[Haskell-cafe] Language.Haskell.Parser question
Hi, I want to parse haskell file to find all calls to function 'foo' and gathers a create a list of all argumets, which passed to it. E.g. from the following code: f1 = foo 5 f2 = foo 8 f3 = foo 9 I want to extract a list [5, 8, 9] (suppouse function takes only one argument) The most obvious way is to use Language.Haskell for this task. The parser works pretty good, but its output data type is terrible. As I understand, I need to extract all objects that looks like HsApp (HsVar (UnQual (HsIdent foo))) The question is, is there a method to do it quickly or I have to process each object of different type separately ? Maybe it is a work for a template Haskell ? Thanks. -- Best regards, Vasyl Pasternak ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
Re: [Haskell-cafe] Language.Haskell.Parser question
Hi f1 = foo 5 f2 = foo 8 f3 = foo 9 I want to extract a list [5, 8, 9] (suppouse function takes only one argument) Firstly, use haskell-src-exts and Language.Haskell.Exts - its a much better library, deals with many extensions, and gives you everything Language.Haskell did. parser works pretty good, but its output data type is terrible. As I understand, I need to extract all objects that looks like HsApp (HsVar (UnQual (HsIdent foo))) It's trivial, if you use a generics solution, say Uniplate: http://community.haskell.org/~ndm/uniplate [x | App foo x - universeBi src, prettyPrint foo == foo ] I often use prettyPrint to follow down Ident/Qual/UnQual paths without having to know as much of the data type. Using universeBi makes it easy to find everything that occurs everywhere. If you attempt this without using a generics library, I'd say you are destined to fail. Thanks Neil ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
Re: [Haskell-cafe] Language.Haskell.Parser question
2009/3/26 Vasyl Pasternak vasyl.paster...@gmail.com: Hi, I want to parse haskell file to find all calls to function 'foo' and gathers a create a list of all argumets, which passed to it. E.g. from the following code: f1 = foo 5 f2 = foo 8 f3 = foo 9 I want to extract a list [5, 8, 9] (suppouse function takes only one argument) The most obvious way is to use Language.Haskell for this task. The parser works pretty good, but its output data type is terrible. As I understand, I need to extract all objects that looks like HsApp (HsVar (UnQual (HsIdent foo))) The question is, is there a method to do it quickly or I have to process each object of different type separately ? Have a look at this: http://neilmitchell.blogspot.com/2009/03/concise-generic-queries.html Cheers, Thu ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
Re: [Haskell-cafe] Language.Haskell.Parser question
Actually, looking at the docs for UniplateStr[1], isn't there an error in the following example statement in the Queries section? vals x = [Val i | i - universe x] Shouldn't that be: vals x = [i | Val i - universe x] ? /jve 1. http://hackage.haskell.org/packages/archive/uniplate/1.2.0.3/doc/html/Data-Generics-UniplateStr.html On Thu, Mar 26, 2009 at 1:47 PM, minh thu not...@gmail.com wrote: 2009/3/26 Vasyl Pasternak vasyl.paster...@gmail.com: Hi, I want to parse haskell file to find all calls to function 'foo' and gathers a create a list of all argumets, which passed to it. E.g. from the following code: f1 = foo 5 f2 = foo 8 f3 = foo 9 I want to extract a list [5, 8, 9] (suppouse function takes only one argument) The most obvious way is to use Language.Haskell for this task. The parser works pretty good, but its output data type is terrible. As I understand, I need to extract all objects that looks like HsApp (HsVar (UnQual (HsIdent foo))) The question is, is there a method to do it quickly or I have to process each object of different type separately ? Have a look at this: http://neilmitchell.blogspot.com/2009/03/concise-generic-queries.html Cheers, Thu ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
Re: [Haskell-cafe] Language.Haskell.Parser question
Excellent! The black magic had me scratching my head until I realized it was broken magic. :) /jve On Thu, Mar 26, 2009 at 4:23 PM, Neil Mitchell ndmitch...@gmail.com wrote: Hi John, Actually, looking at the docs for UniplateStr[1], isn't there an error in the following example statement in the Queries section? vals x = [Val i | i - universe x] Shouldn't that be: vals x = [i | Val i - universe x] Yep, you are indeed right. I've fixed the examples in the darcs version, and next time there is a release these changes will be incorporated. Many thanks Neil ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
Re: [Haskell-cafe] Language.Haskell.Parser question
Hi John, Actually, looking at the docs for UniplateStr[1], isn't there an error in the following example statement in the Queries section? vals x = [Val i | i - universe x] Shouldn't that be: vals x = [i | Val i - universe x] Yep, you are indeed right. I've fixed the examples in the darcs version, and next time there is a release these changes will be incorporated. Many thanks Neil ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
Re: [Haskell-cafe] Language.Haskell.Parser question
Excellent! The black magic had me scratching my head until I realized it was broken magic. :) I should probably rerelease Uniplate so the documentation gets fixed, but its not actually broken - although there is no way it does what I intended! vals x = [Val i | i - universe x] Given the type rules: Val :: Int - Expr universe :: a - [a] And the knowledge that: universe (i :: Int) = [i] We can conclude that i :: Int and x :: Int. Therefore the function is equivalent to: vals :: Int - [Expr] vals i = [Val i] Certainly not what I was going for, but it does work! You could even argue it would be sensible to name such a function vals... Thanks Neil On Thu, Mar 26, 2009 at 4:23 PM, Neil Mitchell ndmitch...@gmail.com wrote: Hi John, Actually, looking at the docs for UniplateStr[1], isn't there an error in the following example statement in the Queries section? vals x = [Val i | i - universe x] Shouldn't that be: vals x = [i | Val i - universe x] Yep, you are indeed right. I've fixed the examples in the darcs version, and next time there is a release these changes will be incorporated. Many thanks Neil ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
Re: [Haskell-cafe] Language.Haskell.Parser question
Wow, uniplate is the library from my dreams :) I knew there should be easy, elegant and simple solution (I hate brute force, that's why I start using Haskell). Many thanks. 2009/3/26 Neil Mitchell ndmitch...@gmail.com: Hi f1 = foo 5 f2 = foo 8 f3 = foo 9 I want to extract a list [5, 8, 9] (suppouse function takes only one argument) Firstly, use haskell-src-exts and Language.Haskell.Exts - its a much better library, deals with many extensions, and gives you everything Language.Haskell did. parser works pretty good, but its output data type is terrible. As I understand, I need to extract all objects that looks like HsApp (HsVar (UnQual (HsIdent foo))) It's trivial, if you use a generics solution, say Uniplate: http://community.haskell.org/~ndm/uniplate [x | App foo x - universeBi src, prettyPrint foo == foo ] I often use prettyPrint to follow down Ident/Qual/UnQual paths without having to know as much of the data type. Using universeBi makes it easy to find everything that occurs everywhere. If you attempt this without using a generics library, I'd say you are destined to fail. Thanks Neil -- Best regards, Vasyl Pasternak ___ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
