Hello,
I have a multi-device btrfs (with problems, more on that later). I looked into
btrfs-image and was surprised to find that "for i in 5 6 7 8 ; do sudo
btrfs-image -t2 /dev/sda$i - | md5sum;done" returns a different hash for sda7.
The other three hashes are the same, as I believe they all should be, or am I
mistaken?
$ for i in 5 6 7 8 ; do echo -n sda$i:" " ; sudo btrfs-image -t2 -c9 /dev/sda$i
- | tee /tmp/sda$i.img | md5sum;done
sda5: 047a1da23edeb9661e79d1006f17eab0 -
sda6: 047a1da23edeb9661e79d1006f17eab0 -
sda7: 9cc7afdc1476daa6f671db8d3c855164 -
sda8: 047a1da23edeb9661e79d1006f17eab0 -
$ sudo btrfs fi show
Label: 'SSD128' uuid: f110a925-6ad9-4b40-9207-6bf09ce0cb23
Total devices 4 FS bytes used 105.96GiB
devid 1 size 100.00GiB used 100.00GiB path /dev/sda5
devid 2 size 10.00GiB used 10.00GiB path /dev/sda6
devid 3 size 5.00GiB used 5.00GiB path /dev/sda7
devid 4 size 1.99GiB used 1.00GiB path /dev/sda8
The difference is somewhere very early on in the file:
$ wc -c /tmp/sda?.img
223763456 /tmp/sda5.img
223763456 /tmp/sda6.img
223763456 /tmp/sda7.img
223763456 /tmp/sda8.img
895053824 total
$ for file in /tmp/sda?.img;do echo -n $file: " "; tail -c 222950000 $file |
md5sum;done
/tmp/sda5.img: afe8010fa089415aaa55f2d549c3b5d4 -
/tmp/sda6.img: afe8010fa089415aaa55f2d549c3b5d4 -
/tmp/sda7.img: afe8010fa089415aaa55f2d549c3b5d4 -
/tmp/sda8.img: afe8010fa089415aaa55f2d549c3b5d4 -
$ for file in /tmp/sda?.img;do echo -n $file: " "; tail -c 222960000 $file |
md5sum;done
/tmp/sda5.img: 2bc5fe13e5f2dd8592a24eecb322482e -
/tmp/sda6.img: 2bc5fe13e5f2dd8592a24eecb322482e -
/tmp/sda7.img: ee26d34afa50ccb33e95e869b3e18af3 -
/tmp/sda8.img: 2bc5fe13e5f2dd8592a24eecb322482e -
How could this be?
Regards
Rolf
PS: While I will check back for replies in the archive, a courtesy cc will be
appreciated since I am not subscribed to the list.
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