Re: [Haskell-cafe] Tasty not compiling

2013-08-30 Thread Roman Cheplyaka
* Thiago Negri evoh...@gmail.com [2013-08-29 22:27:47-0300]
 I can't install tasty with cabal. Anyone with the same issue or a fix?
 
 $ cabal install tasty
 ...
 Test\Tasty\Core.hs:147:11: Not in scope: `witness'

You probably have a too old version of 'tagged'. I'll add the lower
version bound on it. Meanwhile, just do

  cabal install tasty --constraint 'tagged =0.5'

Roman


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[Haskell-cafe] Performance of delete-and-return-last-element

2013-08-30 Thread Lucas Paul
Suppose I need to get an element from a data structure, and also
modify the data structure. For example, I might need to get and delete
the last element of a list:

darle xs = ((last xs), (rmlast xs)) where
  rmlast [_] = []
  rmlast (y:ys) = y:(rmlast ys)

There are probably other and better ways to write rmlast, but I want
to focus on the fact that darle here, for lack of a better name off
the top of my head, appears to traverse the list twice. Once to get
the element, and once to remove it to produce a new list. This seems
bad. Especially for large data structures, I don't want to be
traversing twice to do what ought to be one operation. To fix it, I
might be tempted to write something like:

darle' [a] = (a, [])
darle' (x:xs) = let (a, ys) = darle' xs in (a, (x:ys))

But this version has lost its elegance. It was also kind of harder to
come up with, and for more complex data structures (like the binary
search tree) the simpler expression is really desirable. Can a really
smart compiler transform/optimize the first definition into something
that traverses the data structure only once? Can GHC?

- Lucas

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Re: [Haskell-cafe] Performance of delete-and-return-last-element

2013-08-30 Thread Ben
isn't this what zippers are for?

b

On Aug 30, 2013, at 1:04 PM, Clark Gaebel wrote:

 I don't think a really smart compiler can make that transformation. It looks 
 like an exponential-time algorithm would be required, but I can't prove that.
 
 GHC definitely won't...
 
 For this specific example, though, I'd probably do:
 
 darle :: [a] - (a, [a])
 darle xs =
   case reverse xs of
 []   - error darle: empty list
 (x:xs) - (x, reverse xs)
 
   - Clark
 
 
 On Fri, Aug 30, 2013 at 2:18 PM, Lucas Paul reilith...@gmail.com wrote:
 Suppose I need to get an element from a data structure, and also
 modify the data structure. For example, I might need to get and delete
 the last element of a list:
 
 darle xs = ((last xs), (rmlast xs)) where
   rmlast [_] = []
   rmlast (y:ys) = y:(rmlast ys)
 
 There are probably other and better ways to write rmlast, but I want
 to focus on the fact that darle here, for lack of a better name off
 the top of my head, appears to traverse the list twice. Once to get
 the element, and once to remove it to produce a new list. This seems
 bad. Especially for large data structures, I don't want to be
 traversing twice to do what ought to be one operation. To fix it, I
 might be tempted to write something like:
 
 darle' [a] = (a, [])
 darle' (x:xs) = let (a, ys) = darle' xs in (a, (x:ys))
 
 But this version has lost its elegance. It was also kind of harder to
 come up with, and for more complex data structures (like the binary
 search tree) the simpler expression is really desirable. Can a really
 smart compiler transform/optimize the first definition into something
 that traverses the data structure only once? Can GHC?
 
 - Lucas
 
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Re: [Haskell-cafe] Performance of delete-and-return-last-element

2013-08-30 Thread Clark Gaebel
I don't think a really smart compiler can make that transformation. It
looks like an exponential-time algorithm would be required, but I can't
prove that.

GHC definitely won't...

For this specific example, though, I'd probably do:

darle :: [a] - (a, [a])
darle xs =
  case reverse xs of
[]   - error darle: empty list
(x:xs) - (x, reverse xs)

  - Clark


On Fri, Aug 30, 2013 at 2:18 PM, Lucas Paul reilith...@gmail.com wrote:

 Suppose I need to get an element from a data structure, and also
 modify the data structure. For example, I might need to get and delete
 the last element of a list:

 darle xs = ((last xs), (rmlast xs)) where
   rmlast [_] = []
   rmlast (y:ys) = y:(rmlast ys)

 There are probably other and better ways to write rmlast, but I want
 to focus on the fact that darle here, for lack of a better name off
 the top of my head, appears to traverse the list twice. Once to get
 the element, and once to remove it to produce a new list. This seems
 bad. Especially for large data structures, I don't want to be
 traversing twice to do what ought to be one operation. To fix it, I
 might be tempted to write something like:

 darle' [a] = (a, [])
 darle' (x:xs) = let (a, ys) = darle' xs in (a, (x:ys))

 But this version has lost its elegance. It was also kind of harder to
 come up with, and for more complex data structures (like the binary
 search tree) the simpler expression is really desirable. Can a really
 smart compiler transform/optimize the first definition into something
 that traverses the data structure only once? Can GHC?

 - Lucas

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 Haskell-Cafe@haskell.org
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