Re: Symmetrical ties in TieColumn
Karol, On Wed, Dec 4, 2013 at 6:14 PM, Karol Majewski karo...@wp.pl wrote: Hi, David Your function for offsetting control-points of a TieColumn is very useful to me. Now it would be great if someone could improve it to make it work with ties over the line break. I'm glad that you find some utility in that function. Unfortunately, I don't have the time to modify it as you ask. I think that the routine in the older thread cited in your first post and \alignTies could be combined by someone wanting to take this on. BTW, I don't recall seeing this notation--is it associated with anyone in particular? --David ___ lilypond-user mailing list lilypond-user@gnu.org https://lists.gnu.org/mailman/listinfo/lilypond-user
Re: Symmetrical ties in TieColumn
Hi, David Your function for offsetting control-points of a TieColumn is very useful to me. Now it would be great if someone could improve it to make it work with ties over the line break. Best Karol Dnia 20-10-2013 o godz. 0:39 David Nalesnik napisał(a): Hi Karol, On Sat, Oct 19, 2013 at 3:36 PM, Karol Majewski karo...@wp.pl wrote: Hi Currently I'm making some experiments with ties. What I need is a function that makes all ties in TieColumn have the same length (see attachment). I tried to achieve this by changing some values from Tie.details, but couldn't find the right configuration. Then I tried to modify shapeTieColumn.ly (http://lists.gnu.org/archive/html/lilypond-devel/2012-06/msg00285.html) but that's probably not the way it should be done. My question: how difficult would be to write such function? The problem here is that AFAIK you can't tell LilyPond: here are the attachment points I want for my ties; draw nice ones. . I've come up with a sketch which does something like what you want, but you have to play around with numbers to get a good result. Basically, it draws however many ties you need, but draws them with the same shape, lined up. You need to specify the shape of one of them by giving a list resembling control points. The y coordinates in this list are relative to 0. The x-coordinates represent the horizontal distance of the control points from the first NoteColumn associated with the TieColumn. I don't think that makes a lot of sense--and I'm a little too tired to do better--but I fiddling with the numbers should make it clear. Now the problems :) --Layout changes will mess up your hard work. --Won't work with broken ties as of yet. Anyway, it's something. --David ___ lilypond-user mailing list lilypond-user@gnu.org https://lists.gnu.org/mailman/listinfo/lilypond-user
Re: Symmetrical ties in TieColumn
Hmm... the code:
{
\override Tie.after-line-breaking =
#(lambda (grob)
(display (ly:grob-property grob 'control-points))
(newline))
c'1~ c'1
}
doesn't work for me. I see no control points (nor the numbers).
Meanwhile, I've found this:
===
#(define (make-cross-stencil coords) (ly:stencil-add (make-line-stencil 0.1 (- (car coords) 0.2 ) (- (cdr coords) 0.2) (+ (car coords) 0.2) (+ (cdr coords) 0.2)) (make-line-stencil 0.1 (- (car coords) 0.2) (+ (cdr coords) 0.2) (+ (car coords) 0.2) (- (cdr coords) 0.2#(define (display-control-points line) (lambda (grob) (let ((stencil (ly:tie::print grob)) (cps
(ly:grob-property grob 'control-points))) (ly:stencil-add stencil (ly:stencil-in-color (make-cross-stencil (second cps)) 1 0 0) (ly:stencil-in-color (make-cross-stencil (third cps)) 1 0 0) (if (eq? line #t) (make-line-stencil 0.05 (car (second cps)) (cdr (second cps)) (car (third cps)) (cdr (third cps))) empty-stencil)
{
\override Tie #'stencil = #(display-control-points #t)
}
===
... but it shows only the points, not the x,y_numbers.
Dnia 20-10-2013 o godz. 1:56 David Nalesnik napisał(a):
Karol,
On Sat, Oct 19, 2013 at 6:22 PM, Karol Majewski karo...@wp.pl wrote:
Thank you, David, it works indeed! I know that this is not exactly what I asked for but it is a good starting point.
Now the question: is it possible for LilyPond to show control_point_values of ties?Let's say I have something like:
=
\version "2.17.28"{c'1~ c'1}
=
and want LilyPond to show me all control points of that tie.
Is this viable?
Sure. You'll notice that the function I sent works with the control points of each tie in the column, Displaying them is straightforward:
{
\override Tie.after-line-breaking =
#(lambda (grob)
(display (ly:grob-property grob 'control-points))
(newline))
c'1~ c'1
}
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Re: Symmetrical ties in TieColumn
2013/10/20 Karol Majewski karo...@wp.pl:
Hmm... the code:
{
\override Tie.after-line-breaking =
#(lambda (grob)
(display (ly:grob-property grob 'control-points))
(newline))
c'1~ c'1
}
doesn't work for me. I see no control points (nor the numbers).
Well, it works for me.
Below I use David's code adding an approach via TieColumn.
\version 2.17.28
%% Nicer formatting with:
#(use-modules (ice-9 pretty-print))
displayTieCps =
\override Tie.after-line-breaking =
#(lambda (grob)
(display \nDisplay control-points using \\displayTieCps\n)
(pretty-print (ly:grob-property grob 'control-points))
;; or use
;(display (ly:grob-property grob 'control-points))
(newline))
displayTieColumnCps =
%\once
\override TieColumn #'after-line-breaking =
#(lambda (grob)
(let* ((ties (ly:grob-array-list (ly:grob-object grob 'ties)))
(c-ps
(map
(lambda (tie) (ly:grob-property tie 'control-points))
ties)))
(newline)
(display \nDisplay control-points using \\displayTieColumnCps\n)
(pretty-print c-ps)
;; or use
;(display c-ps)
))
{
\displayTieCps
\displayTieColumnCps
fis' cis'' a''2~
%% If you want to use \once \displayTieColumnCps it has to be inserted here.
%\displayTieColumnCps
fis' cis'' a''2
}
This returns:
Display control-points using \displayTieColumnCps
(((0.8949918 . -2.5)
(1.55561519677929 . -3.14431009035289)
(3.29240580235533 . -3.14431009035289)
(3.95302899913461 . -2.5))
((0.4650003 . 1.225)
(1.18506989232716 . 1.90581194400239)
(3.23295910680746 . 1.90581194400239)
(3.95302899913461 . 1.225))
((0.8949918 . 4.0)
(1.66581234547445 . 4.70907034772497)
(4.01220065366016 . 4.70907034772497)
(4.78302099913461 . 4.0)))
Display control-points using \displayTieCps
((0.8949918 . 4.0)
(1.66581234547445 . 4.70907034772497)
(4.01220065366016 . 4.70907034772497)
(4.78302099913461 . 4.0))
Display control-points using \displayTieCps
((0.4650003 . 1.225)
(1.18506989232716 . 1.90581194400239)
(3.23295910680746 . 1.90581194400239)
(3.95302899913461 . 1.225))
Display control-points using \displayTieCps
((0.8949918 . -2.5)
(1.55561519677929 . -3.14431009035289)
(3.29240580235533 . -3.14431009035289)
(3.95302899913461 . -2.5))
HTH,
Harm
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Re: Symmetrical ties in TieColumn
I must be doing something wrong. Where are the numbers? In PDF? In separate
file?
I use version 2.17.28 on Windows 7. Perhaps it is Windows issue?
Dnia 20-10-2013 o godz. 12:45 Thomas Morley napisał(a):
2013/10/20 Karol Majewski karo...@wp.pl:
Hmm... the code:
{
\override Tie.after-line-breaking =
#(lambda (grob)
(display (ly:grob-property grob 'control-points))
(newline))
c'1~ c'1
}
doesn't work for me. I see no control points (nor the numbers).
Well, it works for me.
Below I use David's code adding an approach via TieColumn.
\version 2.17.28
%% Nicer formatting with:
#(use-modules (ice-9 pretty-print))
displayTieCps =
\override Tie.after-line-breaking =
#(lambda (grob)
(display \nDisplay control-points using \\displayTieCps\n)
(pretty-print (ly:grob-property grob 'control-points))
;; or use
;(display (ly:grob-property grob 'control-points))
(newline))
displayTieColumnCps =
%\once
\override TieColumn #'after-line-breaking =
#(lambda (grob)
(let* ((ties (ly:grob-array-list (ly:grob-object grob 'ties)))
(c-ps
(map
(lambda (tie) (ly:grob-property tie 'control-points))
ties)))
(newline)
(display \nDisplay control-points using \\displayTieColumnCps\n)
(pretty-print c-ps)
;; or use
;(display c-ps)
))
{
\displayTieCps
\displayTieColumnCps
fis' cis'' a''2~
%% If you want to use \once \displayTieColumnCps it has to be inserted
here.
%\displayTieColumnCps
fis' cis'' a''2
}
This returns:
Display control-points using \displayTieColumnCps
(((0.8949918 . -2.5)
(1.55561519677929 . -3.14431009035289)
(3.29240580235533 . -3.14431009035289)
(3.95302899913461 . -2.5))
((0.4650003 . 1.225)
(1.18506989232716 . 1.90581194400239)
(3.23295910680746 . 1.90581194400239)
(3.95302899913461 . 1.225))
((0.8949918 . 4.0)
(1.66581234547445 . 4.70907034772497)
(4.01220065366016 . 4.70907034772497)
(4.78302099913461 . 4.0)))
Display control-points using \displayTieCps
((0.8949918 . 4.0)
(1.66581234547445 . 4.70907034772497)
(4.01220065366016 . 4.70907034772497)
(4.78302099913461 . 4.0))
Display control-points using \displayTieCps
((0.4650003 . 1.225)
(1.18506989232716 . 1.90581194400239)
(3.23295910680746 . 1.90581194400239)
(3.95302899913461 . 1.225))
Display control-points using \displayTieCps
((0.8949918 . -2.5)
(1.55561519677929 . -3.14431009035289)
(3.29240580235533 . -3.14431009035289)
(3.95302899913461 . -2.5))
HTH,
Harm
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Re: Symmetrical ties in TieColumn
On Sun, Oct 20, 2013 at 6:20 AM, Karol Majewski karo...@wp.pl wrote: I must be doing something wrong. Where are the numbers? In PDF? In separate file? I use version 2.17.28 on Windows 7. Perhaps it is Windows issue? The numbers are in the log. ___ lilypond-user mailing list lilypond-user@gnu.org https://lists.gnu.org/mailman/listinfo/lilypond-user
Re: Symmetrical ties in TieColumn
No numbers in log file.
After generating PDF from this code:
==
\version "2.17.28"{ \override Tie.after-line-breaking = #(lambda (grob) (display (ly:grob-property grob 'control-points)) (newline)) c'1~ c'1}
==
I get the following log:
==
# -*-compilation-*-Processing `C:/Users/Karol/Desktop/p.ly'Parsing...Interpreting music...Preprocessing graphical objects...Finding the ideal number of pages...Fitting music on 1 page...Drawing systems...Layout output to `/Users/Karol/Desktop/p.ps'...Converting to `/Users/Karol/Desktop/p.pdf'...Success: compilation successfully completed==
Can anyone reproduce this behavior on Windows?
Karol
Dnia 20-10-2013 o godz. 13:46 David Nalesnik napisał(a):
On Sun, Oct 20, 2013 at 6:20 AM, Karol Majewski karo...@wp.pl wrote:
I must be doing something wrong. Where are the numbers? In PDF? In separate file? I use version 2.17.28 on Windows 7. Perhaps it is Windows issue?
The numbers are in the log.
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Re: Symmetrical ties in TieColumn
Try running lilypond simply from the command line, with no options to create
the logfile (i.e. no redirection, no -dgui).
--
Phil Holmes
- Original Message -
From: Karol Majewski
To: David Nalesnik
Cc: Thomas Morley ; lilypond-user
Sent: Sunday, October 20, 2013 3:58 PM
Subject: Re: Symmetrical ties in TieColumn
No numbers in log file.
After generating PDF from this code:
==
\version 2.17.28
{
\override Tie.after-line-breaking =
#(lambda (grob)
(display (ly:grob-property grob 'control-points))
(newline))
c'1~ c'1
}
==
I get the following log:
==
# -*-compilation-*-
Processing `C:/Users/Karol/Desktop/p.ly'
Parsing...
Interpreting music...
Preprocessing graphical objects...
Finding the ideal number of pages...
Fitting music on 1 page...
Drawing systems...
Layout output to `/Users/Karol/Desktop/p.ps'...
Converting to `/Users/Karol/Desktop/p.pdf'...
Success: compilation successfully completed
==
Can anyone reproduce this behavior on Windows?
Karol
Dnia 20-10-2013 o godz. 13:46 David Nalesnik napisał(a):
On Sun, Oct 20, 2013 at 6:20 AM, Karol Majewski karo...@wp.pl wrote:
I must be doing something wrong. Where are the numbers? In PDF? In
separate file?
I use version 2.17.28 on Windows 7. Perhaps it is Windows issue?
The numbers are in the log.
--
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___
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Re: Symmetrical ties in TieColumn
Works now :) Thank you. Is there any way to have these numbers displayed in log file on Windows?
Dnia 20-10-2013 o godz. 18:06 Phil Holmes napisał(a):
Try running lilypond simply from the command line, with no options to create the logfile (i.e. no redirection, no -dgui).
--Phil Holmes
- Original Message -
From: Karol Majewski
To: David Nalesnik
Cc: Thomas Morley ; lilypond-user
Sent: Sunday, October 20, 2013 3:58 PM
Subject: Re: Symmetrical ties in TieColumn
No numbers in log file.
After generating PDF from this code:
==
\version "2.17.28"{ \override Tie.after-line-breaking = #(lambda (grob) (display (ly:grob-property grob 'control-points)) (newline)) c'1~ c'1}
==
I get the following log:
==
# -*-compilation-*-Processing `C:/Users/Karol/Desktop/p.ly'Parsing...Interpreting music...Preprocessing graphical objects...Finding the ideal number of pages...Fitting music on 1 page...Drawing systems...Layout output to `/Users/Karol/Desktop/p.ps'...Converting to `/Users/Karol/Desktop/p.pdf'...Success: compilation successfully completed==
Can anyone reproduce this behavior on Windows?
Karol
Dnia 20-10-2013 o godz. 13:46 David Nalesnik napisał(a):
On Sun, Oct 20, 2013 at 6:20 AM, Karol Majewski karo...@wp.pl wrote:
I must be doing something wrong. Where are the numbers? In PDF? In separate file?I use version 2.17.28 on Windows 7. Perhaps it is Windows issue?
The numbers are in the log.
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Re: Symmetrical ties in TieColumn
Hi Karol, On Sat, Oct 19, 2013 at 3:36 PM, Karol Majewski karo...@wp.pl wrote: Hi Currently I'm making some experiments with ties. What I need is a function that makes all ties in TieColumn have the same length (see attachment). I tried to achieve this by changing some values from Tie.details, but couldn't find the right configuration. Then I tried to modify shapeTieColumn.ly ( http://lists.gnu.org/archive/html/lilypond-devel/2012-06/msg00285.html) but that's probably not the way it should be done. My question: how difficult would be to write such function? The problem here is that AFAIK you can't tell LilyPond: here are the attachment points I want for my ties; draw nice ones. . I've come up with a sketch which does something like what you want, but you have to play around with numbers to get a good result. Basically, it draws however many ties you need, but draws them with the same shape, lined up. You need to specify the shape of one of them by giving a list resembling control points. The y coordinates in this list are relative to 0. The x-coordinates represent the horizontal distance of the control points from the first NoteColumn associated with the TieColumn. I don't think that makes a lot of sense--and I'm a little too tired to do better--but I fiddling with the numbers should make it clear. Now the problems :) --Layout changes will mess up your hard work. --Won't work with broken ties as of yet. Anyway, it's something. --David lined-up-ties.ly Description: Binary data attachment: lined-up-ties.png___ lilypond-user mailing list lilypond-user@gnu.org https://lists.gnu.org/mailman/listinfo/lilypond-user
Re: Symmetrical ties in TieColumn
Thank you, David, it works indeed! I know that this is not exactly what I asked for but it is a good starting point.
Now the question: is it possible for LilyPond to show control_point_values of ties?Let's say I have something like:
=
\version "2.17.28"{c'1~ c'1}
=
and want LilyPond to show me all control points of that tie.
Is this viable?
Dnia 20-10-2013 o godz. 0:39 David Nalesnik napisał(a):
Hi Karol,
On Sat, Oct 19, 2013 at 3:36 PM, Karol Majewski karo...@wp.pl wrote:
Hi Currently I'm making some experiments with ties. What I need is a function that makes all ties in TieColumn have the same length (see attachment). I tried to achieve this by changing some values from Tie.details, but couldn't find the right configuration. Then I tried to modify shapeTieColumn.ly (http://lists.gnu.org/archive/html/lilypond-devel/2012-06/msg00285.html) but that's probably not the way it should be done. My question: how difficult would be to write such function?
The problem here is that AFAIK you can't tell LilyPond: here are the attachment points I want for my ties; draw nice ones.
.
I've come up with a sketch which does something like what you want, but you have to play around with numbers to get a good result.
Basically, it draws however many ties you need, but draws them with the same shape, lined up.
You need to specify the shape of one of them by giving a list resembling control points.
The y coordinates in this list are relative to 0.
The x-coordinates represent the horizontal distance of the control points from the first NoteColumn associated with the TieColumn.
I don't think that makes a lot of sense--and I'm a little too tired to do better--but I fiddling with the numbers should make it clear.
Now the problems :)
--Layout changes will mess up your hard work.
--Won't work with broken ties as of yet.
Anyway, it's something.
--David
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Re: Symmetrical ties in TieColumn
Karol,
On Sat, Oct 19, 2013 at 6:22 PM, Karol Majewski karo...@wp.pl wrote:
Thank you, David, it works indeed! I know that this is not exactly what I
asked for but it is a good starting point.
Now the question: is it possible for LilyPond to show control_point_values
of ties?
Let's say I have something like:
=
\version 2.17.28
{
c'1~ c'1
}
=
and want LilyPond to show me all control points of that tie.
Is this viable?
Sure. You'll notice that the function I sent works with the control points
of each tie in the column, Displaying them is straightforward:
{
\override Tie.after-line-breaking =
#(lambda (grob)
(display (ly:grob-property grob 'control-points))
(newline))
c'1~ c'1
}
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