Re: simple sh scripting. How to put a result of a command to avariable?

2003-08-14 Thread Constantine
Michael Conlen wrote:

Constantine wrote:

I am writing a script, which involves unzipping some files. I would 
have to unzip 4 different zip-files from some directory, and I would 
need to unzip them to the directory, which would have the same name 
in it as the original zip-file, i.e. I would like to run something 
like "ls *.zip", have each file name recorded in some variable, and 
do a loop like "unzip $filename[$i] -d $filename[$i].unzipped/". Can 
someone help me with the code? How can I put the results of a command 
to a variable? 
If I understand you properly I think the following would do what you want

#!/bin/sh
for i in `ls *.zip`
do
   unzip ${i} -d ${i}.unzipped
done 
Thank you very much indeed! Seems just what I wanted. But can I save the 
archive names in an array for further manipulation? Also, how can I type 
that apostrophe ` from my keyboard?

Cheers,
Constantine.
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Re: simple sh scripting. How to put a result of a command to avariable?

2003-08-14 Thread Michael Conlen
Constantine wrote:

Hello!

I am writing a script, which involves unzipping some files. I would 
have to unzip 4 different zip-files from some directory, and I would 
need to unzip them to the directory, which would have the same name in 
it as the original zip-file, i.e. I would like to run something like 
"ls *.zip", have each file name recorded in some variable, and do a 
loop like "unzip $filename[$i] -d $filename[$i].unzipped/". Can 
someone help me with the code? How can I put the results of a command 
to a variable? 


If I understand you properly I think the following would do what you want

#!/bin/sh
for i in `ls *.zip`
do
   unzip ${i} -d ${i}.unzipped
done


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Re: simple sh scripting. How to put a result of a command to avariable?

2003-08-14 Thread Michal F. Hanula
On Mon, Aug 11, 2003 at 06:17:25PM -0400, Michael Conlen wrote:
> #!/bin/sh
> for i in `ls *.zip`
Useless use of backticks --- what about
for i in *.zip
?
> do
>unzip ${i} -d ${i}.unzipped
> done

-- 
What do you care what other people think?


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Description: PGP signature


Re: simple sh scripting. How to put a result of a command to avariable?

2003-08-11 Thread Joshua Oreman
On Mon, Aug 11, 2003 at 06:35:17PM -0400 or thereabouts, Constantine wrote:
> Michael Conlen wrote:
> 
> >Constantine wrote:
> >
> >>I am writing a script, which involves unzipping some files. I would 
> >>have to unzip 4 different zip-files from some directory, and I would 
> >>need to unzip them to the directory, which would have the same name 
> >>in it as the original zip-file, i.e. I would like to run something 
> >>like "ls *.zip", have each file name recorded in some variable, and 
> >>do a loop like "unzip $filename[$i] -d $filename[$i].unzipped/". Can 
> >>someone help me with the code? How can I put the results of a command 
> >>to a variable? 
> >
> >If I understand you properly I think the following would do what you want
> >
> >#!/bin/sh
> >for i in `ls *.zip`
> >do
> >   unzip ${i} -d ${i}.unzipped
> >done 
> 
> Thank you very much indeed! Seems just what I wanted. But can I save the 
> archive names in an array for further manipulation? Also, how can I type 
> that apostrophe ` from my keyboard?

For the array I think you do need bash. I'm not familiar with arrays in shell;
someone else may be able to help you there.

As far as the backquote (`), it seems you answered your own question by typing
it into your email. (But the backquote is on the tilde (~) key, if you don't
push shift).

-- Josh

> 
> Cheers,
> Constantine.
> 
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