Re: [Flashcoders] pythagoras question
Merrill, Jason wrote: A simple solution could be to create a sprite to draw the line onto, and add a listener to the sprite to see if it was clicked on. Yes, but then you still have the problem that a two pixel line is not a great hit area for drawn line. That's why I asked the question to improve the experience by calculating the hit area myself. I can basically check if the click is within the given radius of the line. If so, recognize the click as clicked on the line. ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Re: [Flashcoders] pythagoras question
Hello, Yes, but then you still have the problem that a two pixel line is not a great hit area for drawn line. [...] - also you can draw 5 pixel transparent line. like this: http://bezier.ru/wp-content/uploads/2008/06/bezier.swf?demo=3 -- iv http://www.bezier.ru http://bezier.googlecode.com ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Re: [Flashcoders] pythagoras question
yeh - that's what i did On 30 Aug 2008, at 21:10, Merrill, Jason wrote: A simple solution could be to create a sprite to draw the line onto, and add a listener to the sprite to see if it was clicked on. Jason Merrill Bank of America Enterprise Technology Global Risk LLD Instructional Technology Media Join the Bank of America Flash Platform Developer Community Are you a Bank of America associate interested in innovative learning ideas and technologies? Check out our internal Innovative Learning Blog subscribe. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Weyert de Boer Sent: Saturday, August 30, 2008 8:19 AM To: Flash Coders List Subject: Re: [Flashcoders] pythagoras question May I ask a related question? How can I detected if a user has clicked on a line (or later a bezier path) ? I am having the starting and ending coordinates of this line and so also the distance. Now I am would like to check if the user has clicked within this line with/or without a specific radius. I am currently a bit clueless how to solve this problem. I know it's close what you have given earlier. Yours, Weyert ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Re: [Flashcoders] pythagoras question
Expand the idea of Jason and draw an invisible rectangle under your specific line. Assumed your line should be 30px long and your click radius should be 5xp var line:Sprite = new Sprite(); var g:Graphics = line.graphics; g.clear(); // hit radius *g.beginFill(0xff,0);* g.drawRect(0,-3,30,5); g.endFill(); // line itself *g.beginFill(0x00,1); g.drawRect(0,0,30,1);* g.endFill(); Notice that the hit radius has an alpha of zero and the line an alpha of 1. Does it work for you? Weyert de Boer schrieb: Merrill, Jason wrote: A simple solution could be to create a sprite to draw the line onto, and add a listener to the sprite to see if it was clicked on. Yes, but then you still have the problem that a two pixel line is not a great hit area for drawn line. That's why I asked the question to improve the experience by calculating the hit area myself. I can basically check if the click is within the given radius of the line. If so, recognize the click as clicked on the line. ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Re: [Flashcoders] pythagoras question
I think this is what you need. --- angle = Math.atan2( endY - startY, endX - startX ); trainX = vectorLength * Math.cos( angle ); trainY = vectorLength * Math.sin( angle ); --- Notes: 1. I'm using atan2(), not atan(). 2. The function atan2() takes (endY - startY) as its first parameter, and (endX - startX) as its second. It's easy to make the mistake of assigning them the other way round. Hope this helps. A On Thu, Aug 28, 2008 at 2:00 AM, allandt bik-elliott (thefieldcomic.com) [EMAIL PROTECTED] wrote: hi guys I'm doing something wrong in my pythagoras theorum but i'm not seeing what it is right now i'm trying to find out the coordinates for a point on a line. I know the start x, end x, start y, end y, c length for the line and i know how far along c the point should be (call it vector length) but i'm a little stumped as to where to go from there the psuedo code for what i've been trying is vector x = start x / end x vector y = start y / end y train x = (vector x * vector length) + start x train y = (vector x * vector length) + start y I think i have my maths very wrong here - hope you guys can help a ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Re: [Flashcoders] pythagoras question
May I ask a related question? How can I detected if a user has clicked on a line (or later a bezier path) ? I am having the starting and ending coordinates of this line and so also the distance. Now I am would like to check if the user has clicked within this line with/or without a specific radius. I am currently a bit clueless how to solve this problem. I know it's close what you have given earlier. Yours, Weyert ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Re: [Flashcoders] pythagoras question
Let's call the position of the mouse click on the stage (clickedX, clickedY) The starting coordinates are (startX, startY) The ending coordinates are (endX , endY) The general equation of your line, for any variables X and Y, is: Y == (X - startX) * (endY - startY) / (endX - startX) So when the user clicks on the stage, the values of clickedX and clickedY would need to satisfy the following equation: clickedY == (clickedX - startX) * (endY - startY) / (endX - startX) If this is true for clickedX and clickedY then that means the click fell on the line. Of course you would probably have to provide a bit of an error margin because you can't accurately evaluate the equality (==) of real numbers. A On Sat, Aug 30, 2008 at 9:18 PM, Weyert de Boer [EMAIL PROTECTED] wrote: May I ask a related question? How can I detected if a user has clicked on a line (or later a bezier path) ? I am having the starting and ending coordinates of this line and so also the distance. Now I am would like to check if the user has clicked within this line with/or without a specific radius. I am currently a bit clueless how to solve this problem. I know it's close what you have given earlier. Yours, Weyert ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
RE: [Flashcoders] pythagoras question
A simple solution could be to create a sprite to draw the line onto, and add a listener to the sprite to see if it was clicked on. Jason Merrill Bank of America Enterprise Technology Global Risk LLD Instructional Technology Media Join the Bank of America Flash Platform Developer Community Are you a Bank of America associate interested in innovative learning ideas and technologies? Check out our internal Innovative Learning Blog subscribe. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Weyert de Boer Sent: Saturday, August 30, 2008 8:19 AM To: Flash Coders List Subject: Re: [Flashcoders] pythagoras question May I ask a related question? How can I detected if a user has clicked on a line (or later a bezier path) ? I am having the starting and ending coordinates of this line and so also the distance. Now I am would like to check if the user has clicked within this line with/or without a specific radius. I am currently a bit clueless how to solve this problem. I know it's close what you have given earlier. Yours, Weyert ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Re: [Flashcoders] pythagoras question
Hi, I don't think pythagoras is involved here. try: factor = vectorLength/c; coordX = startX + (endX-startX)*factor; coordY = startY + (endY-startY)*factor; greetz JC On Wed, Aug 27, 2008 at 7:00 PM, allandt bik-elliott (thefieldcomic.com) [EMAIL PROTECTED] wrote: hi guys I'm doing something wrong in my pythagoras theorum but i'm not seeing what it is right now i'm trying to find out the coordinates for a point on a line. I know the start x, end x, start y, end y, c length for the line and i know how far along c the point should be (call it vector length) but i'm a little stumped as to where to go from there the psuedo code for what i've been trying is vector x = start x / end x vector y = start y / end y train x = (vector x * vector length) + start x train y = (vector x * vector length) + start y I think i have my maths very wrong here - hope you guys can help a ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
RE: [Flashcoders] pythagoras question
It sounds to me like your trying to find the x,y coordinates along a line. If this is the case then: M = (starty-endy)/(startx-endx) and B = -startx + starty Then Y = m*x + b where x is the current x location of the train and y will be the y-coordinate of the train. I hope this helps. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of allandt bik-elliott (thefieldcomic.com) Sent: Wednesday, August 27, 2008 12:00 PM To: Flash Coders List Subject: [Flashcoders] pythagoras question hi guys I'm doing something wrong in my pythagoras theorum but i'm not seeing what it is right now i'm trying to find out the coordinates for a point on a line. I know the start x, end x, start y, end y, c length for the line and i know how far along c the point should be (call it vector length) but i'm a little stumped as to where to go from there the psuedo code for what i've been trying is vector x = start x / end x vector y = start y / end y train x = (vector x * vector length) + start x train y = (vector x * vector length) + start y I think i have my maths very wrong here - hope you guys can help a ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
RE: [Flashcoders] pythagoras question
Why not just use Point.polar()? That would do exactly what it seems you are describing. Jason Merrill Bank of America Enterprise Technology Global Risk LLD Instructional Technology Media Join the Bank of America Flash Platform Developer Community Are you a Bank of America associate interested in innovative learning ideas and technologies? Check out our internal Innovative Learning Blog subscribe. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of allandt bik-elliott (thefieldcomic.com) Sent: Wednesday, August 27, 2008 1:00 PM To: Flash Coders List Subject: [Flashcoders] pythagoras question hi guys I'm doing something wrong in my pythagoras theorum but i'm not seeing what it is right now i'm trying to find out the coordinates for a point on a line. I know the start x, end x, start y, end y, c length for the line and i know how far along c the point should be (call it vector length) but i'm a little stumped as to where to go from there the psuedo code for what i've been trying is vector x = start x / end x vector y = start y / end y train x = (vector x * vector length) + start x train y = (vector x * vector length) + start y I think i have my maths very wrong here - hope you guys can help a ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders ___ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
