In development mode `$entry(...)` converts `false` to `Boolean(false)` which can be evaluated to true

2011-12-29 Thread Ali
Hi

In following example (v2.3.0 development mode) `$entry()` converts returned 
`false` to `Boolean(false)` which can be evaluated to true if used 
immediately.

public class Example {
public boolean test() { return false; }
public native void inject() /*-{
var self = this;
$wnd.test = $entry(function(){ return 
se...@my.gwt.client.Example::test()(); });
}-*/;
}

in js
alert(test() + = + (test() ? true : false));
results in `false=true`.

Is this a bug or I have used it incorrectly?

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Re: In development mode `$entry(...)` converts `false` to `Boolean(false)` which can be evaluated to true

2011-12-29 Thread Sanjiv Jivan
I hit the same issue as well. See the thread below which describes problem
and a workaround.

http://groups.google.com/group/google-web-toolkit-contributors/tree/browse_frm/month/2010-04/f728b64e7237b937?rnum=211_done=%2Fgroup%2Fgoogle-web-toolkit-contributors%2Fbrowse_frm%2Fmonth%2F2010-04%3F

Sanjiv

On Thu, Dec 29, 2011 at 4:32 PM, Ali ali.sak...@gmail.com wrote:

 Hi

 In following example (v2.3.0 development mode) `$entry()` converts
 returned `false` to `Boolean(false)` which can be evaluated to true if used
 immediately.

 public class Example {
 public boolean test() { return false; }
 public native void inject() /*-{
 var self = this;
 $wnd.test = $entry(function(){ return se...@my.gwt.client.Example
 ::test()(); });
 }-*/;
 }

 in js
 alert(test() + = + (test() ? true : false));
 results in `false=true`.

 Is this a bug or I have used it incorrectly?

 --
 You received this message because you are subscribed to the Google Groups
 Google Web Toolkit group.
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 To unsubscribe from this group, send email to
 google-web-toolkit+unsubscr...@googlegroups.com.
 For more options, visit this group at
 http://groups.google.com/group/google-web-toolkit?hl=en.


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