I have this (rather ugly) solution:
var i:uint = 0;
while(i xml.dog.length()){
if(xml.dog[i].attribute(id) != 2){
delete xml.dog[i];
} else {
++i;
}
}
My preferred way would be though, is doing it vise versa, i.e. add the
qualifying nodes instead of deleting not qualifying nodes:
var xml2:XML = pack /;
xml2.appendChild(xml.dog.(attribute(id) == 2));
Kenneth Kawamoto
http://www.materiaprima.co.uk/
On 01/12/2010 05:33, Mendelsohn, Michael wrote:
Sorry list! I didn't properly title that post! :-(
- MM
Hi list...
I want loop through to delete certain nodes, but can't figure out how to do it.
I've tried a conventional loop, for...in and for...each...in, and I must be
missing something.
pack
dog id=1/
dog/
dog id=2/
dog/
dog id=3/
/pack
I'd like to delete all instances of dog that don't have an @id, or @id==2.
Any thoughts?
Thanks,
- Michael M.
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