If you're interested in learning parsec, RWH covered this topic in depth in
Chapter 16, Choices and Errors:
http://book.realworldhaskell.org/read/using-parsec.html.
On Mon, Jan 2, 2012 at 3:44 AM, max m...@mtw.ru wrote:
I want to write a function whose behavior is as follows:
foo string1\nstring2\r\nstring3\nstring4 = [string1,
string2\r\nstring3, string4]
Note the sequence \r\n, which is ignored. How can I do this?
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