[Bug analyzer/101713] -Wanalyzer-malloc-leak false positive with GNU coreutils hash table code
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=101713 Eric Gallager changed: What|Removed |Added Ever confirmed|0 |1 Status|UNCONFIRMED |NEW Last reconfirmed||2024-04-02 --- Comment #3 from Eric Gallager --- Confirming due to the link to it from gnulib's manywarnings.m4
[Bug analyzer/101713] -Wanalyzer-malloc-leak false positive with GNU coreutils hash table code
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=101713 --- Comment #2 from eggert at cs dot ucla.edu --- (In reply to David Malcolm from comment #1) > Am I right in thinking that there's a cast somewhere inside the hash table > code that at some point casts away the const from the pointer and frees it? Yes there's a cast to void *, but no it doesn't free the storage. Instead, the caller later is supposed to take ownership of the storage if it removes the item from the hashtable, e.g., the caller can later do this: void *entry = hash_remove (pattern); free (entry); where ENTRY will be the same pointer as STR in the sample code I gave earlier. This means there's no leak in addpat per se.
[Bug analyzer/101713] -Wanalyzer-malloc-leak false positive with GNU coreutils hash table code
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=101713 --- Comment #1 from David Malcolm --- Thanks for reporting this issue. The analyzer sees that "str" is passed to hash_insert as a const pointer, and therefore assumes that hash_insert cannot free it, that hash_insert is merely borrowing a pointer to str, rather than taking ownership. Am I right in thinking that there's a cast somewhere inside the hash table code that at some point casts away the const from the pointer and frees it?