Re: [PATCH 0/1] Forced-wakeup for stop lite states on Powernv
Hi Nicholas, On Thu, May 16, 2019 at 04:13:17PM +1000, Nicholas Piggin wrote: > > > The motivation behind this patch was a HPC customer issue where they > > were observing some CPUs in the core getting stuck at stop0_lite > > state, thereby lowering the performance on the other CPUs of the core > > which were running the application. > > > > Disabling stop0_lite via sysfs didn't help since we would fallback to > > snooze and it would make matters worse. > > snooze has the timeout though, so it should kick into stop0 properly > (and if it doesn't that's another issue that should be fixed in this > series). > > I'm not questioning the patch for stop0_lite, to be clear. I think > the logic is sound. I just raise one urelated issue that happens to > be for stop0_lite as well (should we even enable it on P9?), and one > peripheral issue (should we make a similar fix for deeper stop states?) > I think it makes sense to generalize this from the point of view of CPUs remaining in shallower idle states for long durations on tickless kernels. > > > >> > >> We should always have fewer states unless proven otherwise. > > > > I agree. > > > >> > >> That said, we enable it today so I don't want to argue this point > >> here, because it is a different issue from your patch. > >> > >> > When it is in stop0 or deeper, > >> > it free up both > >> > space and time slice of core. > >> > In stop0_lite, cpu doesn't free up the core resources and thus inhibits > >> > thread > >> > folding. When a cpu goes to stop0, it will free up the core resources > >> > thus increasing > >> > the single thread performance of other sibling thread. > >> > Hence, we do not want to get stuck in stop0_lite for long duration, and > >> > want to quickly > >> > move onto the next state. > >> > If we get stuck in any other state we would possibly be losing on to > >> > power saving, > >> > but will still be able to gain the performance benefits for other > >> > sibling threads. > >> > >> That's true, but stop0 -> deeper stop is also a benefit (for > >> performance if we have some power/thermal constraints, and/or for power > >> usage). > >> > >> Sure it may not be so noticable as the SMT switch, but I just wonder > >> if the infrastructure should be there for the same reason. > >> > >> I was testing interrupt frequency on some tickless workloads configs, > >> and without too much trouble you can get CPUs to sleep with no > >> interrupts for many minutes. Hours even. We wouldn't want the CPU to > >> stay in stop0 for that long. > > > > If it stays in stop0 or even stop2 for that long, we would want to > > "promote" it to a deeper state, such as say STOP5 which allows the > > other cores to run at higher frequencies. > > So we would want this same logic for all but the deepest runtime > stop state? Yes. We can, in steps, promote individual threads of the core to eventually request a deeper state such as stop4/5. On a completely idle tickless system, eventually we should see the core go to the deeper idle state. > > >> Just thinking about the patch itself, I wonder do you need a full > >> kernel timer, or could we just set the decrementer? Is there much > >> performance cost here? > >> > > > > Good point. A decrementer would do actually. > > That would be good if it does, might save a few cycles. > > Thanks, > Nick > -- Thanks and Regards gautham.
Re: [PATCH 0/1] Forced-wakeup for stop lite states on Powernv
Gautham R Shenoy's on May 16, 2019 3:36 pm: > Hello Nicholas, > > > On Thu, May 16, 2019 at 02:55:42PM +1000, Nicholas Piggin wrote: >> Abhishek's on May 13, 2019 7:49 pm: >> > On 05/08/2019 10:29 AM, Nicholas Piggin wrote: >> >> Abhishek Goel's on April 22, 2019 4:32 pm: >> >>> Currently, the cpuidle governors determine what idle state a idling CPU >> >>> should enter into based on heuristics that depend on the idle history on >> >>> that CPU. Given that no predictive heuristic is perfect, there are cases >> >>> where the governor predicts a shallow idle state, hoping that the CPU >> >>> will >> >>> be busy soon. However, if no new workload is scheduled on that CPU in the >> >>> near future, the CPU will end up in the shallow state. >> >>> >> >>> Motivation >> >>> -- >> >>> In case of POWER, this is problematic, when the predicted state in the >> >>> aforementioned scenario is a lite stop state, as such lite states will >> >>> inhibit SMT folding, thereby depriving the other threads in the core from >> >>> using the core resources. >> >>> >> >>> So we do not want to get stucked in such states for longer duration. To >> >>> address this, the cpuidle-core can queue timer to correspond with the >> >>> residency value of the next available state. This timer will forcefully >> >>> wakeup the cpu. Few such iterations will essentially train the governor >> >>> to >> >>> select a deeper state for that cpu, as the timer here corresponds to the >> >>> next available cpuidle state residency. Cpu will be kicked out of the >> >>> lite >> >>> state and end up in a non-lite state. >> >>> >> >>> Experiment >> >>> -- >> >>> I performed experiments for three scenarios to collect some data. >> >>> >> >>> case 1 : >> >>> Without this patch and without tick retained, i.e. in a upstream kernel, >> >>> It would spend more than even a second to get out of stop0_lite. >> >>> >> >>> case 2 : With tick retained in a upstream kernel - >> >>> >> >>> Generally, we have a sched tick at 4ms(CONF_HZ = 250). Ideally I expected >> >>> it to take 8 sched tick to get out of stop0_lite. Experimentally, >> >>> observation was >> >>> >> >>> = >> >>> sample minmax 99percentile >> >>> 20 4ms12ms 4ms >> >>> = >> >>> >> >>> It would take atleast one sched tick to get out of stop0_lite. >> >>> >> >>> case 2 : With this patch (not stopping tick, but explicitly queuing a >> >>>timer) >> >>> >> >>> >> >>> sample min max 99percentile >> >>> >> >>> 20 144us 192us 144us >> >>> >> >>> >> >>> In this patch, we queue a timer just before entering into a stop0_lite >> >>> state. The timer fires at (residency of next available state + exit >> >>> latency >> >>> of next available state * 2). Let's say if next state(stop0) is available >> >>> which has residency of 20us, it should get out in as low as (20+2*2)*8 >> >>> [Based on the forumla (residency + 2xlatency)*history length] >> >>> microseconds >> >>> = 192us. Ideally we would expect 8 iterations, it was observed to get out >> >>> in 6-7 iterations. Even if let's say stop2 is next available state(stop0 >> >>> and stop1 both are unavailable), it would take (100+2*10)*8 = 960us to >> >>> get >> >>> into stop2. >> >>> >> >>> So, We are able to get out of stop0_lite generally in 150us(with this >> >>> patch) as compared to 4ms(with tick retained). As stated earlier, we do >> >>> not >> >>> want to get stuck into stop0_lite as it inhibits SMT folding for other >> >>> sibling threads, depriving them of core resources. Current patch is using >> >>> forced-wakeup only for stop0_lite, as it gives performance >> >>> benefit(primary >> >>> reason) along with lowering down power consumption. We may extend this >> >>> model for other states in future. >> >> I still have to wonder, between our snooze loop and stop0, what does >> >> stop0_lite buy us. >> >> >> >> That said, the problem you're solving here is a generic one that all >> >> stop states have, I think. Doesn't the same thing apply going from >> >> stop0 to stop5? You might under estimate the sleep time and lose power >> >> savings and therefore performance there too. Shouldn't we make it >> >> generic for all stop states? >> >> >> >> Thanks, >> >> Nick >> >> >> >> >> > When a cpu is in snooze, it takes both space and time of core. When in >> > stop0_lite, >> > it free up time but it still takes space. >> >> True, but snooze should only be taking less than 1% of front end >> cycles. I appreciate there is some non-zero difference here, I just >> wonder in practice what exactly we gain by it. > > The idea
Re: [PATCH 0/1] Forced-wakeup for stop lite states on Powernv
Hello Nicholas, On Thu, May 16, 2019 at 02:55:42PM +1000, Nicholas Piggin wrote: > Abhishek's on May 13, 2019 7:49 pm: > > On 05/08/2019 10:29 AM, Nicholas Piggin wrote: > >> Abhishek Goel's on April 22, 2019 4:32 pm: > >>> Currently, the cpuidle governors determine what idle state a idling CPU > >>> should enter into based on heuristics that depend on the idle history on > >>> that CPU. Given that no predictive heuristic is perfect, there are cases > >>> where the governor predicts a shallow idle state, hoping that the CPU will > >>> be busy soon. However, if no new workload is scheduled on that CPU in the > >>> near future, the CPU will end up in the shallow state. > >>> > >>> Motivation > >>> -- > >>> In case of POWER, this is problematic, when the predicted state in the > >>> aforementioned scenario is a lite stop state, as such lite states will > >>> inhibit SMT folding, thereby depriving the other threads in the core from > >>> using the core resources. > >>> > >>> So we do not want to get stucked in such states for longer duration. To > >>> address this, the cpuidle-core can queue timer to correspond with the > >>> residency value of the next available state. This timer will forcefully > >>> wakeup the cpu. Few such iterations will essentially train the governor to > >>> select a deeper state for that cpu, as the timer here corresponds to the > >>> next available cpuidle state residency. Cpu will be kicked out of the lite > >>> state and end up in a non-lite state. > >>> > >>> Experiment > >>> -- > >>> I performed experiments for three scenarios to collect some data. > >>> > >>> case 1 : > >>> Without this patch and without tick retained, i.e. in a upstream kernel, > >>> It would spend more than even a second to get out of stop0_lite. > >>> > >>> case 2 : With tick retained in a upstream kernel - > >>> > >>> Generally, we have a sched tick at 4ms(CONF_HZ = 250). Ideally I expected > >>> it to take 8 sched tick to get out of stop0_lite. Experimentally, > >>> observation was > >>> > >>> = > >>> sample minmax 99percentile > >>> 20 4ms12ms 4ms > >>> = > >>> > >>> It would take atleast one sched tick to get out of stop0_lite. > >>> > >>> case 2 : With this patch (not stopping tick, but explicitly queuing a > >>>timer) > >>> > >>> > >>> sample min max 99percentile > >>> > >>> 20 144us 192us 144us > >>> > >>> > >>> In this patch, we queue a timer just before entering into a stop0_lite > >>> state. The timer fires at (residency of next available state + exit > >>> latency > >>> of next available state * 2). Let's say if next state(stop0) is available > >>> which has residency of 20us, it should get out in as low as (20+2*2)*8 > >>> [Based on the forumla (residency + 2xlatency)*history length] microseconds > >>> = 192us. Ideally we would expect 8 iterations, it was observed to get out > >>> in 6-7 iterations. Even if let's say stop2 is next available state(stop0 > >>> and stop1 both are unavailable), it would take (100+2*10)*8 = 960us to get > >>> into stop2. > >>> > >>> So, We are able to get out of stop0_lite generally in 150us(with this > >>> patch) as compared to 4ms(with tick retained). As stated earlier, we do > >>> not > >>> want to get stuck into stop0_lite as it inhibits SMT folding for other > >>> sibling threads, depriving them of core resources. Current patch is using > >>> forced-wakeup only for stop0_lite, as it gives performance benefit(primary > >>> reason) along with lowering down power consumption. We may extend this > >>> model for other states in future. > >> I still have to wonder, between our snooze loop and stop0, what does > >> stop0_lite buy us. > >> > >> That said, the problem you're solving here is a generic one that all > >> stop states have, I think. Doesn't the same thing apply going from > >> stop0 to stop5? You might under estimate the sleep time and lose power > >> savings and therefore performance there too. Shouldn't we make it > >> generic for all stop states? > >> > >> Thanks, > >> Nick > >> > >> > > When a cpu is in snooze, it takes both space and time of core. When in > > stop0_lite, > > it free up time but it still takes space. > > True, but snooze should only be taking less than 1% of front end > cycles. I appreciate there is some non-zero difference here, I just > wonder in practice what exactly we gain by it. The idea behind implementing a lite-state was that on the future platforms it can be made to wait on a flag and hence act as a replacement for snooze. On POWER9 we don't have this feature. The motivation be
Re: [PATCH 0/1] Forced-wakeup for stop lite states on Powernv
Abhishek's on May 13, 2019 7:49 pm: > On 05/08/2019 10:29 AM, Nicholas Piggin wrote: >> Abhishek Goel's on April 22, 2019 4:32 pm: >>> Currently, the cpuidle governors determine what idle state a idling CPU >>> should enter into based on heuristics that depend on the idle history on >>> that CPU. Given that no predictive heuristic is perfect, there are cases >>> where the governor predicts a shallow idle state, hoping that the CPU will >>> be busy soon. However, if no new workload is scheduled on that CPU in the >>> near future, the CPU will end up in the shallow state. >>> >>> Motivation >>> -- >>> In case of POWER, this is problematic, when the predicted state in the >>> aforementioned scenario is a lite stop state, as such lite states will >>> inhibit SMT folding, thereby depriving the other threads in the core from >>> using the core resources. >>> >>> So we do not want to get stucked in such states for longer duration. To >>> address this, the cpuidle-core can queue timer to correspond with the >>> residency value of the next available state. This timer will forcefully >>> wakeup the cpu. Few such iterations will essentially train the governor to >>> select a deeper state for that cpu, as the timer here corresponds to the >>> next available cpuidle state residency. Cpu will be kicked out of the lite >>> state and end up in a non-lite state. >>> >>> Experiment >>> -- >>> I performed experiments for three scenarios to collect some data. >>> >>> case 1 : >>> Without this patch and without tick retained, i.e. in a upstream kernel, >>> It would spend more than even a second to get out of stop0_lite. >>> >>> case 2 : With tick retained in a upstream kernel - >>> >>> Generally, we have a sched tick at 4ms(CONF_HZ = 250). Ideally I expected >>> it to take 8 sched tick to get out of stop0_lite. Experimentally, >>> observation was >>> >>> = >>> sample minmax 99percentile >>> 20 4ms12ms 4ms >>> = >>> >>> It would take atleast one sched tick to get out of stop0_lite. >>> >>> case 2 : With this patch (not stopping tick, but explicitly queuing a >>>timer) >>> >>> >>> sample min max 99percentile >>> >>> 20 144us 192us 144us >>> >>> >>> In this patch, we queue a timer just before entering into a stop0_lite >>> state. The timer fires at (residency of next available state + exit latency >>> of next available state * 2). Let's say if next state(stop0) is available >>> which has residency of 20us, it should get out in as low as (20+2*2)*8 >>> [Based on the forumla (residency + 2xlatency)*history length] microseconds >>> = 192us. Ideally we would expect 8 iterations, it was observed to get out >>> in 6-7 iterations. Even if let's say stop2 is next available state(stop0 >>> and stop1 both are unavailable), it would take (100+2*10)*8 = 960us to get >>> into stop2. >>> >>> So, We are able to get out of stop0_lite generally in 150us(with this >>> patch) as compared to 4ms(with tick retained). As stated earlier, we do not >>> want to get stuck into stop0_lite as it inhibits SMT folding for other >>> sibling threads, depriving them of core resources. Current patch is using >>> forced-wakeup only for stop0_lite, as it gives performance benefit(primary >>> reason) along with lowering down power consumption. We may extend this >>> model for other states in future. >> I still have to wonder, between our snooze loop and stop0, what does >> stop0_lite buy us. >> >> That said, the problem you're solving here is a generic one that all >> stop states have, I think. Doesn't the same thing apply going from >> stop0 to stop5? You might under estimate the sleep time and lose power >> savings and therefore performance there too. Shouldn't we make it >> generic for all stop states? >> >> Thanks, >> Nick >> >> > When a cpu is in snooze, it takes both space and time of core. When in > stop0_lite, > it free up time but it still takes space. True, but snooze should only be taking less than 1% of front end cycles. I appreciate there is some non-zero difference here, I just wonder in practice what exactly we gain by it. We should always have fewer states unless proven otherwise. That said, we enable it today so I don't want to argue this point here, because it is a different issue from your patch. > When it is in stop0 or deeper, > it free up both > space and time slice of core. > In stop0_lite, cpu doesn't free up the core resources and thus inhibits > thread > folding. When a cpu goes to stop0, it will free up the core resources > thus increasing > the single thread performance of other sibli
Re: [PATCH 0/1] Forced-wakeup for stop lite states on Powernv
On 05/08/2019 10:29 AM, Nicholas Piggin wrote: Abhishek Goel's on April 22, 2019 4:32 pm: Currently, the cpuidle governors determine what idle state a idling CPU should enter into based on heuristics that depend on the idle history on that CPU. Given that no predictive heuristic is perfect, there are cases where the governor predicts a shallow idle state, hoping that the CPU will be busy soon. However, if no new workload is scheduled on that CPU in the near future, the CPU will end up in the shallow state. Motivation -- In case of POWER, this is problematic, when the predicted state in the aforementioned scenario is a lite stop state, as such lite states will inhibit SMT folding, thereby depriving the other threads in the core from using the core resources. So we do not want to get stucked in such states for longer duration. To address this, the cpuidle-core can queue timer to correspond with the residency value of the next available state. This timer will forcefully wakeup the cpu. Few such iterations will essentially train the governor to select a deeper state for that cpu, as the timer here corresponds to the next available cpuidle state residency. Cpu will be kicked out of the lite state and end up in a non-lite state. Experiment -- I performed experiments for three scenarios to collect some data. case 1 : Without this patch and without tick retained, i.e. in a upstream kernel, It would spend more than even a second to get out of stop0_lite. case 2 : With tick retained in a upstream kernel - Generally, we have a sched tick at 4ms(CONF_HZ = 250). Ideally I expected it to take 8 sched tick to get out of stop0_lite. Experimentally, observation was = sample minmax 99percentile 20 4ms12ms 4ms = It would take atleast one sched tick to get out of stop0_lite. case 2 : With this patch (not stopping tick, but explicitly queuing a timer) sample min max 99percentile 20 144us 192us 144us In this patch, we queue a timer just before entering into a stop0_lite state. The timer fires at (residency of next available state + exit latency of next available state * 2). Let's say if next state(stop0) is available which has residency of 20us, it should get out in as low as (20+2*2)*8 [Based on the forumla (residency + 2xlatency)*history length] microseconds = 192us. Ideally we would expect 8 iterations, it was observed to get out in 6-7 iterations. Even if let's say stop2 is next available state(stop0 and stop1 both are unavailable), it would take (100+2*10)*8 = 960us to get into stop2. So, We are able to get out of stop0_lite generally in 150us(with this patch) as compared to 4ms(with tick retained). As stated earlier, we do not want to get stuck into stop0_lite as it inhibits SMT folding for other sibling threads, depriving them of core resources. Current patch is using forced-wakeup only for stop0_lite, as it gives performance benefit(primary reason) along with lowering down power consumption. We may extend this model for other states in future. I still have to wonder, between our snooze loop and stop0, what does stop0_lite buy us. That said, the problem you're solving here is a generic one that all stop states have, I think. Doesn't the same thing apply going from stop0 to stop5? You might under estimate the sleep time and lose power savings and therefore performance there too. Shouldn't we make it generic for all stop states? Thanks, Nick When a cpu is in snooze, it takes both space and time of core. When in stop0_lite, it free up time but it still takes space. When it is in stop0 or deeper, it free up both space and time slice of core. In stop0_lite, cpu doesn't free up the core resources and thus inhibits thread folding. When a cpu goes to stop0, it will free up the core resources thus increasing the single thread performance of other sibling thread. Hence, we do not want to get stuck in stop0_lite for long duration, and want to quickly move onto the next state. If we get stuck in any other state we would possibly be losing on to power saving, but will still be able to gain the performance benefits for other sibling threads. Thanks, Abhishek
[PATCH 0/1] Forced-wakeup for stop lite states on Powernv
Currently, the cpuidle governors determine what idle state a idling CPU should enter into based on heuristics that depend on the idle history on that CPU. Given that no predictive heuristic is perfect, there are cases where the governor predicts a shallow idle state, hoping that the CPU will be busy soon. However, if no new workload is scheduled on that CPU in the near future, the CPU will end up in the shallow state. Motivation -- In case of POWER, this is problematic, when the predicted state in the aforementioned scenario is a lite stop state, as such lite states will inhibit SMT folding, thereby depriving the other threads in the core from using the core resources. So we do not want to get stucked in such states for longer duration. To address this, the cpuidle-core can queue timer to correspond with the residency value of the next available state. This timer will forcefully wakeup the cpu. Few such iterations will essentially train the governor to select a deeper state for that cpu, as the timer here corresponds to the next available cpuidle state residency. Cpu will be kicked out of the lite state and end up in a non-lite state. Experiment -- I performed experiments for three scenarios to collect some data. case 1 : Without this patch and without tick retained, i.e. in a upstream kernel, It would spend more than even a second to get out of stop0_lite. case 2 : With tick retained in a upstream kernel - Generally, we have a sched tick at 4ms(CONF_HZ = 250). Ideally I expected it to take 8 sched tick to get out of stop0_lite. Experimentally, observation was = sample minmax 99percentile 20 4ms12ms 4ms = It would take atleast one sched tick to get out of stop0_lite. case 2 : With this patch (not stopping tick, but explicitly queuing a timer) sample min max 99percentile 20 144us 192us 144us In this patch, we queue a timer just before entering into a stop0_lite state. The timer fires at (residency of next available state + exit latency of next available state * 2). Let's say if next state(stop0) is available which has residency of 20us, it should get out in as low as (20+2*2)*8 [Based on the forumla (residency + 2xlatency)*history length] microseconds = 192us. Ideally we would expect 8 iterations, it was observed to get out in 6-7 iterations. Even if let's say stop2 is next available state(stop0 and stop1 both are unavailable), it would take (100+2*10)*8 = 960us to get into stop2. So, We are able to get out of stop0_lite generally in 150us(with this patch) as compared to 4ms(with tick retained). As stated earlier, we do not want to get stuck into stop0_lite as it inhibits SMT folding for other sibling threads, depriving them of core resources. Current patch is using forced-wakeup only for stop0_lite, as it gives performance benefit(primary reason) along with lowering down power consumption. We may extend this model for other states in future. Abhishek Goel (1): cpuidle-powernv : forced wakeup for stop lite states arch/powerpc/include/asm/opal-api.h | 1 + drivers/cpuidle/cpuidle-powernv.c | 71 - 2 files changed, 71 insertions(+), 1 deletion(-) -- 2.17.1
