The following code should return the base2 logarithm of 64 (ie 6)
double d = log(64.0) / log(2.0);
int i = (int)d;
cout << i;
And indeed it does output "6". However, if you attempt to cast it on the same
line, then it returns 5.
int i2 = (int)( log(64.0) / log(2.0) );
int i3 = static_cast<int>( log(64.0) / log(2.0) );
cout << i2 << i3;
This outputs "55" instead of the expected "66". Visual Studio 2003 outputs
"66".
gcc 4.1.0, Suse Linux 10.1.
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Summary: log expression returns different results when casting
Product: gcc
Version: 4.1.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: brad_atcheson at yahoo dot ca
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=29597
