[Bug libstdc++/65290] New: [C++11] operator new(std::size_t, const std::nothrow_t&) should call operator new(std::size_t)

[kariya_mitsuru at hotmail dot com]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=65290

            Bug ID: 65290
           Summary: [C++11] operator new(std::size_t, const
                    std::nothrow_t&) should call operator new(std::size_t)
           Product: gcc
           Version: 5.0
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: libstdc++
          Assignee: unassigned at gcc dot gnu.org
          Reporter: kariya_mitsuru at hotmail dot com

Created attachment 34930
  --> https://gcc.gnu.org/bugzilla/attachment.cgi?id=34930&action=edit
g++ -v

Please see the sample code below.

========================== sample code ==========================
#include <iostream>
#include <new>

void* operator new(std::size_t)
{
    throw std::bad_alloc();
}

int main()
{
    int* p = new(std::nothrow) int;
    std::cout << std::boolalpha << (p == nullptr) << std::endl;
    delete p;
}
========================== sample code ==========================

========================== output ==========================
false
========================== output ==========================
cf. http://melpon.org/wandbox/permlink/LTq0gqETftUEvWK0


The C++11 standard 18.6.1.1[new.delete.single]/p.8 says,

  Default behavior: Calls operator new(size). If the call returns normally,
returns the result of that call. Otherwise, returns a null pointer.

This description was changed in C++11(see LWG DR206).

cf. http://cplusplus.github.io/LWG/lwg-defects.html#206


So, I think that the sample code above should output
========================== output ==========================
true
========================== output ==========================


I am not sure whether operator new(std::size_t, const std::nothrow_t&) should
call operator new(std::size_t) in C++03 mode.