[Bug tree-optimization/65917] [6.0 regression] FAIL: gcc.dg/tree-ssa/20030922-2.c scan-tree-dump-times dom1 if 2
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=65917 Richard Biener rguenth at gcc dot gnu.org changed: What|Removed |Added Status|UNCONFIRMED |WAITING Last reconfirmed||2015-04-28 CC||law at gcc dot gnu.org Target Milestone|--- |6.0 Ever confirmed|0 |1 --- Comment #1 from Richard Biener rguenth at gcc dot gnu.org --- Fixed by Jeffs later patch?
[Bug tree-optimization/65917] [6.0 regression] FAIL: gcc.dg/tree-ssa/20030922-2.c scan-tree-dump-times dom1 if 2
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=65917 Jeffrey A. Law law at redhat dot com changed: What|Removed |Added CC||law at redhat dot com --- Comment #3 from Jeffrey A. Law law at redhat dot com --- if (_8 != _14) goto bb 3; else goto bb 6; bb 3: target_bb.1_15 = target_bb; if (_14 == target_bb.1_15) goto bb 4; else goto bb 6; bb 4: if (_8 != target_bb.1_15) goto bb 5; else goto bb 6; Presumably depending on the ordering in the conditionals, we should discover that in bb4 _8 and _15 are equal and eliminate the test.
[Bug tree-optimization/65917] [6.0 regression] FAIL: gcc.dg/tree-ssa/20030922-2.c scan-tree-dump-times dom1 if 2
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=65917 Andreas Schwab sch...@linux-m68k.org changed: What|Removed |Added Status|WAITING |NEW --- Comment #2 from Andreas Schwab sch...@linux-m68k.org --- r222492 is still failing.
[Bug tree-optimization/65917] [6.0 regression] FAIL: gcc.dg/tree-ssa/20030922-2.c scan-tree-dump-times dom1 if 2
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=65917 --- Comment #4 from Jeffrey A. Law law at redhat dot com --- We'll probably need to XFAIL this for now. This is definitely a case where we were just getting lucky before and the new code to canonicalize the comparison arguments causes us not to get lucky. The single use heuristic doesn't help here, because both operands have multiple uses. I'd pondered walking up the use-def chains to guess which operand is more expensive to compute and use that as a heuristic as well, but in this case it'd do the opposite of what we want. I don't see other obvious heuristics that would resolve this issue. The right way to fix this would be to unify cprop and simplification -- ie, when we have a statement that references an SSA_NAME with one of these equivalences, we need to try both SSA_NAMEs and see if it simplifies. I've avoided doing that simply because it hasn't seemed worth the effort and compile-time cost.