RE: [flexcoders] Re: e4x XML question - possible bug?

2006-02-10 Thread Gordon Smith 
I haven't tried it, but I think you should be able to use predicate
filtering with a variable.

XML and XMLList instances have child(name) and attribute(name) methods
for accessing a child element or an attribute whose name may not be
known until runtime. In other words,

x.employee.(name == McGee)

should be the same as

x.employee.(child(name) == McGee)

so instead of

x.employee.([whichProperty] == whichValue)

try

x.employee.(child(whichProperty) == whichValue)

- Gordon


-Original Message-
From: flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] On
Behalf Of Matt Chotin
Sent: Thursday, February 09, 2006 11:27 PM
To: flexcoders@yahoogroups.com
Subject: RE: [flexcoders] Re: e4x XML question - possible bug?

I'm not sure the filtering predicate operator will work for a variable.
I think you're going to need to do this instead:

var matches:XMLList = new XMLList();
var i:int = 0;
for each (var emp:XML in x.employee)
{
  if (emp[testVar] == testValue)
  {
matches[i++] = emp;
  }
}

The e4x compiler is going to generate code similar to this, so I don't
think we're doing anything too inefficient here.

Matt

-Original Message-
From: flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] On
Behalf Of thunderstumpgesatwork
Sent: Thursday, February 09, 2006 9:41 AM
To: flexcoders@yahoogroups.com
Subject: [flexcoders] Re: e4x XML question - possible bug?

Good thought, and I saw this suggestion in another related post,
however this always returns an empty list.

Is this possibly a bug?

Do you know that this should in fact work? I have not seen any
documentation stating that it should or shouldn't.

thanks,
Thunder

--- In flexcoders@yahoogroups.com, Manish Jethani [EMAIL PROTECTED]
wrote:

 On 2/8/06, thunderstumpgesatwork [EMAIL PROTECTED] wrote:
 
  x.employee.(lastName == McGee) // nodes with lastName McGee
 
  I need to do this dynamically.. what if I don't know the element
name
  (the 'lastName' portion above) ? How can I substitute a String
  variable for the 'lastName' ?
 
 Try this:
 
  x.employee.([variable] == McGee)







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[flexcoders] Re: e4x XML question - possible bug?

2006-02-10 Thread thunderstumpgesatwork 
Dang! I thought for sure this would work... such a good idea.
Unfortunately with this syntax the compiler throws an error: 

Call to a possibly undefined method 'child'

Note the first thing I did was make sure I was in fact using an
XMLList variable, and that the child method was defined..

Darn... I guess for now its just going to take a custom filtering
function. Maybe someday later we can use the predicate filtering
syntax with a variable.

Thanks guys for trying!
Thunder

--- In flexcoders@yahoogroups.com, Gordon Smith [EMAIL PROTECTED] wrote:

 I haven't tried it, but I think you should be able to use predicate
 filtering with a variable.
 
 XML and XMLList instances have child(name) and attribute(name) methods
 for accessing a child element or an attribute whose name may not be
 known until runtime. In other words,
 
 x.employee.(name == McGee)
 
 should be the same as
 
 x.employee.(child(name) == McGee)
 
 so instead of
 
 x.employee.([whichProperty] == whichValue)
 
 try
 
 x.employee.(child(whichProperty) == whichValue)
 
 - Gordon
 
 
 -Original Message-
 From: flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] On
 Behalf Of Matt Chotin
 Sent: Thursday, February 09, 2006 11:27 PM
 To: flexcoders@yahoogroups.com
 Subject: RE: [flexcoders] Re: e4x XML question - possible bug?
 
 I'm not sure the filtering predicate operator will work for a variable.
 I think you're going to need to do this instead:
 
 var matches:XMLList = new XMLList();
 var i:int = 0;
 for each (var emp:XML in x.employee)
 {
   if (emp[testVar] == testValue)
   {
 matches[i++] = emp;
   }
 }
 
 The e4x compiler is going to generate code similar to this, so I don't
 think we're doing anything too inefficient here.
 
 Matt
 
 -Original Message-
 From: flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] On
 Behalf Of thunderstumpgesatwork
 Sent: Thursday, February 09, 2006 9:41 AM
 To: flexcoders@yahoogroups.com
 Subject: [flexcoders] Re: e4x XML question - possible bug?
 
 Good thought, and I saw this suggestion in another related post,
 however this always returns an empty list.
 
 Is this possibly a bug?
 
 Do you know that this should in fact work? I have not seen any
 documentation stating that it should or shouldn't.
 
 thanks,
 Thunder
 
 --- In flexcoders@yahoogroups.com, Manish Jethani manish.jethani@
 wrote:
 
  On 2/8/06, thunderstumpgesatwork thunder.stumpges@ wrote:
  
   x.employee.(lastName == McGee) // nodes with lastName McGee
  
   I need to do this dynamically.. what if I don't know the element
 name
   (the 'lastName' portion above) ? How can I substitute a String
   variable for the 'lastName' ?
  
  Try this:
  
   x.employee.([variable] == McGee)
 
 
 
 
 
 
 
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[flexcoders] Re: e4x XML question - possible bug?

2006-02-09 Thread thunderstumpgesatwork 
Good thought, and I saw this suggestion in another related post,
however this always returns an empty list.

Is this possibly a bug?

Do you know that this should in fact work? I have not seen any
documentation stating that it should or shouldn't.

thanks,
Thunder

--- In flexcoders@yahoogroups.com, Manish Jethani [EMAIL PROTECTED]
wrote:

 On 2/8/06, thunderstumpgesatwork [EMAIL PROTECTED] wrote:
 
  x.employee.(lastName == McGee) // nodes with lastName McGee
 
  I need to do this dynamically.. what if I don't know the element name
  (the 'lastName' portion above) ? How can I substitute a String
  variable for the 'lastName' ?
 
 Try this:
 
  x.employee.([variable] == McGee)







--
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FAQ: http://groups.yahoo.com/group/flexcoders/files/flexcodersFAQ.txt
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RE: [flexcoders] Re: e4x XML question - possible bug?

2006-02-09 Thread Matt Chotin 
I'm not sure the filtering predicate operator will work for a variable.
I think you're going to need to do this instead:

var matches:XMLList = new XMLList();
var i:int = 0;
for each (var emp:XML in x.employee)
{
  if (emp[testVar] == testValue)
  {
matches[i++] = emp;
  }
}

The e4x compiler is going to generate code similar to this, so I don't
think we're doing anything too inefficient here.

Matt

-Original Message-
From: flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] On
Behalf Of thunderstumpgesatwork
Sent: Thursday, February 09, 2006 9:41 AM
To: flexcoders@yahoogroups.com
Subject: [flexcoders] Re: e4x XML question - possible bug?

Good thought, and I saw this suggestion in another related post,
however this always returns an empty list.

Is this possibly a bug?

Do you know that this should in fact work? I have not seen any
documentation stating that it should or shouldn't.

thanks,
Thunder

--- In flexcoders@yahoogroups.com, Manish Jethani [EMAIL PROTECTED]
wrote:

 On 2/8/06, thunderstumpgesatwork [EMAIL PROTECTED] wrote:
 
  x.employee.(lastName == McGee) // nodes with lastName McGee
 
  I need to do this dynamically.. what if I don't know the element
name
  (the 'lastName' portion above) ? How can I substitute a String
  variable for the 'lastName' ?
 
 Try this:
 
  x.employee.([variable] == McGee)







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