Re: Separate a tuplet from the rest under a common beam
Hello,
I often have varied groupings under one beam and have used the solution
given by Michael Werner. However, I have also created the following to
simplify entering the commands and the look of the score file:
bcLnone = \set stemLeftBeamCount = #0
bcRone = \set stemRightBeamCount = #1
bcLone = \set stemLeftBeamCount = #1
bcRtwo = \set stemRightBeamCount = #2
bcLtwo = \set stemLeftBeamCount = #2
Such as in:
\times 2/3 {f'16([ b, \bcRone f' ~} \bcLone f16 b,] ~ b16[ \bcRone f' ~
\bcLone f32-- b,16.] f'32[ b, ~ b8 f'16] ~ \times 4/6 {f16 b, \bcRone f'
~ \bcLone f b, f'] ~} | \times 2/3 {f16[ b, \bcRone f' ~} \bcLone f32 b,
f' b,] f'32[ b,32 ~ b8]) r16 fis'32([ b, ~ b8 fis'16] ~ \times 4/6 {
fis16[ b, \bcRone fis' ~ \bcLone fis b, fis'])} |
beam count example
Archer
On 14/12/2022 16:24, Michael Werner wrote:
Resending to include the list ... oops.
Something like this, perhaps?
\version "2.23.82"
\relative {
\clef treble
\key c \minor
\time 2/4
\tuplet 3/2 { g'16[( aes \set stemRightBeamCount = #1 g) } \set
stemLeftBeamCount = #1 fis g] a8 b |
}
On Wed, Dec 14, 2022 at 10:42 AM Volodymyr Prokopyuk
wrote:
Hello,
*Problem*
How can I separate a \tuplet from two sixteenths using a common
eightingth beam?
*Example code*
\version "2.23.81"
\relative {
\clef treble
\key c \minor
\time 2/4
\tuplet 3/2 { g'='16[( aes g) } fis g] a8 b |
}
image.png
*Desired result*
image.png
I've tried to adjust the baseMoment, beatStructure, subdivideBeats
and strictBeatBeaming but without success.
Thank you very much,
Vlad
\version "2.22.1"
% beamcountexample.ly
%Shorthand for setting the beam count:
bcLnone = \set stemLeftBeamCount = #0
bcRone = \set stemRightBeamCount = #1
bcLone = \set stemLeftBeamCount = #1
bcRtwo = \set stemRightBeamCount = #2
bcLtwo = \set stemLeftBeamCount = #2
\score {
\new Staff {
\relative c {
\clef "treble_8"
\time 4/4
\override TupletBracket.bracket-visibility = ##t
\times 2/3 {f'16([ b, \bcRone f' ~} \bcLone f16 b,] ~ b16[ \bcRone f' ~ \bcLone f32-- b,16.] f'32[ b, ~ b8 f'16] ~ \times 4/6 {f16 b, \bcRone f' ~ \bcLone f b, f'] ~} | \times 2/3 {f16[ b, \bcRone f' ~} \bcLone f32 b, f' b,] f'32[ b,32 ~ b8]) r16 fis'32([ b, ~ b8 fis'16] ~ \times 4/6 { fis16[ b, \bcRone fis' ~ \bcLone fis b, fis'])} |
}
}
}
Re: Separate a tuplet from the rest under a common beam
Thank you Michael and Mats!
I'll go with Mat's response!
Vlad
On Wed, Dec 14, 2022 at 5:35 PM Mats Bengtsson
wrote:
> Just copying and pasting from the example of subdividing beams at
> https://lilypond.org/doc/v2.23/Documentation/notation/beams, I tried the
> following, which seems to give the desired result.
>
> \version "2.23.81"
>
>
> \relative {
>\clef treble
>\key c \minor
>\time 2/4
>\set subdivideBeams = ##t
>\set baseMoment = #(ly:make-moment 1/8)
>\tuplet 3/2 { g'='16[( aes g) } fis g] a8 b |
> }
>
> /Mats
>
> On 2022-12-14 16:41, Volodymyr Prokopyuk wrote:
> > Hello,
> >
> > *Problem*
> >
> > How can I separate a \tuplet from two sixteenths using a common
> > eightingth beam?
> >
> > *Example code*
> >
> > \version "2.23.81"
> >
> > \relative {
> > \clef treble
> > \key c \minor
> > \time 2/4
> > \tuplet 3/2 { g'='16[( aes g) } fis g] a8 b |
> > }
> >
> > image.png
> >
> >
> > *Desired result*
> > image.png
> >
> > I've tried to adjust the baseMoment, beatStructure, subdivideBeats and
> > strictBeatBeaming but without success.
> >
> > Thank you very much,
> > Vlad
> >
>
Re: Separate a tuplet from the rest under a common beam
Most likely before your time at Lilypond. I used it a lot then. Paul On 12/14/22 10:04, David Kastrup wrote: Paul Scott writes: Good to know. Many many versions ago we could just nest square brackets. Not to my knowledge. We had some handwaving discussions at some point of time, but there were solid reasons against such an idea.
Re: Separate a tuplet from the rest under a common beam
Paul Scott writes: > Good to know. Many many versions ago we could just nest square > brackets. Not to my knowledge. We had some handwaving discussions at some point of time, but there were solid reasons against such an idea. -- David Kastrup
Re: Separate a tuplet from the rest under a common beam
Just copying and pasting from the example of subdividing beams at
https://lilypond.org/doc/v2.23/Documentation/notation/beams, I tried the
following, which seems to give the desired result.
\version "2.23.81"
\relative {
\clef treble
\key c \minor
\time 2/4
\set subdivideBeams = ##t
\set baseMoment = #(ly:make-moment 1/8)
\tuplet 3/2 { g'='16[( aes g) } fis g] a8 b |
}
/Mats
On 2022-12-14 16:41, Volodymyr Prokopyuk wrote:
Hello,
*Problem*
How can I separate a \tuplet from two sixteenths using a common
eightingth beam?
*Example code*
\version "2.23.81"
\relative {
\clef treble
\key c \minor
\time 2/4
\tuplet 3/2 { g'='16[( aes g) } fis g] a8 b |
}
image.png
*Desired result*
image.png
I've tried to adjust the baseMoment, beatStructure, subdivideBeats and
strictBeatBeaming but without success.
Thank you very much,
Vlad
Re: Separate a tuplet from the rest under a common beam
Good to know. Many many versions ago we could just nest square brackets.
Paul
On 12/14/22 09:24, Michael Werner wrote:
Resending to include the list ... oops.
Something like this, perhaps?
\version "2.23.82"
\relative {
\clef treble
\key c \minor
\time 2/4
\tuplet 3/2 { g'16[( aes \set stemRightBeamCount = #1 g) } \set
stemLeftBeamCount = #1 fis g] a8 b |
}
On Wed, Dec 14, 2022 at 10:42 AM Volodymyr Prokopyuk
wrote:
Hello,
*Problem*
How can I separate a \tuplet from two sixteenths using a common
eightingth beam?
*Example code*
\version "2.23.81"
\relative {
\clef treble
\key c \minor
\time 2/4
\tuplet 3/2 { g'='16[( aes g) } fis g] a8 b |
}
image.png
*Desired result*
image.png
I've tried to adjust the baseMoment, beatStructure, subdivideBeats
and strictBeatBeaming but without success.
Thank you very much,
Vlad
Re: Separate a tuplet from the rest under a common beam
Resending to include the list ... oops.
Something like this, perhaps?
\version "2.23.82"
\relative {
\clef treble
\key c \minor
\time 2/4
\tuplet 3/2 { g'16[( aes \set stemRightBeamCount = #1 g) } \set
stemLeftBeamCount = #1 fis g] a8 b |
}
On Wed, Dec 14, 2022 at 10:42 AM Volodymyr Prokopyuk <
volodymyrprokop...@gmail.com> wrote:
> Hello,
>
> *Problem*
>
> How can I separate a \tuplet from two sixteenths using a common
> eightingth beam?
>
> *Example code*
>
> \version "2.23.81"
>
> \relative {
> \clef treble
> \key c \minor
> \time 2/4
> \tuplet 3/2 { g'='16[( aes g) } fis g] a8 b |
> }
>
> [image: image.png]
>
>
> *Desired result*
> [image: image.png]
>
> I've tried to adjust the baseMoment, beatStructure, subdivideBeats and
> strictBeatBeaming but without success.
>
> Thank you very much,
> Vlad
>
>
Separate a tuplet from the rest under a common beam
Hello,
*Problem*
How can I separate a \tuplet from two sixteenths using a common eightingth
beam?
*Example code*
\version "2.23.81"
\relative {
\clef treble
\key c \minor
\time 2/4
\tuplet 3/2 { g'='16[( aes g) } fis g] a8 b |
}
[image: image.png]
*Desired result*
[image: image.png]
I've tried to adjust the baseMoment, beatStructure, subdivideBeats and
strictBeatBeaming but without success.
Thank you very much,
Vlad
