://electorama.com/em for list info


Election-Methods mailing list - see http://electorama.com/em for list info


Re: [EM] An interesting real election

2011-01-30 Thread Aaron Armitage
1 has a path to 6 at least as strong as 6's path to 1, namely 136, at 15-11 
and 14-11. It
seems a little odd, to me at least, that 6's path to 1 should benefit 2 but not 
6 itself.
Starting from the top seems the only way of ensuring that the path that orders 
the two
candidates relative to each other is the one which actually contributes to the 
final outcome.

--- On Sat, 1/29/11, Andrew Myers an...@cs.cornell.edu wrote:

From: Andrew Myers an...@cs.cornell.edu
Subject: [EM] An interesting real election
To: Election Methods Mailing List election-meth...@electorama.com
Date: Saturday, January 29, 2011, 4:40 PM



  


  Here is an unusual case from a real poll run recently by a group
using CIVS. Usually there is a Condorcet winner, but not this time.
Who should win?



Ranked pairs says #1, and ranks the six choices as shown. It only
has to reverse one preference. Schulze says #2, because it beats #6
by 15-11, and #6 beats #1 by 14-13. So #2 has a 14-13 beatpath vs.
#1. Hill's method (Condorcet-IRV) picks #6 as the winner.



-- Andrew




  

   
   
  1.
  2.
  3.
  4.
  5.
  6.


  1. 

  
   
  -
  13
  15
  17
  16
  13


  2. 

  
   
  9
  -
  13
  14
  17
  15


  3.
   
  11
  11
  -
  13
  15
  14


  4. 

  
   
  9
  10
  10
  -
  14
  13


  5. 

  
   
  11
  10
  9
  10
  -
  13


  6. 

  
   
  14
  11
  11
  13
  10
  -

  

  

-Inline Attachment Follows-


Election-Methods mailing list - see http://electorama.com/em for list info



  
Election-Methods mailing list - see http://electorama.com/em for list info


Re: [EM] An interesting real election

2011-01-30 Thread Andrew Myers
It's a little tough to spot without the coloring that CIVS does, but #1 
loses pairwise to #6. This makes #2 win according to Schulze. As Markus 
points out, #2 is the candidate with the weakest pairwise defeat (13-9 
vs the 14-13 defeat of #1 by #6).


-- Andrew

On 1/30/11 2:33 PM, Paul Kislanko wrote:
How is #1 not a Condorcet Winner, since #1 pairwise-beats every other 
alternative?



*From:* election-methods-boun...@lists.electorama.com 
[mailto:election-methods-boun...@lists.electorama.com] *On Behalf Of 
*Andrew Myers

*Sent:* Saturday, January 29, 2011 4:41 PM
*To:* Election Methods Mailing List
*Subject:* [EM] An interesting real election

Here is an unusual case from a real poll run recently by a group using 
CIVS. Usually there is a Condorcet winner, but not this time. Who 
should win?


Ranked pairs says #1, and ranks the six choices as shown. It only has 
to reverse one preference. Schulze says #2, because it beats #6 by 
15-11, and #6 beats #1 by 14-13. So #2 has a 14-13 beatpath vs. #1. 
Hill's method (Condorcet-IRV) picks #6 as the winner.


-- Andrew

1.  2.  3.  4.  5.  6.
1.
-   13  15  17  16  13
2.
9   -   13  14  17  15
3.  11  11  -   13  15  14
4.
9   10  10  -   14  13
5.
11  10  9   10  -   13
6.
14  11  11  13  10  -


Election-Methods mailing list - see http://electorama.com/em for list info


Re: [EM] An interesting real election

2011-01-30 Thread Kevin Venzke
Hi Aaron,

--- En date de : Dim 30.1.11, Aaron Armitage eutychus_sl...@yahoo.com a 
écrit :
1 has a path to 6 at least as strong as 6's path to 1, namely 136, at 
15-11 and 14-11. It
seems a little odd, to me at least, that 6's path to 1 should benefit 2 
but not 6 itself.

When you say benefit do you mean elect or something more broad? It
seems to me election is the only meaningful benefit but of course only
one candidate can receive it.

Starting from the top seems the only way of ensuring that the path that 
orders the two
candidates relative to each other is the one which actually contributes 
to the final outcome.

I don't understand this. Are you saying the Schulze outcome in this
election is an example where these two things differed?

It's true that 1's path to 6 is better than the reverse, but the only
method that will never elect the loser of such a comparison is Schulze.

Kevin


  

Election-Methods mailing list - see http://electorama.com/em for list info