[Bug preprocessor/35610] Pasting foo and ( does not give a valid preprocessing token

[pinskia at gcc dot gnu dot org]

--- Comment #1 from pinskia at gcc dot gnu dot org  2008-03-16 22:46 ---
Yes and GCC behavior is correct.  pasting foo and ( don't make a valid
preprocessing token.


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pinskia at gcc dot gnu dot org changed:

   What|Removed |Added

 Status|UNCONFIRMED |RESOLVED
 Resolution||INVALID
Summary|Pasting foo and ( does  |Pasting foo and ( does
   |not give a valid|not give a valid
   |preprocessing token |preprocessing token


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=35610

[Bug preprocessor/35610] Pasting foo and ( does not give a valid preprocessing token

[pinskia at gcc dot gnu dot org]

--- Comment #2 from pinskia at gcc dot gnu dot org  2008-03-16 22:49 ---
## only works to form a valid token, if it does not, then the code is invalid.


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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=35610

[Bug preprocessor/35610] Pasting foo and ( does not give a valid preprocessing token

[andry at inbox dot ru]

--- Comment #3 from andry at inbox dot ru  2008-03-16 22:56 ---
(In reply to comment #2)
 ## only works to form a valid token, if it does not, then the code is invalid.
 
When i can understand which token is valid then?


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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=35610

[Bug preprocessor/35610] Pasting foo and ( does not give a valid preprocessing token

[pinskia at gcc dot gnu dot org]

--- Comment #4 from pinskia at gcc dot gnu dot org  2008-03-16 23:06 ---
(In reply to comment #3)
 When i can understand which token is valid then?

By reading the C/C++ standards :).  But basically in this case foo and ( are
two different tokens.  Examples of valid tokens: -, foo, ., ,, etc.


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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=35610