Re: [go-nuts] How can I syslog without PID
On Thu, Apr 16, 2020 at 8:16 PM Dean Schulze wrote:
>
> I have a C program with a syslog command like this:
>
> syslog(LOG_INFO, "slurmctrld: initializing resources");
>
> It outputs the first line below in the syslog. This C code executes a golang
> binary that also does syslog commands:
>
> Syslogger, err = syslog.New(syslog.LOG_INFO, "slurmctld")
>
> Syslogger.Info("slurmctld: initializing resources - completed")
>
> The golang code writes the last 3 entries in the syslog, but they include a
> PID or thread id:
>
> Apr 16 19:18:37 slurmctld slurmctld: slurmctrld: initializing resources
> Apr 16 19:19:12 slurmctld slurmctld[24785]: slurmctrld: creating resource
> group
> Apr 16 19:19:15 slurmctld slurmctld[24785]: slurmctrld: creating machines
> Apr 16 19:20:28 slurmctld slurmctld[24785]: slurmctld: initializing resources
> - completed
>
> In golang is there a way to get syslog messages without the PID so they look
> the same as from C code?
No, there isn't. The Go log/syslog package in effect acts like the C
function syslog if LOG_PID is passed to openlog.
If this is important to you I recommend that you just copy the
log/syslog package and edit it for your needs. It's about 400 lines.
Ian
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Re: [go-nuts] How can I syslog without PID
You can get the PID with https://golang.org/pkg/os/#Getpid and use that
you construct a string to hand in as tag to syslog.New.
On Thu, 2020-04-16 at 20:16 -0700, Dean Schulze wrote:
> I have a C program with a syslog command like this:
>
> syslog(LOG_INFO, "slurmctrld: initializing resources");
>
> It outputs the first line below in the syslog. This C code executes
> a golang binary that also does syslog commands:
>
> Syslogger, err = syslog.New(syslog.LOG_INFO, "slurmctld")
>
> Syslogger.Info("slurmctld: initializing resources - completed")
>
> The golang code writes the last 3 entries in the syslog, but they
> include a PID or thread id:
>
> Apr 16 19:18:37 slurmctld slurmctld: slurmctrld: initializing
> resources
> Apr 16 19:19:12 slurmctld slurmctld[24785]: slurmctrld: creating
> resource group
> Apr 16 19:19:15 slurmctld slurmctld[24785]: slurmctrld: creating
> machines
> Apr 16 19:20:28 slurmctld slurmctld[24785]: slurmctld: initializing
> resources - completed
>
> In golang is there a way to get syslog messages without the PID so
> they look the same as from C code?
>
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> Groups "golang-nuts" group.
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> .
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[go-nuts] How can I syslog without PID
I have a C program with a syslog command like this:
syslog(LOG_INFO, "slurmctrld: initializing resources");
It outputs the first line below in the syslog. This C code executes a
golang binary that also does syslog commands:
Syslogger, err = syslog.New(syslog.LOG_INFO, "slurmctld")
Syslogger.Info("slurmctld: initializing resources - completed")
The golang code writes the last 3 entries in the syslog, but they include a
PID or thread id:
Apr 16 19:18:37 slurmctld slurmctld: slurmctrld: initializing resources
Apr 16 19:19:12 slurmctld slurmctld[24785]: slurmctrld: creating resource
group
Apr 16 19:19:15 slurmctld slurmctld[24785]: slurmctrld: creating machines
Apr 16 19:20:28 slurmctld slurmctld[24785]: slurmctld: initializing
resources - completed
In golang is there a way to get syslog messages without the PID so they
look the same as from C code?
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