Re: How to get the parameters from HttpRequest?
On Thu, 2014-12-18 at 17:59 +0100, Johan Hertz wrote: Hi, I am creating a class that implements the interface HttpRequestHandler. The handle method has a parameter of type HttpRequest on which I would expect to find the payload/parameters sent to the server. It does have a getParams method but it is deprecated. The deprecated message is /use configuration classes provided 'org.apache.http.config' and 'org.apache.http.client.config///. Looking at this classes I can't seem to find what I am after, anyone know where I should look? Regards Johan Johan URIBuilder [1] and URLEncodedUtils [2] from HttpClient should do the trick. You can use URIBuilder to manipulate request URIs and extract request query parameters. URLEncodedUtils can be used to parse request entity to extract form parameters. Hope this helps. Oleg [1] http://hc.apache.org/httpcomponents-client-4.3.x/httpclient/apidocs/org/apache/http/client/utils/URIBuilder.html [2] http://hc.apache.org/httpcomponents-client-4.3.x/httpclient/apidocs/org/apache/http/client/utils/URLEncodedUtils.html - To unsubscribe, e-mail: httpclient-users-unsubscr...@hc.apache.org For additional commands, e-mail: httpclient-users-h...@hc.apache.org
Re: How to get the parameters from HttpRequest?
On 2014-12-19 14:47, Oleg Kalnichevski wrote: On Thu, 2014-12-18 at 17:59 +0100, Johan Hertz wrote: Hi, I am creating a class that implements the interface HttpRequestHandler. The handle method has a parameter of type HttpRequest on which I would expect to find the payload/parameters sent to the server. It does have a getParams method but it is deprecated. The deprecated message is /use configuration classes provided 'org.apache.http.config' and 'org.apache.http.client.config///. Looking at this classes I can't seem to find what I am after, anyone know where I should look? Regards Johan Johan URIBuilder [1] and URLEncodedUtils [2] from HttpClient should do the trick. You can use URIBuilder to manipulate request URIs and extract request query parameters. URLEncodedUtils can be used to parse request entity to extract form parameters. Hope this helps. Oleg [1] http://hc.apache.org/httpcomponents-client-4.3.x/httpclient/apidocs/org/apache/http/client/utils/URIBuilder.html [2] http://hc.apache.org/httpcomponents-client-4.3.x/httpclient/apidocs/org/apache/http/client/utils/URLEncodedUtils.html - To unsubscribe, e-mail: httpclient-users-unsubscr...@hc.apache.org For additional commands, e-mail: httpclient-users-h...@hc.apache.org Hi, Thanks for replying. I am doing this on the server side so I don't know if the solution you suggested applies? But what I found was that the request was of type HttpEntityEnclosingRequest. So I just cast to that and then get the payload data using entityRequest.getEntity() and then read the data from the input stream returned by entity.getContent(). Regards Johan - To unsubscribe, e-mail: httpclient-users-unsubscr...@hc.apache.org For additional commands, e-mail: httpclient-users-h...@hc.apache.org
Re: How to get the parameters from HttpRequest?
On Fri, 2014-12-19 at 14:55 +0100, Johan Hertz wrote: On 2014-12-19 14:47, Oleg Kalnichevski wrote: On Thu, 2014-12-18 at 17:59 +0100, Johan Hertz wrote: Hi, I am creating a class that implements the interface HttpRequestHandler. The handle method has a parameter of type HttpRequest on which I would expect to find the payload/parameters sent to the server. It does have a getParams method but it is deprecated. The deprecated message is /use configuration classes provided 'org.apache.http.config' and 'org.apache.http.client.config///. Looking at this classes I can't seem to find what I am after, anyone know where I should look? Regards Johan Johan URIBuilder [1] and URLEncodedUtils [2] from HttpClient should do the trick. You can use URIBuilder to manipulate request URIs and extract request query parameters. URLEncodedUtils can be used to parse request entity to extract form parameters. Hope this helps. Oleg [1] http://hc.apache.org/httpcomponents-client-4.3.x/httpclient/apidocs/org/apache/http/client/utils/URIBuilder.html [2] http://hc.apache.org/httpcomponents-client-4.3.x/httpclient/apidocs/org/apache/http/client/utils/URLEncodedUtils.html - To unsubscribe, e-mail: httpclient-users-unsubscr...@hc.apache.org For additional commands, e-mail: httpclient-users-h...@hc.apache.org Hi, Thanks for replying. I am doing this on the server side so I don't know if the solution you suggested applies? Why would that matter? URI and HttpEntity instances are absolutely the same. But what I found was that the request was of type HttpEntityEnclosingRequest. So I just cast to that and then get the payload data using entityRequest.getEntity() and then read the data from the input stream returned by entity.getContent(). You could use URLEncodedUtils#parse(HttpEntity) to digest this entity to a list of name/value pairs, but reading directly from the content stream is perfectly reasonable, too. Oleg - To unsubscribe, e-mail: httpclient-users-unsubscr...@hc.apache.org For additional commands, e-mail: httpclient-users-h...@hc.apache.org
How to get the parameters from HttpRequest?
Hi, I am creating a class that implements the interface HttpRequestHandler. The handle method has a parameter of type HttpRequest on which I would expect to find the payload/parameters sent to the server. It does have a getParams method but it is deprecated. The deprecated message is /use configuration classes provided 'org.apache.http.config' and 'org.apache.http.client.config///. Looking at this classes I can't seem to find what I am after, anyone know where I should look? Regards Johan
