[Bug c++/38055] key for compilation -Wconversion
--- Comment #1 from manu at gcc dot gnu dot org 2009-01-24 01:40 --- Quoting the FAQ at http://gcc.gnu.org/wiki/NewWconversion#faq Why Wconversion is not enabled by -Wall or at least by -Wextra? Implicit conversions are very common in C. This tied with the fact that there is no data-flow in front-ends (see next question) results in hard to avoid warnings for perfectly working and valid code. Wconversion is designed for a niche of uses (security audits, porting 32 bit code to 64 bit, etc.) where the programmer is willing to accept and workaround invalid warnings. Therefore, it shouldn't be enabled if it is not explicitly requested. -- manu at gcc dot gnu dot org changed: What|Removed |Added CC||manu at gcc dot gnu dot org Status|UNCONFIRMED |RESOLVED Resolution||INVALID http://gcc.gnu.org/bugzilla/show_bug.cgi?id=38055
[Bug c++/38055] key for compilation -Wconversion
--- Comment #2 from lisp2d at lisp2d dot net 2009-01-24 06:00 ---
The niche is selected incorrectly. Basically the considerable quantity of
errors of programming is linked to implicit type conversion.
void insert(char*,char,unsigned int){..}
insert(..,..,size_t);
Example
double d = 1.0;
int i;
i = d;
correctly and necessary to write so:
double d = 1.0;
int i;
i = (int)d;
In the program text this obvious conversion will be visible.
--
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=38055
