https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66425
Christian Groessler <groessler_christian at yahoo dot de> changed:
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--- Comment #62 from Christian Groessler <groessler_christian at yahoo dot de>
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(In reply to Segher Boessenkool from comment #60)
> So you want to not warn for some (just *some*) explicitly unused cases, and
> do
> warn for other explicitly unused cases, and all implicitly unused cases?
> While
> the author of the code explicitly asked for a warning message to be emitted
> in
> all such cases: "The 'warn_unused_result' attribute causes a warning to be
> emitted if a caller of the function with this attribute does not use its
> return
> value."
Yes! I'm write()ing to a pipe a small amount of data (< page size), and anyway
don't know how to continue if the write() fails. It would be noticed at the
other end.
(void)write(....) doesn't suppress the warning. Annoying...
