[gmx-users] confusion of forward and backward FEP in Gromacs-4.6.5

2014-06-19 Thread dbaogen
Hi all,

I want to calculate the free energy difference for ATP--GTP in 
solution, for the forward analysis, the parameters for free energy perturbation 
are as follows: 
free-energy  = yes
sc-alpha = 0.3
sc-power = 1
sc-sigma = 0.25
sc-coul  = no
couple-intramol  = yes
init-lambda-state= $LAMBDA$
coul-lambdas = 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.00 1.0 
1.00 1.0 1.00 1.0 1.00 1.0 1.00 1.0 1.00 1.0 1.00 1.0 1.00 1.0 1.00 1.0 1.00 1.0
vdw-lambdas  = 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.05 0.1 
0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5 0.55 0.6 0.65 0.7 0.75 0.8 0.85 0.9 0.95 1.0
nstdhdl  = 50
calc-lambda-neighbors= 1

 The calculated free energy difference is about -273 kJ/mol. In order to 
check the FEP convergence, backward analysis was also done. I adopt two ways to 
carry out backward analysis.

(1) Modify the topology file for GTP-- ATP , the parameters of free energy 
calculation is the same as forward analysis. And the free energy difference of 
backward is about 213   kJ/mol. 

(2)Using the same topology file as forward analysis. But modify the parameter 
settings of coul-lambdas and vdw-lambdas for free energy calculation shown as 
follows
free-energy  = yes
sc-alpha = 0.3
sc-power = 1
sc-sigma = 0.25
sc-coul  = no
couple-intramol  = yes
init-lambda-state= $LAMBDA$
coul-lambdas = 1.0 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0.0 0.00 0.0 
0.00 0.0 0.00 0.0 0.00 0.0 0.00 0.0 0.00 0.0 0.00 0.0 0.00 0.0 0.00 0.0 0.00 0.0
vdw-lambdas  = 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 0.95 0.9 
0.85 0.8 0.75 0.7 0.65 0.6 0.55 0.5 0.45 0.4 0.35 0.3 0.25 0.2 0.15 0.1 0.05 0.0
nstdhdl  = 50
calc-lambda-neighbors= 1

The calculated free energy difference is about 272 kJ/mol

Theoretically, the two ways of backward analysis is the same. And the values of 
free energy should be identical. Now, I am confused whether  I  misunderstand 
something or set the wrong parameters for FEP calculation. Would you like to 
give me some help? Thanks in advance.

Best wishes
Duan Baogen

Beijing Computational Science Research Center





 
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[gmx-users] large free energy difference of mutating ATP to GTP in solution using FEP method in Gromacs-4.6.5

2014-05-23 Thread dbaogen
  DUM_1   
0.00   1.0080
31 NC  1RAG N1 31   -0.76150  14.00   NA 
-0.47870  14.00
32 CQ  1RAG C2 320.58750  12.00   CA 
0.76570  12.00
33 H5  1RAG H2 330.04730   1.008000   N2 
-0.96720  14.00
34 NC  1RAG N3 34   -0.69970  14.00   NC 
-0.63230  14.00
35 CB  1RAG C4 350.30530  12.00   CB 
0.12220  12.00
36 CT  1RAGC3* 360.20220  12.00
37 H1  1RAGH30 370.06150   1.008000
38 OH  1RAGO3* 38   -0.65410  16.00
39 HO  1RAGH3' 390.43760   1.008000
40 CT  1RAGC2* 400.06700  12.00
41 H1  1RAGH20 410.09720   1.008000
42 OH  1RAGO2* 42   -0.61390  16.00
43 HO  1RAGH2' 430.41860   1.008000
; add dummy atoms
44   DUM_1 1RAGDH1 440.00  1.008000   H  
0.34240   1.008000
45   DUM_1 1RAG   DH21 450.00  1.008000   H  
0.43640   1.008000
46   DUM_1 1RAG   DH22 460.00  1.008000   H  
0.43640   1.008000

After  the FEP simulation is done, g_bar program is used to obtain the free 
energy difference. The value is about -260 kJ/mol which is too large. Because 
the difference between ATP and GTP is only base part.  In addition, if the 
other parameters are kept and only change sc-coul = yes and couple-intramol  = 
yes, the free energy difference is -160 kJ/mol. So far, I have not found the 
solution. Could anyone give me some suggestions about this? whether the mdp 
file or top for FEP calculation is wrong?  The equilibrium hybrid structure  
and topology files are enclosed. Thanks for your great help!


Best 

Duan Baogen
Beijing Computational Science Research Center




dbaogen
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