Bash Script Help - File Names With Spaces
I have a collection of yearly top 100 Billboard mp3s in this format (all
one line - sorry if it wraps):
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028 Kenny
Loggins - This Is It.mp3
I want to create symbolic links to the top 30 in 1966-1969 in another
directory for easy migration to a flash card. Thus I invoked 'find' to
get a list (again, all one line):
find -E /archive/Multimedia/Audio/Music/Billboard Top USA Singles
-regex '.*19[6-9][0-9]-0[0-2][0-9].*'
(OK, I know this will only return the top 29)
'find' returns the complete filename as above:
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028 Kenny
Loggins - This Is It.mp3
Then I attempt to use 'basename' to extract the file name to a variable
which I can later pass to 'ln'. This seems to work:
basename /archive/Multimedia/Audio/Music/Billboard Top USA
Singles/1980-028 Kenny Loggins - This Is It.mp3
returns (all one line):
1980-028 Kenny Loggins - This Is It.mp3
which is what I would expect. However using it with 'find' give me this
type of unexpected result:
for i in `find -E /archive/Multimedia/Audio/Music/Billboard Top USA
Singles -regex '.*19[6-9][0-9]-0[1-2][0-9].*'`; do basename ${i};done
1980-028
Kenny
Loggins
-
This
Is
It.mp3
Why is this different? And more importantly, how can I capture the file
name to $i?
Thanks,
Drew
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Re: Bash Script Help - File Names With Spaces
Quoth Drew Tomlinson on Tuesday, 17 August 2010:
I have a collection of yearly top 100 Billboard mp3s in this format (all
one line - sorry if it wraps):
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028 Kenny
Loggins - This Is It.mp3
I want to create symbolic links to the top 30 in 1966-1969 in another
directory for easy migration to a flash card. Thus I invoked 'find' to
get a list (again, all one line):
find -E /archive/Multimedia/Audio/Music/Billboard Top USA Singles
-regex '.*19[6-9][0-9]-0[0-2][0-9].*'
(OK, I know this will only return the top 29)
'find' returns the complete filename as above:
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028 Kenny
Loggins - This Is It.mp3
Then I attempt to use 'basename' to extract the file name to a variable
which I can later pass to 'ln'. This seems to work:
basename /archive/Multimedia/Audio/Music/Billboard Top USA
Singles/1980-028 Kenny Loggins - This Is It.mp3
returns (all one line):
1980-028 Kenny Loggins - This Is It.mp3
which is what I would expect. However using it with 'find' give me this
type of unexpected result:
for i in `find -E /archive/Multimedia/Audio/Music/Billboard Top USA
Singles -regex '.*19[6-9][0-9]-0[1-2][0-9].*'`; do basename ${i};done
1980-028
Kenny
Loggins
-
This
Is
It.mp3
Why is this different? And more importantly, how can I capture the file
name to $i?
Try:
find -E ... | while read i; do; basename $i; done
When using back-ticks, all the output gets appended together,
space-separated. Then 'for' can't tell the difference between a space in
a filename and a delimiter. Using 'read' instead preserves line
boundaries.
Thanks,
Drew
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Re: Bash Script Help - File Names With Spaces -- SOLVED
On 8/17/2010 7:47 AM, Drew Tomlinson wrote:
I have a collection of yearly top 100 Billboard mp3s in this format
(all one line - sorry if it wraps):
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028
Kenny Loggins - This Is It.mp3
I want to create symbolic links to the top 30 in 1966-1969 in another
directory for easy migration to a flash card. Thus I invoked 'find' to
get a list (again, all one line):
find -E /archive/Multimedia/Audio/Music/Billboard Top USA Singles
-regex '.*19[6-9][0-9]-0[0-2][0-9].*'
(OK, I know this will only return the top 29)
'find' returns the complete filename as above:
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028
Kenny Loggins - This Is It.mp3
Then I attempt to use 'basename' to extract the file name to a
variable which I can later pass to 'ln'. This seems to work:
basename /archive/Multimedia/Audio/Music/Billboard Top USA
Singles/1980-028 Kenny Loggins - This Is It.mp3
returns (all one line):
1980-028 Kenny Loggins - This Is It.mp3
which is what I would expect. However using it with 'find' give me
this type of unexpected result:
for i in `find -E /archive/Multimedia/Audio/Music/Billboard Top USA
Singles -regex '.*19[6-9][0-9]-0[1-2][0-9].*'`; do basename ${i};done
1980-028
Kenny
Loggins
-
This
Is
It.mp3
Why is this different? And more importantly, how can I capture the
file name to $i?
It finally occurred to me that I needed the shell to see a new line as
the delimiter and not whitespace. Then a simple search revealed my answer:
O=$IFS
IFS=$(echo -en \n\b)
do stuff
IFS=$O
Sorry for the noise.
Drew
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Re: Bash Script Help - File Names With Spaces
On 8/17/2010 8:22 AM, Chip Camden wrote:
Quoth Drew Tomlinson on Tuesday, 17 August 2010:
I have a collection of yearly top 100 Billboard mp3s in this format (all
one line - sorry if it wraps):
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028 Kenny
Loggins - This Is It.mp3
I want to create symbolic links to the top 30 in 1966-1969 in another
directory for easy migration to a flash card. Thus I invoked 'find' to
get a list (again, all one line):
find -E /archive/Multimedia/Audio/Music/Billboard Top USA Singles
-regex '.*19[6-9][0-9]-0[0-2][0-9].*'
(OK, I know this will only return the top 29)
'find' returns the complete filename as above:
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028 Kenny
Loggins - This Is It.mp3
Then I attempt to use 'basename' to extract the file name to a variable
which I can later pass to 'ln'. This seems to work:
basename /archive/Multimedia/Audio/Music/Billboard Top USA
Singles/1980-028 Kenny Loggins - This Is It.mp3
returns (all one line):
1980-028 Kenny Loggins - This Is It.mp3
which is what I would expect. However using it with 'find' give me this
type of unexpected result:
for i in `find -E /archive/Multimedia/Audio/Music/Billboard Top USA
Singles -regex '.*19[6-9][0-9]-0[1-2][0-9].*'`; do basename ${i};done
1980-028
Kenny
Loggins
-
This
Is
It.mp3
Why is this different? And more importantly, how can I capture the file
name to $i?
Try:
find -E ... | while read i; do; basename $i; done
When using back-ticks, all the output gets appended together,
space-separated. Then 'for' can't tell the difference between a space in
a filename and a delimiter. Using 'read' instead preserves line
boundaries.
Thanks for your reply. I like this better than manipulating $IFS
because then I don't have to set it back.
Cheers,
Drew
--
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learn card magic secrets for free!
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Re: Bash Script Help - File Names With Spaces
Am Dienstag, den 17.08.2010, 08:22 -0700 schrieb Chip Camden: find -E ... | while read i; do; basename $i; done The semicolon behind do isn't necessary. -- Timm ___ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to freebsd-questions-unsubscr...@freebsd.org
Re: Bash Script Help - File Names With Spaces
On Tue, 17 Aug 2010 07:47:25 -0700, Drew Tomlinson d...@mykitchentable.net said: D Then I attempt to use 'basename' to extract the file name to a variable D which I can later pass to 'ln'. This seems to work: D basename /archive/Multimedia/Audio/Music/Billboard Top USA D Singles/1980-028 Kenny Loggins - This Is It.mp3 This is a subset of a larger problem: getting the last field from a set of delimited records which may not all have the same number of fields. I've used this when I needed basenames for ~500,000 files: find . regex-or-print-or-whatever | rev | cut -f1 -d/ | rev For dirnames: find . regex-or-print-or-whatever | rev | cut -f2- -d/ | rev | sort -u -- Karl Vogel I don't speak for the USAF or my company When I'm feeling down, I like to whistle. It makes the neighbor's dog run to the end of his chain and gag himself.--unknown ___ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to freebsd-questions-unsubscr...@freebsd.org
Re: Bash Script Help - File Names With Spaces -- SOLVED
Drew Tomlinson d...@mykitchentable.net writes:
It finally occurred to me that I needed the shell to see a new line as
the delimiter and not whitespace. Then a simple search revealed my
answer:
O=$IFS
IFS=$(echo -en \n\b)
do stuff
IFS=$O
Old IFS value can be preserved by using `local' keyword or (...) braces, too.
It's a bit better than polluting global scope with temporary variable.
$ echo -n $IFS | (vis -w; echo)
\040\^I\^J
$ for i in $(find . -type f); do echo $i; done
./My
Long
File
Name
./Another
File
$ f() { local IFS=; eval $@; }
$ f 'for i in $(find . -type f); do echo $i; done'
./My Long File Name
./Another File
$ (IFS=; for i in $(find . -type f); do echo $i; done)
./My Long File Name
./Another File
$ echo -n $IFS | (vis -w; echo)
\040\^I\^J
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