One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:

struct foo {
    int stuff;
    void *entry[];
};

instance = kmalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL);

Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:

instance = kmalloc(struct_size(instance, entry, count), GFP_KERNEL);

This code was detected with the help of Coccinelle.

Signed-off-by: Gustavo A. R. Silva <gust...@embeddedor.com>
---
 arch/powerpc/platforms/cell/spufs/file.c | 5 ++---
 1 file changed, 2 insertions(+), 3 deletions(-)

diff --git a/arch/powerpc/platforms/cell/spufs/file.c 
b/arch/powerpc/platforms/cell/spufs/file.c
index ae8123edddc6..48c2477e7e2a 100644
--- a/arch/powerpc/platforms/cell/spufs/file.c
+++ b/arch/powerpc/platforms/cell/spufs/file.c
@@ -2338,9 +2338,8 @@ static int spufs_switch_log_open(struct inode *inode, 
struct file *file)
                goto out;
        }
 
-       ctx->switch_log = kmalloc(sizeof(struct switch_log) +
-               SWITCH_LOG_BUFSIZE * sizeof(struct switch_log_entry),
-               GFP_KERNEL);
+       ctx->switch_log = kmalloc(struct_size(ctx->switch_log, log,
+                                 SWITCH_LOG_BUFSIZE), GFP_KERNEL);
 
        if (!ctx->switch_log) {
                rc = -ENOMEM;
-- 
2.20.1

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