Re: [Matplotlib-users] contour plot in semi-circle domain

2010-10-22 Thread Jae-Joon Lee
Kenshi,

I'm sorry that I completely forgot about this issue.

I just took a look and it seems to be due to a bug in clabel routine.
The fix is easy and I'll commit it soon. Meanwhile, here is a work
around. Basically, you need to draw a contour in ax3, not in
aux_ax3.

First of all, you can populate Z without for loops (note that I
changed X, Y to Theta, R).

Theta, R = meshgrid(theta, r)

Z = (Theta/90.)**2 + (R-2)**2


Now, instead of aux_ax3.contour, use

CS = aux_contour(aux_ax3, Theta, R, Z,levels,colors='k')

where aux_contour is defined as

def aux_contour(aux_ax, aux_X, aux_Y, Z, *kl, **kwargs):
ax = aux_ax._parent_axes
shape_orig = Theta.shape
TR = np.array([aux_X, aux_Y]).reshape((2, -1)).transpose() #
coordinates in aux_ax
XY = aux_ax.transAux.transform(TR) # coordinates in ax
X, Y = XY.transpose().reshape((2, shape_orig[0], shape_orig[1]))

CS = ax.contour(X, Y, Z, *kl, **kwargs)

return CS

And do clabel with the original axes (ax3). use_clabeltext will help
the labels aligned with contour lines.

ax3.clabel(CS,fontsize=10, use_clabeltext=True)

A complete example is attached.

Regards,

-JJ




On Fri, Sep 17, 2010 at 7:34 PM, Kenshi hibino
hib...@kugi.kyoto-u.ac.jp wrote:


 Jae-Joon Lee wrote:


 Another option is to use mpl_toolkits.axisartist (distributed with mpl
 1.0). However, learning curve of the axisartist is also steep. You may
 play around with the last figure in the example below.

 http://matplotlib.sourceforge.net/examples/axes_grid/demo_floating_axes.html



 Jae-Joon,
 Thanks for the quick reply and good advice.

 Second option you recommended is seemed to work well.
 My code modified from example is attached.

 But, in semi-circle domain I can't write contour label using clabel().
 Do you know the reason why? http://old.nabble.com/file/p29737063/test2.py
 test2.py

 For reference my system is python(x,y) on Windows and mpl version is 1.0

 Thanks again.

 Kenshi
 --
 View this message in context: 
 http://old.nabble.com/contour-plot-in-semi-circle-domain-tp29699332p29737063.html
 Sent from the matplotlib - users mailing list archive at Nabble.com.


 --
 Start uncovering the many advantages of virtual appliances
 and start using them to simplify application deployment and
 accelerate your shift to cloud computing.
 http://p.sf.net/sfu/novell-sfdev2dev
 ___
 Matplotlib-users mailing list
 Matplotlib-users@lists.sourceforge.net
 https://lists.sourceforge.net/lists/listinfo/matplotlib-users



tererer.py
Description: Binary data
--
Nokia and ATT present the 2010 Calling All Innovators-North America contest
Create new apps  games for the Nokia N8 for consumers in  U.S. and Canada
$10 million total in prizes - $4M cash, 500 devices, nearly $6M in marketing
Develop with Nokia Qt SDK, Web Runtime, or Java and Publish to Ovi Store 
http://p.sf.net/sfu/nokia-dev2dev___
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users


Re: [Matplotlib-users] contour plot in semi-circle domain

2010-09-17 Thread Kenshi hibino


Jae-Joon Lee wrote:
 
 
 Another option is to use mpl_toolkits.axisartist (distributed with mpl
 1.0). However, learning curve of the axisartist is also steep. You may
 play around with the last figure in the example below.
 
 http://matplotlib.sourceforge.net/examples/axes_grid/demo_floating_axes.html
 
 

Jae-Joon,
Thanks for the quick reply and good advice.

Second option you recommended is seemed to work well.
My code modified from example is attached.

But, in semi-circle domain I can't write contour label using clabel(). 
Do you know the reason why? http://old.nabble.com/file/p29737063/test2.py
test2.py 

For reference my system is python(x,y) on Windows and mpl version is 1.0

Thanks again.

Kenshi
-- 
View this message in context: 
http://old.nabble.com/contour-plot-in-semi-circle-domain-tp29699332p29737063.html
Sent from the matplotlib - users mailing list archive at Nabble.com.


--
Start uncovering the many advantages of virtual appliances
and start using them to simplify application deployment and
accelerate your shift to cloud computing.
http://p.sf.net/sfu/novell-sfdev2dev
___
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users


[Matplotlib-users] contour plot in semi-circle domain

2010-09-13 Thread Kenshi hibino

Hi!

I want to use polar plot and write contour in semi-circle domain.But I can't
do so.

Here is a part of my code. 

-
from pylab import *
from scipy import *

fig=figure(figsize=(10,10))
ax=fig.add_axes([0.1,0.1,0.8,0.8],polar=True)

axis([0, pi, 0, 1])

show()


I thought that axis([0,pi,0,1]) make the writing domain semi-circle,
but complete circle was written as domain.

Does anyone know how I should write?

Many thanks, 

Kenshi
-- 
View this message in context: 
http://old.nabble.com/contour-plot-in-semi-circle-domain-tp29699332p29699332.html
Sent from the matplotlib - users mailing list archive at Nabble.com.


--
Start uncovering the many advantages of virtual appliances
and start using them to simplify application deployment and
accelerate your shift to cloud computing
http://p.sf.net/sfu/novell-sfdev2dev
___
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users


Re: [Matplotlib-users] contour plot in semi-circle domain

2010-09-13 Thread Jae-Joon Lee
On Tue, Sep 14, 2010 at 12:09 AM, Kenshi hibino
hib...@kugi.kyoto-u.ac.jp wrote:
 I thought that axis([0,pi,0,1]) make the writing domain semi-circle,
 but complete circle was written as domain.

 Does anyone know how I should write?


With polar projection, it is not possible to make semi-circle domain.
You need to make a custom projection
(http://matplotlib.sourceforge.net/devel/add_new_projection.html). But
it would not be easy for a normal user.

Another option is to use mpl_toolkits.axisartist (distributed with mpl
1.0). However, learning curve of the axisartist is also steep. You may
play around with the last figure in the example below.

http://matplotlib.sourceforge.net/examples/axes_grid/demo_floating_axes.html

Regards,

-JJ

--
Start uncovering the many advantages of virtual appliances
and start using them to simplify application deployment and
accelerate your shift to cloud computing.
http://p.sf.net/sfu/novell-sfdev2dev
___
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users