I searched around and couldn't find an answer for this. I'm in a bind
because I'm developing JS that is used in a web framework, and is
frequently mixed in with other developers' jQuery code. Unfortunately
errors in their jQuery(document).ready blocks prevent mine from
executing. Take the following simple sample:
<script type="text/javascript">
jQuery(document).ready(function() {
nosuchobject.fakemethod(); //intentionally cause major error
});
</script>
<script type="text/javascript">
jQuery(document).ready(function() {
alert("Hello!"); //never executed
});
</script>
Why is is that an error in on ready block will prevent further ready
blocks from executing? Is there a "safe" way to run jQuery
(document).ready that will run even in the case of previous errors?
Thanks for any pointers.
