[jQuery] Re: G is undefined
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpgquot;
alt=quot;quot;gt;},{ImageTag:lt;img src=quot;http://
www.xxx.com/image/4852.jpgquot; alt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpgquot;
alt=quot;quot;gt;},{ImageTag:lt;img src=quot;http://
www.xxx.com/image/4852.jpgquot; alt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpgquot;
alt=quot;quot;gt;},{ImageTag:lt;img src=quot;http://
www.xxx.com/image/4852.jpgquot; alt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
So is this valid JSON that jQuery can parse? or do I need an initial
level such as Images:
[{Images :
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img src=quot;http://
www.xxx.com/image/4852.jpg alt=quot;quot;gt;}
]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
So is this valid JSON that jQuery can parse? or do I need an initial
level such as Images:
[{Images :
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img src=quot;http://
www.xxx.com/image/4852.jpg alt=quot;quot;gt;}
]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
So is this valid JSON that jQuery can parse? or do I need an initial
level such as Images:
[{Images :
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img src=quot;http://
www.xxx.com/image/4852.jpg alt=quot;quot;gt;}
]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an initial
level such as Images:
[{Images :
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg; alt=quot;quot;gt;}
]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
yea, refreshing the page posts again, very annoying
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an initial
level such as Images:
[{Images :
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg; alt=quot;quot;gt;}
]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
this is how I'm sending the JSON, so it adds [ ]
http://weblogs.asp.net/scottgu/archive/2007/10/01/tip-trick-building-a-tojson-extension-method-using-net-3-5.aspx
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an initial
level such as Images:
[{Images :
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg; alt=quot;quot;gt;}
]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
http://en.wikipedia.org/wiki/JSON
will show you what it should look like... notice the outside symbols
are { ... }, not [ ]
again, you should look at this if you are working with .NET and JSON,
it really takes all this guess work from the equation:
http://james.newtonking.com/pages/json-net.aspx
On Jun 29, 12:01 pm, expresso dschin...@gmail.com wrote:
Ok, so what should it be wrapped in or how should I reformat this?
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an initial
level such as Images:
[{Images :
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg; alt=quot;quot;gt;}
]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
Thanks I've seen this but would rather stay away from any libraries
right now. So basically yea, should be {}
I just wonder why the ASP.NET 3.5 JavascriptSerializer class doesn't
produce the right output.
On Jun 29, 11:03 am, MorningZ morni...@gmail.com wrote:
http://en.wikipedia.org/wiki/JSON
will show you what it should look like... notice the outside symbols
are { ... }, not [ ]
again, you should look at this if you are working with .NET and JSON,
it really takes all this guess work from the equation:
http://james.newtonking.com/pages/json-net.aspx
On Jun 29, 12:01 pm, expresso dschin...@gmail.com wrote:
Ok, so what should it be wrapped in or how should I reformat this?
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an initial
level such as Images:
[{Images :
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg; alt=quot;quot;gt;}
]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var
l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
some tells me that my original JSON is totally valid with the [ and ]
On Jun 29, 11:03 am, MorningZ morni...@gmail.com wrote:
http://en.wikipedia.org/wiki/JSON
will show you what it should look like... notice the outside symbols
are { ... }, not [ ]
again, you should look at this if you are working with .NET and JSON,
it really takes all this guess work from the equation:
http://james.newtonking.com/pages/json-net.aspx
On Jun 29, 12:01 pm, expresso dschin...@gmail.com wrote:
Ok, so what should it be wrapped in or how should I reformat this?
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an initial
level such as Images:
[{Images :
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg; alt=quot;quot;gt;}
]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var
l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
I even sent a test string without the [ ] and I still get 'undefined'
for my alert here:
function mycarousel_itemLoadCallback(carousel, state) {
// Only load items if they don't already exist
if (carousel.has(carousel.first, carousel.last)) {
return;
}
$.getJSON(http://localhost:59396/sss/CHandler.ashx?
action=productsjson,
function(data) {
alert(data.items);
$.each(data.items, function(i, item) {
carousel.add(i, mycarousel_decodeEntities(item));
if (i == 3) return false;
});
});
};
the JSON in this case was:
{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpgquot;
alt=quot;quot;gt;},{ImageTag:lt;img src=quot;http://
www.xxx.com/cat_image/485.jpgquot; alt=quot;quot;gt;}
so same deal here. I'm stuck.
On Jun 29, 11:03 am, MorningZ morni...@gmail.com wrote:
http://en.wikipedia.org/wiki/JSON
will show you what it should look like... notice the outside symbols
are { ... }, not [ ]
again, you should look at this if you are working with .NET and JSON,
it really takes all this guess work from the equation:
http://james.newtonking.com/pages/json-net.aspx
On Jun 29, 12:01 pm, expresso dschin...@gmail.com wrote:
Ok, so what should it be wrapped in or how should I reformat this?
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an initial
level such as Images:
[{Images :
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg; alt=quot;quot;gt;}
]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why because
here's the json my url returns:
[{ImageTag:lt;img src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;gt;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx (line 30)
I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19)
[Break on this error] (function(){var
l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i, mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that the error starts at
$.each I believe
[jQuery] Re: G is undefined
That's right, your JSON is perfectly valid. You can test it at:
www.jsonlint.org
Here's the formatted output from that site, with the image tags elided for
clarity, and comments added showing how you'd access each part of it
directly in JavaScript:
// Data
[
// Data[0]
{
// Data[0].ImageTag
ImageTag: ...
},
// Data[1]
{
// Data[1].ImageTag
ImageTag: ...
}
]
As you can see, what you have is an array of two elements. Each of those
elements is an object with a single property named ImageTag with a string
value.
Now back to your code. This is where it goes wrong:
$.each(Data.items, function(i, item) {...});
Data here is the JSON data, and you're trying to get its items property
and use it as an array. But there is no items property - Data itself is
the array, so you'd use it directly:
$.each(Data, function(i, item) {...});
JSON that would work with your original code using Data.items would look
like this:
// Data
{
// Data.items
items: [
// Data.items[0]
{
// Data.items[0].ImageTag
ImageTag: ...
},
// Data.items[1]
{
// Data.items[1].ImageTag
ImageTag: ...
}
]
}
BTW, I suggest using variable names that begin with lower case. The upper
case first letter makes people think it's the name of a constructor.
-Mike
From: expresso
some tells me that my original JSON is totally valid with the [ and ]
On Jun 29, 11:03 am, MorningZ morni...@gmail.com wrote:
http://en.wikipedia.org/wiki/JSON
will show you what it should look like... notice the
outside symbols
are { ... }, not [ ]
again, you should look at this if you are working with .NET
and JSON,
it really takes all this guess work from the equation:
http://james.newtonking.com/pages/json-net.aspx
On Jun 29, 12:01 pm, expresso dschin...@gmail.com wrote:
Ok, so what should it be wrapped in or how should I reformat this?
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an
initial level such as Images:
[{Images :
[{ImageTag:lt;img
src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg;
alt=quot;quot;gt;} ]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why
because here's the json my url returns:
[{ImageTag:lt;img
src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;g
t;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx
(line 30) I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19) [Break on this error]
(function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i,
mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that
the error
starts at $.each I believe
[jQuery] Re: G is undefined
Mike thanks a lot. That is so weird. I got some ideas from
http://docs.jquery.com/GetJSON and as you can see from the example
it's using data.items.
it's working now. I just wonder why the jQuery example is using
data.items
On Jun 29, 12:19 pm, Michael Geary m...@mg.to wrote:
That's right, your JSON is perfectly valid. You can test it at:
www.jsonlint.org
Here's the formatted output from that site, with the image tags elided for
clarity, and comments added showing how you'd access each part of it
directly in JavaScript:
// Data
[
// Data[0]
{
// Data[0].ImageTag
ImageTag: ...
},
// Data[1]
{
// Data[1].ImageTag
ImageTag: ...
}
]
As you can see, what you have is an array of two elements. Each of those
elements is an object with a single property named ImageTag with a string
value.
Now back to your code. This is where it goes wrong:
$.each(Data.items, function(i, item) {...});
Data here is the JSON data, and you're trying to get its items property
and use it as an array. But there is no items property - Data itself is
the array, so you'd use it directly:
$.each(Data, function(i, item) {...});
JSON that would work with your original code using Data.items would look
like this:
// Data
{
// Data.items
items: [
// Data.items[0]
{
// Data.items[0].ImageTag
ImageTag: ...
},
// Data.items[1]
{
// Data.items[1].ImageTag
ImageTag: ...
}
]
}
BTW, I suggest using variable names that begin with lower case. The upper
case first letter makes people think it's the name of a constructor.
-Mike
From: expresso
some tells me that my original JSON is totally valid with the [ and ]
On Jun 29, 11:03 am, MorningZ morni...@gmail.com wrote:
http://en.wikipedia.org/wiki/JSON
will show you what it should look like... notice the
outside symbols
are { ... }, not [ ]
again, you should look at this if you are working with .NET
and JSON,
it really takes all this guess work from the equation:
http://james.newtonking.com/pages/json-net.aspx
On Jun 29, 12:01 pm, expresso dschin...@gmail.com wrote:
Ok, so what should it be wrapped in or how should I reformat this?
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an
initial level such as Images:
[{Images :
[{ImageTag:lt;img
src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg;
alt=quot;quot;gt;} ]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why
because here's the json my url returns:
[{ImageTag:lt;img
src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;g
t;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx
(line 30) I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19) [Break on this error]
(function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i,
mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that
the error
starts at $.each I believe
[jQuery] Re: G is undefined
I understand. Thanks for the explanation.
On Jun 29, 12:19 pm, Michael Geary m...@mg.to wrote:
That's right, your JSON is perfectly valid. You can test it at:
www.jsonlint.org
Here's the formatted output from that site, with the image tags elided for
clarity, and comments added showing how you'd access each part of it
directly in JavaScript:
// Data
[
// Data[0]
{
// Data[0].ImageTag
ImageTag: ...
},
// Data[1]
{
// Data[1].ImageTag
ImageTag: ...
}
]
As you can see, what you have is an array of two elements. Each of those
elements is an object with a single property named ImageTag with a string
value.
Now back to your code. This is where it goes wrong:
$.each(Data.items, function(i, item) {...});
Data here is the JSON data, and you're trying to get its items property
and use it as an array. But there is no items property - Data itself is
the array, so you'd use it directly:
$.each(Data, function(i, item) {...});
JSON that would work with your original code using Data.items would look
like this:
// Data
{
// Data.items
items: [
// Data.items[0]
{
// Data.items[0].ImageTag
ImageTag: ...
},
// Data.items[1]
{
// Data.items[1].ImageTag
ImageTag: ...
}
]
}
BTW, I suggest using variable names that begin with lower case. The upper
case first letter makes people think it's the name of a constructor.
-Mike
From: expresso
some tells me that my original JSON is totally valid with the [ and ]
On Jun 29, 11:03 am, MorningZ morni...@gmail.com wrote:
http://en.wikipedia.org/wiki/JSON
will show you what it should look like... notice the
outside symbols
are { ... }, not [ ]
again, you should look at this if you are working with .NET
and JSON,
it really takes all this guess work from the equation:
http://james.newtonking.com/pages/json-net.aspx
On Jun 29, 12:01 pm, expresso dschin...@gmail.com wrote:
Ok, so what should it be wrapped in or how should I reformat this?
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an
initial level such as Images:
[{Images :
[{ImageTag:lt;img
src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg;
alt=quot;quot;gt;} ]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why
because here's the json my url returns:
[{ImageTag:lt;img
src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;g
t;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx
(line 30) I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19) [Break on this error]
(function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i,
mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that
the error
starts at $.each I believe
[jQuery] Re: G is undefined
In addition to www.jsonlint.org, since you're developing on Windows, head over here right now and get the Fiddler debugging proxy server: http://www.fiddler2.com/ Then, go to the Extensions page: http://www.fiddler2.com/Fiddler2/extensions.asp At the very least get the JSON Viewer (at the bottom of the page, misnamed as JSON Inspector), and check out some of the other extensions too. The syntax highlighting package and JavaScript formatter are especially useful. The JSON Viewer will both install into Fiddler, so you can view JSON data directly in Fiddler, and you can also run it as a standalone app: Copy and paste your JSON text into the Text tab and then switch to the Viewer tab to inspect it. What the JSON Viewer does that's nice is it shows you the JSON data in a tree structure so you can see how you'd drill down into it with JavaScript code. -Mike From: Michael Geary You can test [your JSON code] at: www.jsonlint.org
[jQuery] Re: G is undefined
The jQuery example is using data.items because the JSON object it is
retrieving is different from yours. Its JSON object is coming from the
flickr API.
--Karl
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Jun 29, 2009, at 1:25 PM, expresso wrote:
Mike thanks a lot. That is so weird. I got some ideas from
http://docs.jquery.com/GetJSON and as you can see from the example
it's using data.items.
it's working now. I just wonder why the jQuery example is using
data.items
On Jun 29, 12:19 pm, Michael Geary m...@mg.to wrote:
That's right, your JSON is perfectly valid. You can test it at:
www.jsonlint.org
Here's the formatted output from that site, with the image tags
elided for
clarity, and comments added showing how you'd access each part of it
directly in JavaScript:
// Data
[
// Data[0]
{
// Data[0].ImageTag
ImageTag: ...
},
// Data[1]
{
// Data[1].ImageTag
ImageTag: ...
}
]
As you can see, what you have is an array of two elements. Each of
those
elements is an object with a single property named ImageTag with a
string
value.
Now back to your code. This is where it goes wrong:
$.each(Data.items, function(i, item) {...});
Data here is the JSON data, and you're trying to get its items
property
and use it as an array. But there is no items property - Data
itself is
the array, so you'd use it directly:
$.each(Data, function(i, item) {...});
JSON that would work with your original code using Data.items would
look
like this:
// Data
{
// Data.items
items: [
// Data.items[0]
{
// Data.items[0].ImageTag
ImageTag: ...
},
// Data.items[1]
{
// Data.items[1].ImageTag
ImageTag: ...
}
]
}
BTW, I suggest using variable names that begin with lower case. The
upper
case first letter makes people think it's the name of a constructor.
-Mike
From: expresso
some tells me that my original JSON is totally valid with the
[ and ]
On Jun 29, 11:03 am, MorningZ morni...@gmail.com wrote:
http://en.wikipedia.org/wiki/JSON
will show you what it should look like... notice the
outside symbols
are { ... }, not [ ]
again, you should look at this if you are working with .NET
and JSON,
it really takes all this guess work from the equation:
http://james.newtonking.com/pages/json-net.aspx
On Jun 29, 12:01 pm, expresso dschin...@gmail.com wrote:
Ok, so what should it be wrapped in or how should I reformat this?
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a JSON
object hence .getJSON has no idea what to do with it
On Jun 29, 11:53 am, expresso dschin...@gmail.com wrote:
So is this valid JSON that jQuery can parse? or do I need an
initial level such as Images:
[{Images :
[{ImageTag:lt;img
src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpg;
alt=quot;quot;gt;} ]]
On Jun 29, 10:37 am, expresso dschin...@gmail.com wrote:
Ok, figured out that data.items is undefined. Not sure why
because here's the json my url returns:
[{ImageTag:lt;img
src=quot;http://www.xxx.com/image/473.jpg;
alt=quot;quot;gt;},{ImageTag:lt;img
src=quot;http://www.xxx.com/image/4852.jpgalt=quot;quot;g
t;}]
On Jun 29, 10:33 am, expresso dschin...@gmail.com wrote:
I get the following error:
G is undefined
init()()jquery-12.min.js (line 12)
(?)()()Carousel.aspx
(line 30) I()jquery-12.min.js (line 19)
F()()jquery-12.min.js (line 19) [Break on this error]
(function(){var l=this,g,y=l.jQuery,p=l.each
(function(){o.dequeue(this,E)})}});
in jquery-1.3.2.min.js
when I call this method of mine:
$.getJSON(http://localhost:59396/xxx/xxxHandler.ashx?
action=xxxjson,
function(Data) {
$.each(Data.items, function(i, item) {
alert('got here');
carousel.add(i,
mycarousel_decodeEntities(item.ImageTag));
if (i == 3) return false;
});
});
I know I can get inside function(Data){ and that
the error
starts at $.each I believe
[jQuery] Re: G is undefined
The jQuery example uses data.items because the JSON data it fetches is an
object with an items property. Load the sample URL in your browser and look
at the data:
http://api.flickr.com/services/feeds/photos_public.gne?tags=cattagmode=any
format=json
http://api.flickr.com/services/feeds/photos_public.gne?tags=cattagmode=any;
format=json
If you remove the jsonFlickrFeed() JSONP wrapper, then the data in skeletal
form looks like:
{
title: Recent Uploads tagged cat,
link: http://www.flickr.com/photos/tags/cat/;,
description: ,
modified: 2009-06-29T17:21:37Z,
generator: http://www.flickr.com/;,
items: [
{
title: Metzler Ortloff #137X,
link:
http://www.flickr.com/photos/31042...@n02/3671772469/;,
media: {
m:
http://farm4.static.flickr.com/3613/3671772469_431f0c6df0_m.jpg;
},
date_taken: 2009-06-29T10:21:37-08:00,
description: p...\/p,
published: 2009-06-29T17:21:37Z,
author: nob...@flickr.com (metzlerortloff.cats),
author_id: 31042...@n02,
tags: cat ilmenau metzler ortloff
},
{
// ...another item here, etc...
}
]
}
As you can see, here the outermost part of the JSON is an object enclosed by
the {}. This object has an items property, which is the array of data for
each of the Flickr images. So, if you fetch this JSON object into a variable
named data, then data.items will be that items array.
If you paste the Flickr response into the JSON viewer that I mentioned in my
other message, it will show you a nicely formatted tree structure for the
data. Paste it into the Text tab and you will see an error message at the
bottom because of the JSONP wrapper. Use the Strip to {} button at the top
to automatically strip out that wrapper. Then click the Viewer tab to see
the structure of the data.
-Mike
From: expresso
Mike thanks a lot. That is so weird. I got some ideas from
http://docs.jquery.com/GetJSON http://docs.jquery.com/GetJSON and as
you can see from the
example it's using data.items.
it's working now. I just wonder why the jQuery example is
using data.items
On Jun 29, 12:19 pm, Michael Geary m...@mg.to wrote:
That's right, your JSON is perfectly valid. You can test it at:
www.jsonlint.org
Here's the formatted output from that site, with the image
tags elided
for clarity, and comments added showing how you'd access
each part of
it directly in JavaScript:
// Data
[
// Data[0]
{
// Data[0].ImageTag
ImageTag: ...
},
// Data[1]
{
// Data[1].ImageTag
ImageTag: ...
}
]
As you can see, what you have is an array of two elements. Each of
those elements is an object with a single property named
ImageTag with
a string value.
Now back to your code. This is where it goes wrong:
$.each(Data.items, function(i, item) {...});
Data here is the JSON data, and you're trying to get its items
property and use it as an array. But there is no items property -
Data itself is the array, so you'd use it directly:
$.each(Data, function(i, item) {...});
JSON that would work with your original code using Data.items would
look like this:
// Data
{
// Data.items
items: [
// Data.items[0]
{
// Data.items[0].ImageTag
ImageTag: ...
},
// Data.items[1]
{
// Data.items[1].ImageTag
ImageTag: ...
}
]
}
BTW, I suggest using variable names that begin with lower case. The
upper case first letter makes people think it's the name of
a constructor.
-Mike
From: expresso
some tells me that my original JSON is totally valid with
the [ and
]
On Jun 29, 11:03 am, MorningZ morni...@gmail.com wrote:
http://en.wikipedia.org/wiki/JSON
http://en.wikipedia.org/wiki/JSON
will show you what it should look like... notice the
outside symbols
are { ... }, not [ ]
again, you should look at this if you are working with .NET
and JSON,
it really takes all this guess work from the equation:
http://james.newtonking.com/pages/json-net.aspx
http://james.newtonking.com/pages/json-net.aspx
On Jun 29, 12:01 pm, expresso dschin...@gmail.com wrote:
Ok, so what should it be wrapped in or how should I
reformat this?
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to bump
your topic
annoying
Anyways,
your results wrapped in [ ] signifies an Array, not a
JSON object hence .getJSON has no
[jQuery] Re: G is undefined
Thanks all.
On Jun 29, 1:12 pm, Michael Geary m...@mg.to wrote:
The jQuery example uses data.items because the JSON data it fetches is an
object with an items property. Load the sample URL in your browser and look
at the data:
http://api.flickr.com/services/feeds/photos_public.gne?tags=cattagmo...
format=jsonhttp://api.flickr.com/services/feeds/photos_public.gne?tags=cattagmo...
format=json
If you remove the jsonFlickrFeed() JSONP wrapper, then the data in skeletal
form looks like:
{
title: Recent Uploads tagged cat,
link: http://www.flickr.com/photos/tags/cat/;,
description: ,
modified: 2009-06-29T17:21:37Z,
generator: http://www.flickr.com/;,
items: [
{
title: Metzler Ortloff #137X,
link:
http://www.flickr.com/photos/31042...@n02/3671772469/;,
media: {
m:
http://farm4.static.flickr.com/3613/3671772469_431f0c6df0_m.jpg;
},
date_taken: 2009-06-29T10:21:37-08:00,
description: p...\/p,
published: 2009-06-29T17:21:37Z,
author: nob...@flickr.com (metzlerortloff.cats),
author_id: 31042...@n02,
tags: cat ilmenau metzler ortloff
},
{
// ...another item here, etc...
}
]
}
As you can see, here the outermost part of the JSON is an object enclosed by
the {}. This object has an items property, which is the array of data for
each of the Flickr images. So, if you fetch this JSON object into a variable
named data, then data.items will be that items array.
If you paste the Flickr response into the JSON viewer that I mentioned in my
other message, it will show you a nicely formatted tree structure for the
data. Paste it into the Text tab and you will see an error message at the
bottom because of the JSONP wrapper. Use the Strip to {} button at the top
to automatically strip out that wrapper. Then click the Viewer tab to see
the structure of the data.
-Mike
From: expresso
Mike thanks a lot. That is so weird. I got some ideas from
http://docs.jquery.com/GetJSONhttp://docs.jquery.com/GetJSONand as
you can see from the
example it's using data.items.
it's working now. I just wonder why the jQuery example is
using data.items
On Jun 29, 12:19 pm, Michael Geary m...@mg.to wrote:
That's right, your JSON is perfectly valid. You can test it at:
www.jsonlint.org
Here's the formatted output from that site, with the image
tags elided
for clarity, and comments added showing how you'd access
each part of
it directly in JavaScript:
// Data
[
// Data[0]
{
// Data[0].ImageTag
ImageTag: ...
},
// Data[1]
{
// Data[1].ImageTag
ImageTag: ...
}
]
As you can see, what you have is an array of two elements. Each of
those elements is an object with a single property named
ImageTag with
a string value.
Now back to your code. This is where it goes wrong:
$.each(Data.items, function(i, item) {...});
Data here is the JSON data, and you're trying to get its items
property and use it as an array. But there is no items property -
Data itself is the array, so you'd use it directly:
$.each(Data, function(i, item) {...});
JSON that would work with your original code using Data.items would
look like this:
// Data
{
// Data.items
items: [
// Data.items[0]
{
// Data.items[0].ImageTag
ImageTag: ...
},
// Data.items[1]
{
// Data.items[1].ImageTag
ImageTag: ...
}
]
}
BTW, I suggest using variable names that begin with lower case. The
upper case first letter makes people think it's the name of
a constructor.
-Mike
From: expresso
some tells me that my original JSON is totally valid with
the [ and
]
On Jun 29, 11:03 am, MorningZ morni...@gmail.com wrote:
http://en.wikipedia.org/wiki/JSON
http://en.wikipedia.org/wiki/JSON
will show you what it should look like... notice the
outside symbols
are { ... }, not [ ]
again, you should look at this if you are working with .NET
and JSON,
it really takes all this guess work from the equation:
http://james.newtonking.com/pages/json-net.aspx
http://james.newtonking.com/pages/json-net.aspx
On Jun 29, 12:01 pm, expresso dschin...@gmail.com wrote:
Ok, so what should it be wrapped in or how should I
reformat this?
On Jun 29, 10:58 am, MorningZ morni...@gmail.com wrote:
Wow, is posting the same thing every 3 mins to
