[Bug fortran/92639] Error: Integer too big for its kind at (1)
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=92639 --- Comment #4 from Steve Kargl --- On Wed, Mar 01, 2023 at 05:51:29PM +, cessenat at gmail dot com wrote: > https://gcc.gnu.org/bugzilla/show_bug.cgi?id=92639 > > --- Comment #2 from Olivier Cessenat --- > integer(kind=4) valid range is -2147483648_4 to +2147483647_4. > So I consider this is a gfortran bug. > > Moreover, if -2147483648_4 is considered out of range, why > -2147483647_4 - 1_4 is not ? Constant elimination makes it evaluated to > -2147483648_4. > > I disagree with the term "there are no negative integers" > [-2147483648_4 is equal to +2147483648_4] exceeds huge(1) % cat a.f90 print *, huge(1) end % gfortran -o z a.f90 && ./z 2147483647 I've already explained the issue. But, I'll go over it one more time. -2147483648_4 is parsed as unary minus operator and an operand of 2147483648_4. 2147483648_4 exceeds huge(1). Fortunately, gfortran can save you, and the error message even tells you. 1 | i = -2147483648_4 | 1 Error: Integer too big for its kind at (1). This check can be disabled with the option '-fno-range-check' So, let me amend the quote above "there are no negative integer-literal constants."
[Bug fortran/92639] Error: Integer too big for its kind at (1)
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=92639 Jerry DeLisle changed: What|Removed |Added CC||jvdelisle at gcc dot gnu.org --- Comment #3 from Jerry DeLisle --- Please observe: program demonstrate integer :: i i = huge(i) print *, i i= -huge(i) print *, i end program $ gfc demonstrate.f90 $ ./a.out 2147483647 -2147483647 This is by the fortran standard definition for a 32 bit integer. You cannot represent 2147483648 in 32 bits because you need bit 32 to represent the sign of the value. How other compilers are storing the sign I can not speak to.
[Bug fortran/92639] Error: Integer too big for its kind at (1)
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=92639 --- Comment #2 from Olivier Cessenat --- integer(kind=4) valid range is -2147483648_4 to +2147483647_4. So I consider this is a gfortran bug. Moreover, if -2147483648_4 is considered out of range, why -2147483647_4 - 1_4 is not ? Constant elimination makes it evaluated to -2147483648_4. I disagree with the term "there are no negative integers" [-2147483648_4 is equal to +2147483648_4] Other compilers, such as aocc, nvfortran, ifort, oneapi are OK with that Thanks
[Bug fortran/92639] Error: Integer too big for its kind at (1)
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=92639 kargl at gcc dot gnu.org changed: What|Removed |Added Status|UNCONFIRMED |RESOLVED CC||kargl at gcc dot gnu.org Resolution|--- |INVALID --- Comment #1 from kargl at gcc dot gnu.org --- (In reply to Shubham Narlawar from comment #0) > For below testcase, I ran on godbolt.org GFORTRAN trunk. Here are some > observations - > > gfortran throws an error for BGE intrinsic when the value of one of > parameter is -2147483648 which should not be according to permissible range > of BGE, the maximum range for default kind is (-2147483648, 2147483647) > > derived as -2^31 to 2^31 - 1 > > whereas x86-64 ifort 19.0.0 (Intel's fortran compiler) gives output without > error. > > > TESTCASE--- > > subroutine print_pass_fail(expected, actual) > implicit none > logical :: actual, expected >if ( actual .eqv. expected )then > print *, "PASS" >else > print *, "FAIL" > end if > end subroutine print_pass_fail > program bge_test_base > implicit none > logical :: index > index = BGE(127, -2147483648); > !print *, index > call print_pass_fail (.true.,index) > end program There are no negative integers. There are integers and unary minus operator. This means that "-2147483648" is parse as "unary minus 2147483648". 2147483648 is too big for its kind.
