I know this does _not_ answer your question, but are you really sure you
want to do this? Can't you just push your variables to an array, and access
them as x[1], x[2], ... ?
On Tuesday, November 3, 2015 at 2:40:34 PM UTC+1, cormu...@mac.com wrote:
>
> I can't work out the syntax for creating symbols and assigning values to
> the variables in a loop. Here's a simple example:
>
> Starting with this basic idea:
>
> julia> for n in 1:10
> println("x_$(n)")
> end
>
> I'd like to do this:
>
> julia> for n in 1:10
> symbol("x_$(n)") = n
> end
>ERROR: syntax: "(string # n)" is not a valid function
> argument name
>
> to create variables called x_1, x_2, and assign numeric values to them...
> (Numbers in this example, but will be image data eventually.)
>
> Also, for better formatting for variable names:
>
> julia> "x_$(@sprintf "%03d" 2)"
> "x_002"
>
> but this gives a similar error when used with symbol():
>
> julia> for n in 1:10
> symbol("x_$(@sprintf "%03d" 2)") = n
> end
>
> ERROR: syntax: "(string # (let (block (= #21#out (call (.
> #0=# (inert IOBuffer (= #22###x#6979 2) (local
> #27#neg #26#pt #25#len #20#exp #23#do_out #24#args) (if (call (. #0# (inert
> isfinite)) #22###x#6979) (block (= (tuple
>#23#do_out #24#args) (call (. #0# (inert decode_dec)) #21#out
> #22###x#6979 # 2 -1 #)) (if #23#do_out
> (block (= (tuple #25#len #26#pt #27#neg) #24#args) (&& #27#neg (call (. #0#
> (inert write)) #21#out #Char(0x002d)>)) (&& (comparison (call (. #0# (inert -)) (call (.
> #0# (inert -)) 2 #27#neg) #26#pt) (. #0# (inert >)) 0) (call (. #0# (inert
> write)) #21#out #)) (call (. #0# (inert write))
> #21#out (call (. #0# (inert pointer)) (. #0# (inert DIGITS)))
>#26#pt (call (. #0# (inert write)) #21#out (block (line 145
> printf.jl) (if (call (. #0# (inert isnan)) #22###x#6979) #
> (if (comparison #22###x#6979 (. #0# (inert <)) 0) # # "Inf">) (. #0# (inert nothing)) (call (. #0# (inert takebuf_string))
> #21#out" is not a valid function argument name
>
> Perhaps `symbol` isn't what I want here?
>
>