[jira] [Commented] (SPARK-21096) Pickle error when passing a member variable to Spark executors
[
https://issues.apache.org/jira/browse/SPARK-21096?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel=16050609#comment-16050609
]
Irina Truong commented on SPARK-21096:
--
I am not passing in {{self}}. I am passing in {{self.multiplier}} - an integer
value.
If this spark behavior is correct, why does the 2nd method not break?
{quote}
def build_ok(self):
mult = self.multiplier
processed = self.rdd.map(lambda row: process_row(row, mult))
return processed.collect()
{quote}
> Pickle error when passing a member variable to Spark executors
> --
>
> Key: SPARK-21096
> URL: https://issues.apache.org/jira/browse/SPARK-21096
> Project: Spark
> Issue Type: Bug
> Components: Spark Core
>Affects Versions: 2.1.1
>Reporter: Irina Truong
>
> There is a pickle error when submitting a spark job that references a member
> variable in a lambda, even when the member variable is a simple type that
> should be serializable.
> Here is a minimal example:
> https://gist.github.com/j-bennet/8390c6d9a81854696f1a9b42a4ea8278
> In the gist above, this method will throw an exception:
> {quote}
> def build_fail(self):
> processed = self.rdd.map(lambda row: process_row(row, self.multiplier))
> return processed.collect()
> {quote}
> While this method will run just fine:
> {quote}
> def build_ok(self):
> mult = self.multiplier
> processed = self.rdd.map(lambda row: process_row(row, mult))
> return processed.collect()
> {quote}
> In this example, {{self.multiplier}} is just an int. However, passing it into
> a lambda throws a pickle error, because it is trying to pickle the whole
> {{self}}, and that contains {{sc}}.
> If this is the expected behavior, then why should re-assigning
> {{self.multiplier}} to a variable make a difference?
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[jira] [Commented] (SPARK-21096) Pickle error when passing a member variable to Spark executors
[
https://issues.apache.org/jira/browse/SPARK-21096?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel=16049852#comment-16049852
]
Hyukjin Kwon commented on SPARK-21096:
--
This is because you are passing {{self}} which has SparkContext that is not
serializable. Taking this out or
{code}
def build_fail(self):
- processed = self.rdd.map(lambda row: process_row(row,
self.multiplier))
+ aa = self.multiplier
+ processed = self.rdd.map(lambda row: process_row(row, aa))
return processed.collect()
{{code}
should work.
> Pickle error when passing a member variable to Spark executors
> --
>
> Key: SPARK-21096
> URL: https://issues.apache.org/jira/browse/SPARK-21096
> Project: Spark
> Issue Type: Bug
> Components: Spark Core
>Affects Versions: 2.1.1
>Reporter: Irina Truong
>
> There is a pickle error when submitting a spark job that references a member
> variable in a lambda, even when the member variable is a simple type that
> should be serializable.
> Here is a minimal example:
> https://gist.github.com/j-bennet/8390c6d9a81854696f1a9b42a4ea8278
> In the gist above, this method will throw an exception:
> {quote}
> def build_fail(self):
> processed = self.rdd.map(lambda row: process_row(row, self.multiplier))
> return processed.collect()
> {quote}
> While this method will run just fine:
> {quote}
> def build_ok(self):
> mult = self.multiplier
> processed = self.rdd.map(lambda row: process_row(row, mult))
> return processed.collect()
> {quote}
> In this example, {{self.multiplier}} is just an int. However, passing it into
> a lambda throws a pickle error, because it is trying to pickle the whole
> {{self}}, and that contains {{sc}}.
> If this is the expected behavior, then why should re-assigning
> {{self.multiplier}} to a variable make a difference?
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